Bragg's Equation For X-Ray Diffraction In Chemistry - Practice Problems
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- čas přidán 7. 09. 2024
- This chemistry video tutorial provides a basic introduction into the use of bragg's equation for X-ray diffraction. It explains how to use the equation to calculate the interplanar spacing between atoms in a crystal given the wavelength of the x-ray. This video explains the derivation of bragg's equation / formula and provides examples and practice problems showing you how to use it.
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Hybridization of Atomic Orbitals:
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Molecular Orbital Theory:
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Hydrogen Bonding:
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London Dispersion Forces:
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Ion Dipole Forces:
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Bragg's Equation For X-Ray Diffraction:
• Bragg's Equation For X...
Molecular & Network Covalent Solids:
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Metallic Bonding:
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You should be proud of your teaching ability, you're very good.
My professor should watch this video before he starts teaching his class! Thank you!
Exctly mine should immidiately start taking lessons from him too.
Same
Facts😭
It ain't easy out here😭
😂😂😂😂 many professor needs classes 😂😂😂 from this guy
I love how college courses don't teach you anything, they just expect you to already know how to utilize Bragg's formula. This video makes it clear and easy. You're the best!
This video should have so many more views and likes, the explanation of the Braggs derivation was a million times better than my lecturers explain it!
Professor Organic Chemistry Tutor, thank you for an awesome Introduction and Derivation into the use of Bragg's Equation For X-Ray Diffraction in AP/General Chemistry. The four example problems show how to apply/use Bragg's classic Equation for X-Ray Diffraction in Modern Chemistry. This is an error free video/lecture on CZcams TV with the Organic Chemistry Tutor.
This is a lifesaver! Thank you for explaining this in clear and simple English! Please keep it up.
Your voice is music to my ears.
You managed to get me through Calculus for tec II. I will forever be grateful dude. Your an amazing teacher and should teach other teachers how to teach.
your teaching ability is off the charts.....like i'd prefer you over my own lecturer back at my university
I'm Japanese, but I couldn't find anyone who explained about θ in Japanese. It was very helpful. Thank you!💕
Thank you so much. I am not even taking chemistry right now, I am watching this for fun!
thank you for the boost of confidence i got after solving the problems on my own!
Very well explained.
Thank you! why can't chem professors be more clear, mine professors combine like 4 equations into one big and I'm like BRAH
Well explained... I found this video really helpful !!!
Much better than our chemistry teacher
hahahaha lol
Crystal clear sir! Thank you!
I was searching for that which you described at 2:10
😍
OMG you saved me!!!!!!!!! I was having so much trouble with this and you made it so simple! You're the best :)
Thank You. Thank you very much. Clear English, clear explanation.
Thank you so much, I was stuck before watching this video
I am wondering how easily you explained it I can't enough Thank you
he taught so well all my doubts are crystal clear, i dont need any external resource
"crystal" clear lol
you are a life saver
I have been in college since '14. I took a cumulative 2 year break, but I started from the beginning of undergrad with nothing. No credits, no classes I could skip, I started with College algebra, worked through that, trig, Calculus 1 through 4, intro to physics, Physics 1, 2 and Chemistry 1 and 2, signals and systems, Analog Electronics and now I am in Modern Physics, and I find myself, yet again learning from you. All of the thanks in the world to you; you are a gift from God. Mad respect for the array of studies that you cover and how well you illustrate various topics. Three semesters left and I imagine I will be seeing more of your content!
Absolutely wonderful explanation!!
Lifesaver!
Hi maybe you could add videos on how to determine interplanar spacing when the crystal system in simple cubic but with different miller indices
Thank u so so much.. Finally i m able to understand. I m a bio student
i cant wrap around my head the fact that i could not understand all this when written in my native language but understood it when someone explained to me in english
same here dude
You quite literally activate a bit of new brain matter when you start using a different language. It forces you to think differently from a possibly different perspective.
@solconcordia4315 not really bruh
If this guy had teached me in my native language and i didnt even have to focus since it would much more easier to understand
But do study from a book is definitely the hardest thing even with their native language.
Very good explanation.
the numericals r very helpful
So why is it that the extra distance the bottom wave travels is equal to n*lambda? Where does that come from? The rest all makes perfect sense, good video!
Was also looking for an answer to this. Did you ever find out?
@@kevinburke59 Indeed. Since the waves only constructively interferes when they are in phase, the 2 small extra distances the bottom wave travels must keep them in phase. Thus any multiple of a wavelength will do - n*lambda.
THANKS Sir 😊😊
You have a really soothing and attractive voice :)
excellent explanation
Thank you so much
Can you please make more videos on more advanced unit cell problems?
You are an amazing teacher
great explanation
Thanks!
You are a God among mortals
Great explanation. Thanks Lot
incredible, amazing thanks
You're awesome!!keep doing this blessed work!
Awesome Man...
Thank you so muchh
Very helpful, I ❤ it
You are justtttt awesome!!
Your perfect sir 👍🏻
Very nice
great explanation. really help me . thanks a lot!
Nice video. Thanks!
8:19 How do you type this in on a calculator?
thanks
Excellent made doubt clear.
I'm I the only one who gets different answers after such amazing explanation?
Yes. I get different answers when my University teachers teach me. In fact I don't even get answers. I am just stuck.
u are incredible !!!!
you are the best thanx
The vidio is helping
Id like to know how this is used in difraction xray machines to distinguis between materials or components
Why is that section highlighted in red the difference in distance the wave travels between the two points?
Thank you!
good explanation
great video mate !
thank you
loved it!!
I have a question. at position y why the wave reflected with 180 degree?
PERFECTION !!!
Thank youu 💕💕✨✨
U r awesome!!!!!!!! ❤💙💚💜💛
I'm a little confused on the steps you did to get your answers, do I multiply 2sin first ? or could you show each step please
thank you :D
Thanx.
Great!!
informative
Why the wave on the bottom travel with greater distance than the wave on the top?
how constructive interference can happen if the beams are parallel ?
lol that's what I just asked
@@MrYahya0101 If the beams meet they can't be parallel. The approximation we use is that the path difference is equal to the distance between two successive layers. Check also Huygens principle where we do something similar.
@@adosar7261 So you're saying according to Huygens principle, each point on the waves will emit spherical waves, and those spherical waves will interfere with each other, eventhough the beams don't physically meet?
During exams of I am asked to do these then I can complete the whole but will not be able to find the sin values of these peculiar angles.
Thanks for GOD to create human beings like you who help people, and your reward will be great with God ❤
How do you find the sine of 17.4 using pen and paper.
1:45 I didn't get why the lower path is longer. Where are you measuring the length of each path from?
He is measuring from the *corresponding* places on the two beams of X-rays hitting the two *parallel* layers of atoms.
The corresponding places on the X-rays are places with the shortest distance between them. Put the sharp tip of a leg of a compass at *any* place on one X-ray beam. Start pulling apart the other leg to make it approach the other X-ray beam. When the tip of the leg being moved touches the other beam, that's the corresponding place on the X-ray beam.
Huygens' Principle says that every point on a wave sends out spherical wavelets expanding like ripples on the surface of a pond with the point being where a tiny pebble drops and touches the surface of the pond creating the ripples.
Hi i have a question for you why i go this way and i enter the calculator according to this command give another number and it differs from the answer to the book or yours
So n is basically the amount of wavelengths that are within the distance XY or YZ?
"n" IS THE order of diffraction
How can we do this if we have a tilted xy plane?
th=ff xD, but well done and thank you, very helpful :)
But if the waves are parallel then how will they interfere?
how he pronounces "Perfec" and "wavelemff" got me dead
my professor used cos instead of sin? do you know why that could be?
One thing i dont understand is why the xy or yz is equal to wavelength
What a goat !
Why am I getting -62.96? because 17.4 was being interpreted as radians, just in case anybody else got that answer.
Me tooo
You need to convert the angle to its radian form. So 17.4 times pi and divide it to 180.
4:40 hahahaha great video
l get confused but understand last
goat
👏🏼👏🏼👏🏼👏🏼
It is not “another” x-ray!
Thank You bro
how he pronounces "Perfec" and "wavelemff" got me dead
and "stheta" also..