2160 Minimum Sum of Four Digit Number After Splitting Digits || LeetCode 2160|| Biweekly LeetCode 71

Here in this video we have discussed the approach to solve
2160 Minimum Sum of Four Digit Number After Splitting Digits of Biweekly Contest 71 .
Question Link :- leetcode.com/contest/biweekly...
Code Link :-
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Biweekly70 #2129 #solution #answer #Fastest_answer
2160 Minimum Sum of Four Digit Number After Splitting Digits || LeetCode 2160|| Biweekly LeetCode 71
2160 Minimum Sum of Four Digit Number After Splitting Digits || LeetCode 2160|| Biweekly LeetCode 71
2160 Minimum Sum of Four Digit Number After Splitting Digits || LeetCode 2160|| Biweekly LeetCode 71
2160 Minimum Sum of Four Digit Number After Splitting Digits || LeetCode 2160|| Biweekly LeetCode 71
2160 Minimum Sum of Four Digit Number After Splitting Digits || LeetCode 2160|| Biweekly LeetCode 71

[@AbhishekSingh-ub2ls]

nice logic. I was stuck from two days.

[@rickwarty]

thanks

[@pawankanttiwari8173]

Well explained.
Thanks bhaiya.

[@BroCoders]

Thanks bhai!!!

[@arjunyadav-kt5jr]

i am so glad, maine bas approach suni aur code karne chala gaya, mai samajh raha tha apka code few liner hoga, and i was continuously thinking to optimize it, but then what i coded was so close to what you showed... take a look❣
_____________________________________________________________________________
class Solution {
public:
int minimumSum(int num) {
int arr[4], rem, temp;
for(int i=0; i

[@BroCoders]

Yeah!!
It's very good that you are grinding over a question this much!!

[@Rizwankhan-ts3gk]

good explanation brother, thanks

[@JeetAcharya-ev4rc]

What for n numbers instead of using 4 digit no. What if I use long integer? What will be the code for that

[@BroCoders]

It is not very tough to think!!
Try out yourself!!

[@purnimahianl5678]

What is string(1, s[0]) mean? What is 1 inside it?

[@whitedracarys7613]

bro O(1) nhi sujta contest ke waqt
my approach : saari permutation nikali array me
aur hr ka 2 2 pair bnna ke minSum calculate krlia

[@BroCoders]

Sahi baat!!

[@sahityaratan]

what if 3,1 ka pair bnte? was this approach working ?

[@BroCoders]

@@sahityaratan Please elaborate on your doubt a bit Sahitya!!

[@thegreekgoat98]

WHY THIS IS NOT WORKING?
vectorv(4);
while(num!=0)
{
int rem=num%10;
v.push_back(rem);
num=num/10;
}
sort(v.begin(),v.end());
int sum1=v[0]*10+v[2];
int sum2=v[1]*10+v[3];
return sum1+sum2;

[@BroCoders]

here, actually you have initialized the size of v which is 4 and then you are pushing back in the while loop so that goes in the 5 th ps and ........ . Therefore the 1st 4 pos contains garbage.
I hope you understood.

[@thegreekgoat98]

@@BroCoders thanks bro understood

[@thegreekgoat98]

Btw... Is this approach good?

[@BroCoders]

Awesome

[@thegreekgoat98]

@@BroCoders thanks

[@ayushrautela8567]

the link to the sheet is not opening !!!!! HELP SIR.

[@BroCoders]

onedrive.live.com/view.aspx?resid=633D0AA17B58E355!3089&ithint=file%2cdocx&authkey=!APXxsLmWQinD6kE

[@swarupsarangi734]

nice approach

[@BroCoders]

Thanks bhai :))

[@Reenasharma-be3ys]

bahut sare edge cases the

[@BroCoders]

Yes!!