His teaching of the technical elements is amazing...period! but we can't discount how his humour and relaxed personality keeps us engaged so we allow ourselves to learn. I've never met any teacher, instructor or prof like Dr. Hanson. This guy is beyond the real deal.
I've said it many times, but this man is a king. His videos are literally saving my grade and my sanity. I wish all instructors were as great as Dr. Hanson.
I've got the worst lecturer of all time.. and everytime i search for a topic to see Dr. Hanson pop up, I'm beyond excited. You really are incredible Doc, thanks alot.
I'm studying through UNISA, which is a self study from home with no tutor.. Making sense of this without a tutor is a nightmare but you sir are a proper legend!!! Other videos I've come across skip so many steps and I end up more confused.. I saw this 1 hour long video and almost shat myself.. I just need to tell you that this was probably the most valuable hour I have ever spent!! Thank you for the wonderful tutorial and amazing breakdown explaining absolutely every step along the way. You get people that are paid to teach and people that CAN teach and this is your calling!
Dr. Hanson, you've helped me in so many classes. I thought I was doomed because I passed solids and Statics and you didn't have any videos past those subjects. Until I got to analysis of structures and we had to do beam deflection again. 1 hour of you explaining the process and im like a pro again. Thank you for helping me become an engineer.
I don't know why our professors don't teaches like this ..if all professors wear like you .we would have a lot of good students . you are so good at teaching ..thank you for your contribution in my educational life sir..
I Just watched your old video about this lesson to solve my assignment. Thank you Jeff Hanson. I hope you can include superposition method and moment area of theorem too
Hey Doc Hanson, Did you do any videos on the Moment Area method? We are covering that and I am way lost. I am trying to stay ahead of the game and pick up this method asap.
Mann thank god for you and going this grinder with us, Prof! 😵💫🤓I spent a solid t hrs on one of these with a partial distributed load (same supports) in my last HW today….. I feel way better watching this- except now I know I need to triple check my math/reductions along the way. And shoot maybe I’ll plug it into the smaller v equation and see if that gets me the answer in the back…. I’m confused though, after finding the equation from A to B (across the beam) we were asked to solve for the deflection at A,B and the midway (C). Why wouldn’t the deflection at A and B be zero though? Isn’t that what our boundary conditions State for these pins and rollers??🤔
just by using first 2 boundary conditions we can solve it right ? in that case c2 and c4=0 in fact your c4 is almost zero c4=(11/128 pl^3)=almost (1pl^3/12) do we need to use 4 boundary conditions?
My school follows beer and johnston book for strength of materials does it goes with your videos ??? You really helped me through statics so i really want to get your help in strength of materials too
For the second M(x) equation, could you have set the right side of the beam as the origin and derived an equation that way? Or is it necessary to have the same origin for both equations?
I’m pretty sure that it is necessary because our “x” variable must represent a distance from the same point. If you did set the right side of the beam as the origin, then your value of x would represent the distance from point “B”. X in both equations of M(x) needs to represent distance from point “A”.
Jeff kind of messed up at about 17.30 minutes of the video. It'd be better to write the equation for a slope at a point like dy/dx = 1/EI * integral(M(x), dx) for easier understanding...
Greetings from Poland Mr. Hanson. We have a little bit different signs, for example your V it is our R (reaction), but methode is the same. I wish I want to have teachers like you in my University. P.S. In my University I didn't pass exam, because in task like that, my constanses of integration were written in the end of eqation, not in 1 interwal. In profesor's opinion it wasn't agree with ,,art of counting in Clebsh methode"
I agree that the slope absolute value would be about the same on either side of c, but wouldn't the values of the actual slope be equal and opposite on each side? Ex.) One will be concave up and one will be concave down ?
No they would be equal but not opposite signs because his coordinates for both his cuts are all in the positive x axis. So the slopes will be both equal and positive.
I don’t understand in 15:09 when writing the boundary counditions, in left side it is fixed right? And in the right side it is pin. But why isn’t the left sides slope is not 0 ? I mean it’s fixed and the slope in fixed conditions are zero. But you side slope is not zero in point A PLEASE I HAVE A FINAL IN FEW HOURS HELPPPP
@@bhbvh4904 I think it is because 'x' is just a variable used so that you can plug in any length into it; meaning you can find the moment at any length.
how come he used x for lenght of both cut. shouldnt be the lengh of first cut(x) smaller then lenght of second cut(x). why he used same variable for different dimentions.
I don't get how we gave x lenght two different values. In the first section we say that it's lenght x and after in the second longer section we say it's x again how come this?
i dont know how terrible my student life would be without your tutorial videos. Thank you so much sir!
The 15 dislikes in the previous video are 15 professors who lost their job due to Prof. Hanson teaching better than them.
😂😂😂
2023 and only 15 haters, 0 dislike in 2 years he doing aight
His teaching of the technical elements is amazing...period! but we can't discount how his humour and relaxed personality keeps us engaged so we allow ourselves to learn. I've never met any teacher, instructor or prof like Dr. Hanson. This guy is beyond the real deal.
I've said it many times, but this man is a king. His videos are literally saving my grade and my sanity. I wish all instructors were as great as Dr. Hanson.
I've got the worst lecturer of all time.. and everytime i search for a topic to see Dr. Hanson pop up, I'm beyond excited. You really are incredible Doc, thanks alot.
I'm studying through UNISA, which is a self study from home with no tutor.. Making sense of this without a tutor is a nightmare but you sir are a proper legend!!! Other videos I've come across skip so many steps and I end up more confused.. I saw this 1 hour long video and almost shat myself.. I just need to tell you that this was probably the most valuable hour I have ever spent!! Thank you for the wonderful tutorial and amazing breakdown explaining absolutely every step along the way. You get people that are paid to teach and people that CAN teach and this is your calling!
Thanks for the great comment. Glad it helped❤
Dr. Hanson, you've helped me in so many classes. I thought I was doomed because I passed solids and Statics and you didn't have any videos past those subjects. Until I got to analysis of structures and we had to do beam deflection again. 1 hour of you explaining the process and im like a pro again. Thank you for helping me become an engineer.
37:31 "Holy banana batman", LOL
Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))
What a wonderful lesson. Thankyou Dr. Hanson for your statics and solid mechanics explanation. It helping me so much
I don't know why our professors don't teaches like this ..if all professors wear like you .we would have a lot of good students .
you are so good at teaching ..thank you for your contribution in my educational life sir..
Just in time, thank you professor Hanson!
Thank you for making this simple and clear.
Thanks for the steps !
Just in time! Thank you
Thanks professor. You do a great job explaining this stuff.
You are just great. I would have aced this course if I had you as a prof.
I Just watched your old video about this lesson to solve my assignment. Thank you Jeff Hanson. I hope you can include superposition method and moment area of theorem too
lun p char
Dr Hanson, a true teacher
18:33 "that dude right there is the devil" lmao
Hey Doc Hanson, Did you do any videos on the Moment Area method? We are covering that and I am way lost. I am trying to stay ahead of the game and pick up this method asap.
Thank you so much!!!!!
So glad I don't have CZcams premium, those advert breaks were lifesavers - especially that 18minute long one
He is one of the best professors for Mechanics of Materials. Does he teach Advanced Mechanics of Materials?
Amazing !!
You are the best!
If I have a beam with loads in the middle and free ends. Do I have to make cuts at the free ends?
Mann thank god for you and going this grinder with us, Prof! 😵💫🤓I spent a solid t hrs on one of these with a partial distributed load (same supports) in my last HW today….. I feel way better watching this- except now I know I need to triple check my math/reductions along the way. And shoot maybe I’ll plug it into the smaller v equation and see if that gets me the answer in the back….
I’m confused though, after finding the equation from A to B (across the beam) we were asked to solve for the deflection at A,B and the midway (C). Why wouldn’t the deflection at A and B be zero though? Isn’t that what our boundary conditions State for these pins and rollers??🤔
You're the man Jeff 💂
You make it fun. LOL , he said get some popcorn we will be here for a while lollll
u are the best!
Structural Theory on your next videos
Dr. Hanson please
just by using first 2 boundary conditions we can solve it right ? in that case c2 and c4=0 in fact your c4 is almost zero c4=(11/128 pl^3)=almost (1pl^3/12)
do we need to use 4 boundary conditions?
You did it very similar to castiglianos theorem. Only youre solving for Bending Moment.
Masterpiece
My school follows beer and johnston book for strength of materials does it goes with your videos ??? You really helped me through statics so i really want to get your help in strength of materials too
For the second M(x) equation, could you have set the right side of the beam as the origin and derived an equation that way? Or is it necessary to have the same origin for both equations?
I’m pretty sure that it is necessary because our “x” variable must represent a distance from the same point. If you did set the right side of the beam as the origin, then your value of x would represent the distance from point “B”. X in both equations of M(x) needs to represent distance from point “A”.
i have found another legendary teacher
Jeff kind of messed up at about 17.30 minutes of the video. It'd be better to write the equation for a slope at a point like dy/dx = 1/EI * integral(M(x), dx) for easier understanding...
Where can I get that eraser! It works better than any I've ever seen!
Why the deflection at C does not equal the integral of the slope at c?
Greetings from Poland Mr. Hanson. We have a little bit different signs, for example your V it is our R (reaction), but methode is the same. I wish I want to have teachers like you in my University.
P.S.
In my University I didn't pass exam, because in task like that, my constanses of integration were written in the end of eqation, not in 1 interwal. In profesor's opinion it wasn't agree with ,,art of counting in Clebsh methode"
yes you did it!!!!!
Is it just me or did Mr. Hanson make a mistake at theta1 og y1.
He mixed up the equation when putting C1 into Theta1 and y1.
Correct me if im wrong?
hi. isn't it easier to use mccouly's brackets?
I agree that the slope absolute value would be about the same on either side of c, but wouldn't the values of the actual slope be equal and opposite on each side? Ex.) One will be concave up and one will be concave down ?
just look at it, they are concave in the same direction
No they would be equal but not opposite signs because his coordinates for both his cuts are all in the positive x axis. So the slopes will be both equal and positive.
YASSSS JEFF KEEP IT UP!!
thanks sir
For theta(c), why did you get rid of (1/EI) . It happened around time: 50:30
When you set the two equations equal to each other EI cancels each other. For example (1/EI)b = (1/EI)c . Find c?
He corrects it @52:30
@@abu-bakr9604since we weren’t given values for elasticity and I …we can still easily cancel out 1/EI ALSO
You are legend
You saved me fr
@31:38 LOL! Algebra! Don't mess me up algebra!
... I always say
professor Hanson, it should be 1/128 PL^2 + C1; (3/8)*(1/16) = 1/128. Thank you
I don’t understand in 15:09 when writing the boundary counditions, in left side it is fixed right? And in the right side it is pin. But why isn’t the left sides slope is not 0 ? I mean it’s fixed and the slope in fixed conditions are zero. But you side slope is not zero in point A PLEASE I HAVE A FINAL IN FEW HOURS HELPPPP
yes masta
Shouldn't the deflection at the roller be unknown? if it were a pin it would be secured but it's not...
Why is the X in the second moment equation the same as the first? Arent they different lengths?
You dont happen to know why now do you?
@@bhbvh4904 I think it is because 'x' is just a variable used so that you can plug in any length into it; meaning you can find the moment at any length.
@@dan9512 exactly, its arbitrary
Can you teach mechanics of materials at my school, please!!
how come he used x for lenght of both cut. shouldnt be the lengh of first cut(x) smaller then lenght of second cut(x). why he used same variable for different dimentions.
7:00 Intimidating ! Lol hhhhhhhhhh
I got an hour and 15 min till my exam…. Hope this allows me to do these
i failed(barely) 🤣 second chance tommorow, hopefully it goes better
dexterity test
Holy dooley, please tell me there's an easier way to calculate slope and deflection.
I hope he finds out that he made a mistake with C4
There will be my final exam tomorrow and I knew nothing before I listened these lessons;however, still I can't predict how the exam will be tomorrow.
how did it go
@@willgggg900 I passed with DC or DD I don't remember actually what the grade is.
Please Sir, kindly Share with me CONJUGATE METHOD.
Thank you
Thank you❤ jeff_Hanson_PhD🙏🏻
That's alot of algebra😂
determine the slope and deflection at point c on the beam below (figure 2). 5 kn 4m 4m a c b figure 2
Ay bro this is not chegg. no one is going to help u
bruh
I don't get how we gave x lenght two different values. In the first section we say that it's lenght x and after in the second longer section we say it's x again how come this?