Moment of Inertia of an Iron Beam's Cross Section
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- čas přidán 8. 04. 2018
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In this video, we will determine the #momentofinertia of an Iron Beam's Cross Section.
Watch the video, right till the end to have firm grasp on the concept.
#engineeringmechanics
#appliedmechanics
#fundamentalsofmechanicalengineering
#whatiscentroid
#whatiscenterofgravity
#whatiscentreofgravity
#centroid
#momentofinertiaofcompositeplane - Věda a technologie
Small correction guys:
At timeline 05:10, I should have written Pi.r^2/2....
But the answer works out as 39.27 cm^2...
Rest is fine...Not to worry...
What would be the changes will happen if we considering another reference axes rather than given reference axes/?
i was just getting mad how come that the value is 39.27.
A2=A3 = (pi * 25 )/2 = 39.2699
x3 = 12-x2=12-2.12=9.88
lmao i questioned my whole life existence for a moment there
thanks G O A T
Super super easy explenation, thank u so much sir. 👏
the way u teach sir,awesome and very easy to learn, thank you i got passed in mos because of ur videos
Thank you so much Manas Patnaik!
Great job Sir...
keep uploading 😊😊
Great explanation video👍👍😊
Amazing video :D
Thank you, u r a genius
Nice explanation thank you very much sir
Thanks sir its helps a lot
sir,how to find out centroid of semicircle with axis tilted
Is there any formula like finding out moment of inertia of semicircle..
Excellent explanation. Just missed to write (2) while showing formula for area's of semicircle divided by 2. Also checked answer is matching. Thanks
Good concept
Thank you so much you have added alot to my knowledge of mechanics
Thank u ......Keep learning and do share it with your friends.........aLL the best
Sir i, ve heard from my teacher dt if a body is symmetric about x_axis it's y bar is zero... How ❓❓ i, m getting confused... Wt is the right answer?
Thanks sir today was my paper and I read complete mechanics before from your videos itself and this was the last question which I saw before entering exam hall .
Thanks a ton ❤️
I am sure you will do well in exams. Good luck
@@ManasPatnaikofficial Yes sir sure.... thanks once again ❤️
Thank you very 😇 much.
Can we apply direct method of finding centroid to I,Z,C section of rectangle??
THANK YOUUU!!!!!!!!
Wonderful sir
Tq u so much sir
just a doubt that is the formula (y-Ybar)square is applicable for all composite section in case of centroidal axis.
Thank your for your explanation, what about Ixy ? Is it Will always be 0?
THANK YOU SO MUCH...........
why don't you consider symmetric about x. axis or y. axis??? Sir. .
Sir... Upload some more problems on moment of inertia
sir does removing semicircles dont change the position of centroid?
Thank you
Very nice sir 👌👌👍
Thank you sir
two semicircle same distance from centroidal y axis
Please, where can I find this question in the source?
Sir Thank you. Pass karwa diye.
Thanq sir
how to calculate the moment of area for the singly reinforced beam?
MOI OF semicircle ?? Is there any video ??plz reply
need help....!! where did you get the 0.11 and 0.393 on the semicircle..? I only saw these number in your video... thank you
Thats a formula
I like the way he speaks...
Sir what is the moment of inertia of semi circle along y-axis
Kindly help us to find the polar moment of inertia and the radius of gyrations
y the two semicircles are subtracted sir?
I'm getting problem with M.O.I. OF SEMI CIRCLE ABOUT x-x & y-y axis
Plse reply with clear concept hearty request 🙏🙏🙏
Pls tell about MoI of L section
sir can u pls explain moment of inertia of inverted T section
Sir area of semicircle is wrong it is pi r^2/2 kk thank you sir
Sir area pi r square by 2 hoga na
0.11 formula If we do not know how can we solve with 0.393
Sorry I think that when you are calculating the area of semi-circle you made some eror that is πr square divided by 2 becouse it is semi-circle
nice
Hello.at 7:48 you explain iparallel=0.11r² and iperpendicular=0.393r²,I am confused because many textbooks say ix =iy for semicircle is 0.393r².they do not mention 0.11r².please explain why.thank you.
Even this lecturer says ix=iy in this link czcams.com/video/idKWlkgKXzM/video.html please skip 5:17.thank you.sorry to bother you
Aman....
Come on FB messenger, lets have a quick chat......
Hi.i messaged you now.thank you again
I have same Question.......plz clear my doubt too
@@faisalnazir9067 in this video Mr.Manas takes MOI from center of semi-circle while many text books give you MOI from edge of semi-circle...BOTH ARE CORRECT, just check if you are at CENTER or EDGE
In text book taking x1=-6 why
Sir please upload a video on derovation of Moment of inertia of shapes like semicircle, quarter circle, triangle etc. Please sir
Even i was thinking about that...
till then u can watch stuff from these playlists.
Topic-wise Playlist of Engineering Drawing / Engineering Graphics in English
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Sir small doubt ,can moment of inertia can be negative value ?
No it will never be because area and distance will both always be positive themselves more or less on a plane it wont be negative. I think correct me if i am wrong
Sir area of semi circle is pi r^2/2
Yes u r right....I should have written Pi.r^2/2....
But the answer works out as 39.27 cm^2
Manas Patnaik yes sir
1:39 X does not match 6 after verification
area of x2 and x3 is wrong and iyy3 is also wrong becoz of x3 has been changed
sir rolling ka video chahiye pls
I yy2 and I yy3 values will not be same
Area of semi circle =pi r*2/2
12:32 to 12:40
09:40
sir pls upload derivation for moment of inertia for rectangle,semi circle,triangle,etc.,
09:40 to 10:00
First like
Area of semicircular is wrong
Problems on product of inertia
Yrr
a little bit mistake of figure 2
Wasted my 3 hrs as u was not getting right answer because you had written Area of semi circle wrong..., rest is good..
Faltu
All things are correct but addition is wrong.
I think he subtracted the value of the rectangle from the values of two semicircles (since it's a hollow in the rect)
Sir, can you explain how to get 0,11r⁴ for the Inertia of si circle?