Last question ans is 4hrs sir...... 1st step:- they meet at 60kms, for A it took 1.5hrs 2nd step:- interchanging speeds A with 60kmph reaches it's point 60kms in 1hr. 3rd step:- with same interchanged speed A with 60kmph meets 60km in 1hr So the total time taken upto 2nd meeting be 1.5+1+1=3.5hrs In case in 3rd with initial speeds it takes 1.5hrs to meet so 2nd meeting will be Total 4hrs
Please sir am Telugu medium students So Naku Answer artham avuthundi kani questions m artham avthaledu sir please Telugu lo chepandi dayacheshi🙏🙏🙏nen maths students ne sir...
pls check @44:31 if train 1st travel 2 hrs alone then also train 2nd will 1.5 hrs alone because train 1st stop at 11:30 AM , why didn't you consider that
here we have to consider that the both trains start at same time so if train 1 after 2hrs of time will be 9:30 and so the train 2 starts at 9:30 by default.
Doesn't matter where they stops bro Becoz they meet each before they stops at their respective stations Obviously question is asked where meet each other
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Tq Sir. You are the great in competitive exam coaching
I'm blessed to watch your videos sir. What a time saving video while preparing for examinations.
It saved my time while preparing for the concept.
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Thank u sir for tricks.. I am from kerala.could u plz add more classes in English..
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U r explanation amazing sir.. 🙏 do prblms on arithmetic more and more different concepts
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Sir upload vedio on trains and platforms.
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Excellent way of teaching ...thku sir
Last question is simply superb 😊
I’m confused when do i use standard D=S x T or like question at 55:00 using proportional method?
Distance constant so S and T are inversely proportional
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Very good lecture. Thanks
sir ssc cgl kosam marathon session cheyandi sir
Sir please explain this class in telugu 🙏🙏🙏
Very great explanation and content, Thank-you. Special thanks for making videos in English 😅😊
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Thanks a lot sir
Last question ans is 4hrs sir......
1st step:- they meet at 60kms, for A it took 1.5hrs
2nd step:- interchanging speeds A with 60kmph reaches it's point 60kms in 1hr.
3rd step:- with same interchanged speed A with 60kmph meets 60km in 1hr
So the total time taken upto 2nd meeting be 1.5+1+1=3.5hrs
In case in 3rd with initial speeds it takes 1.5hrs to meet so 2nd meeting will be Total 4hrs
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Tq sir ❤
Thank you sir Iam nikhil from telangana
Sir plz share videos on trigonometry in English.
sir upload the video to the trains
Sir please teach in English if possible in every topic...i really appreciate your method of calculation and tricks....
Group d kuda cheyyandi sir
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Please sir am Telugu medium students
So
Naku Answer artham avuthundi kani questions m artham avthaledu sir please Telugu lo chepandi dayacheshi🙏🙏🙏nen maths students ne sir...
Sir LCM of 4+7/2 is 15/2 how it will become 28 sir anybody pls explain in train from pune to Bombay problem
He is taking only lcm of numerators
U r adding but the sir is taking lcm means which least number divided by both 4 and 7that is 28
Thanks
Lcm of numerator 28and hcf of denominator 1
Hence 28/1=28
LCM 4*7=28 7*4=28* 2*14=28
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Telugu mediam class Lu separate cheppandi sir🙏🙏🙏
pls check @44:31 if train 1st travel 2 hrs alone then also train 2nd will 1.5 hrs alone because train 1st stop at 11:30 AM , why didn't you consider that
here we have to consider that the both trains start at same time so if train 1 after 2hrs of time will be 9:30 and so the train 2 starts at 9:30 by default.
Doesn't matter where they stops bro
Becoz they meet each before they stops at their respective stations
Obviously question is asked where meet each other
From Google maps distance between Pune and Bombay 150 km sir😂
Thanks a lot sir