Statics: Lesson 60 - Shear Moment Diagram Problem with Moments
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"That's perfectly straight" LOL. Jeff has such a relaxed, fun way to teach. Puts a smile on your face while you learn.
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You're the only reason I'm passing Statics. Definitely using your videos for Solids next semester!!!! you're truly a lifesaver.
Jeff, you are the freaking man!!!!! I love how simply you taught this. I really appreciate how you mentioned calculating the area from the shear diagram, it helps tremendously in calculating the Max Bending Moment!
man i am learning more in a 15-min video than in hours of lectures in my uni. thank you so much
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DR. Hanson, thank for another classic and awesome lecture of Shear Moment Diagram Problem with Moments. These lectures are very helpful to many students all across the world.
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I assumed downward force as negative. but I started the shear force diagram from the free end, and my graph falls below the X-AXIS. Is this right or would I be marked down? the shape and values are exactly the same as Jeffs'
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Your explanation of the parabolic curve using the trick of slow to fast contradicts each other. can you check this please and correct the anomaly? I am bit confused!
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6:56 is the most relatable moment in the history of engineering online lecture videos
But in lecture 59 Shear diagram was slow to fast and you put the moment diagram the same as this ! Why?
Can't thank you enough
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How did you get 12x6 for the triangle area? Wouldn't it have been 14 x 6 since it was 30 kips high and we subtract the 16 for the rectangle below? I appreciate any clarity
nope. rectangular shear width should be 18 brotha...
What happened to lesson 59 in the statics playlist ?
I got a trick for the fast and slow type of curve part sir. Just draw a circle, divide it into 4 regions, and then put "PD" on the upper left hand side (Positive area, Decreasing slope) and then "NI" on the upper right (Negative, Increasing), "ND" on the lower left, "PI" on lower right.
so taking that example at 12:49
since the area of the shear is Positive and then the slope is decreasing, then it would be "PD" and since PD is at upper left region of the circle the curve would steep then slow 😊😊
Thank you omg !!! I was having issues with visualization!!
if only I can send a picture 🤦
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is "Please Dont Neglect Infants
Neglect Dumb People Instead"
PD NI
ND PI
@@tutingrubena1584 I think this doesn't work when the distributed load is a triangle or does it?
Thanks tog
Great Stuff! prefer metric - it seems easier....
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shouldn't be the Moment at A already be in terms of kips only? The ft. unit is cancelled by multiplying the load by 6ft
Thank you so much for these. I'd rather pay you than my university cause I learn nothing from them
Please where how did you get the 30 for the AY at the fixed place
0=Ay-12-10-8 then rearrange
the moments on the smile don't follow the right hand rule though. i don't understand why the moment is positive when doing the equilibrium equations but negative when doing bending moments.
So the sign convention for moments is the opposite of what it has been all along? That's not confusing or anything... :)
The sign convention for bending moments is different than the sign convention for moments in general. Jeff talks about the sign convention for bending moments in lesson 57.
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