HWN - Want to interview for NXP Semi? Study this!
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- čas přidán 10. 09. 2024
- Hi fellow (and future) engineers!
This week we tackle a real interview question using the foundations we learned on one of our first videos. We're so thankful for our community members that constantly send us feedback and ideas for questions. We couldn't make this happen without you!
Check this video before answering the question: • HWN - Hardware Intervi...
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I got to the same answer just by charge conservation, which is more intuitive for me. I just wrote:
Q1_p1 = Q1_p2 + Q2_p2
C1*V1 = C1*(Vout - V2) + C2*Vout
then it is the same equation as you wrote.
Hi Greg,
Thank you so much for stopping by and contributing to the discussion! You're absolutely right, charge conservation is another great way to think about the problem. However, we opted to go with the approach of the initial condition since it builds on the topic of our very first video! :)
I get the same answer applying the superposition principle.
is this correct? Intuitively, C1 is flying capacitor, assuming phi1 and phi2 are complementary clocks, when phi1=1, c1 is charged to V1, when phi2=1, C1 should fly to V2 + V1, your Vout should be V1+V2. since no R is mentioned Tau is zero, implies cap charges instantaneously regardless of Capacitance value. your final equation Vout= C1V1 + C1V2/(C1+C2) doesnt seem right if C1=C2, Vout = (V1+V2)/2 ? There is a problem with notation, delta V1 must be delta Vc1 and Delta Vc2 must be = delta Vc1 + V2
the delta V2 and V2 is a bit confusing. Maybe use Va as V1 and Vb as V2
very nice question! in the second transient event i solve the problem using superposition and got the same answer.
How did u plot Vout out of the equation without explaining
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