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At last week's math department meeting (I teach Spec Ed at a ~600 student high school) I mentioned this fun new channel I discovered called Andy Math. This video is going in an email to the department. Thanks, these are a lot a fun.
I JUST REALIZED, I GOT THIS EXACT PROBLEM ON MY MATH TEST! I’m so gonna watch all your videos looking for more problems they put on my tests, sneaky teachers…
Fun, I took a different approach. Since all of the 3 small RTs are similar, they're all 30-60-90. So I made my own not-to-scale version, and I strategically but arbitrarily assigned my square's side a length of sqrt(3). Then I found the left portion of my hypotenuse to be 1 and the right one to be 3. So I know my hypotenuse measures 4 + sqrt(3), and my side divided by my hypotenuse works out to be (4sqrt(3) - 3)/13. Since I know the given hypotenuse is 13, the given square side must be 4sqrt(3) - 3. Then I squared it.
Pretty sure I’ve looked at Brilliant. I will definitely look again. Anything that demonstrates the deep beauty of mathematics is truly exciting to me. Thanks.
I have this math challenge I’ve tried for a while but still can’t get it. Is there a way you can try it? Also how would I be able to give the challenge? Edit: I don’t know if it’s possible.
I am a designer so sometimes I use 3d model to solve these questions. But I also do this with my own. And usually the number is without any decimals so I solve it 2 times reaching same answer 15.430 and then give up to look for your explanation and get the same answer (never doubting me again)
I did it using trigonometry. Let: x be the length of the lower side of the right. y be the length of the side of the square. z be de length of the lower side of the left. Using tan(), we can get this: x = y÷tan(60°) z = y÷tan(30°) Then, we can solve for y: x + y + z = 13 cm (y÷tan(60°)) + (y÷tan(30°)) + y = 13 cm y(1÷tan(60) + 1÷tan(30°) + 1) = 13 cm y = 13 cm÷(1÷tan(60°) + 1÷tan(30°) + 1) I plugged it into my calculator and gave me y = 4√3 - 3. y² = 57 - 24√3.
Because that is just a decimal approximation of the area. You should always try to arrive at an exact form of the solution first, rather than approximating as you go. 3.93² actually gives you 15.44 (rounded down), not the correct rounded down approximation of 15.43
Let's gooo he got sponsored again
How exciting
My favorite math dude getting his bag. How exiting.
Yippe
How exciting
Brilliant. I guess that means no more videos where 69 and 420 are the solutions. 🤣
More sponsorships to come!!
A tiny bit bummed this one didn't use pi, but still a fun watch! lol!
Happy Pi Day!
At last week's math department meeting (I teach Spec Ed at a ~600 student high school) I mentioned this fun new channel I discovered called Andy Math. This video is going in an email to the department. Thanks, these are a lot a fun.
HOW EXCITING CHAIN 👇
How exciting
How Exciting
How exciting.
How exciting
How exciting
Asker: "How do you know how to answer all these problems."
Andy: "I paid attention in high school."
I JUST REALIZED, I GOT THIS EXACT PROBLEM ON MY MATH TEST!
I’m so gonna watch all your videos looking for more problems they put on my tests, sneaky teachers…
Finally same answear as Andy!
Do I know everything you cover? Yes.
Do I still watch all your videos, regardless? Also yes.
You have a Brilliant Sponsor. How exciting.
Fun, I took a different approach. Since all of the 3 small RTs are similar, they're all 30-60-90. So I made my own not-to-scale version, and I strategically but arbitrarily assigned my square's side a length of sqrt(3). Then I found the left portion of my hypotenuse to be 1 and the right one to be 3. So I know my hypotenuse measures 4 + sqrt(3), and my side divided by my hypotenuse works out to be (4sqrt(3) - 3)/13. Since I know the given hypotenuse is 13, the given square side must be 4sqrt(3) - 3. Then I squared it.
How eclectic!
How on Earth is this eclectic?
How. Brilliant.
Absolutely adore this channel, and send it to my kids all the time
I started to get scared until I was assured at the end that it was indeed exciting.
Always watch your interesting problems. Thankful to your videos.
2:15 You could have used the property of a²-b²=(a+b)*(a-b)
It would have made things easy
Hey, this was the question I sent
How exciting!
cool
Wow great
Pretty sure I’ve looked at Brilliant. I will definitely look again. Anything that demonstrates the deep beauty of mathematics is truly exciting to me. Thanks.
How exciting
So happy for you that you got sponsored!
Get your bag brother
You make me feel so dumb. Thank you for humbling me.
I have this math challenge I’ve tried for a while but still can’t get it. Is there a way you can try it? Also how would I be able to give the challenge?
Edit: I don’t know if it’s possible.
Andy stays winning
They dont cancel, they reduce to 1!
OK tough guy, what would the area of the maximum size origami sculpture that could fit through all those doors behind you?
Tops❤!
hey, how you that motions step by step? It would help me in my online classes
I am a designer so sometimes I use 3d model to solve these questions.
But I also do this with my own.
And usually the number is without any decimals so I solve it 2 times reaching same answer 15.430 and then give up to look for your explanation and get the same answer (never doubting me again)
I got this question on my math exam!
We cry over math not boys 🙂
You're good
You sponsored your own video?
At one stage root 3 x root 3 becomes root 9 (then, later, 3) at another stage root 3 x root 3 immediately becomes 3. How. Odd.
I have the same question! The first one at 2:13 confuses me. Why is it so?
I am having to find 3d prism’s surface area in school, but I am very bad at it. Do you know the formula?
andymath.com/surface-area-rectangular-prisms/
thank you i forgot you did a video on it :)@@AndyMath
Are you also doing triangular prisms? andymath.com/triangular-prisms-surface-area/@@skidmark696
@@AndyMath yeah, this is perfect thanks for the help.
Yo this one could be solved in hundreds of ways 😂 I solved it then I watched you do it absolutely different ways same results
could be easier if using Law of Sines
I got the Area as 169/(4+2*sqrt*(3)). Not sure where I went wrng
How easy
I tried solving this myself and ended up with sqrt(3)•x=sqrt(3)•x and that is correct I will accept no other answers
I did it using trigonometry.
Let:
x be the length of the lower side of the right.
y be the length of the side of the square.
z be de length of the lower side of the left.
Using tan(), we can get this:
x = y÷tan(60°)
z = y÷tan(30°)
Then, we can solve for y:
x + y + z = 13 cm
(y÷tan(60°)) + (y÷tan(30°)) + y = 13 cm
y(1÷tan(60) + 1÷tan(30°) + 1) = 13 cm
y = 13 cm÷(1÷tan(60°) + 1÷tan(30°) + 1)
I plugged it into my calculator and gave me y = 4√3 - 3. y² = 57 - 24√3.
Or sum to ZERO!
thanks doctor math
hOw ExCiTiNg
Too heavy. Plus the camera wasn't invented yet.
If you knew x=3.93, why didn't you just square 3.93 to get 15.43. THAT would have been Brilliant!
Because that is just a decimal approximation of the area.
You should always try to arrive at an exact form of the solution first, rather than approximating as you go.
3.93² actually gives you 15.44 (rounded down), not the correct rounded down approximation of 15.43
🎊 promo sm
You look AI generated
💀
bro 😭
i think andy is real but cool guy could be ai generated