Shift All Zero Elements to Right Side of the Array - Java interview Question
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- čas přidán 28. 05. 2021
- In this video, I have explained how to Shift All Zero Element to Right Side of the Array - Java interview Question.
OR
Shift all non zero elements to left side of the array.
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Just 2 days back I was asked the same question in one of the top MNCs, I did it through arraylist using .add and . remove in one loop
Naveen Sir, I was asked this question recently. I was searching the logic but saw this video.. Thanks for helping people in the testing community.. you are a true blessing for us.. Thank you
Thanks Naveen, gone through all 40 videos and with most of them learnt something new. Really appreciate your efforts. please keep going and keep growing 👍
Thank you Naveen. Please continue to do these kinds of coding problems
This series is really really helpful 👍
Thank you, Naveen.
Really appreciate your efforts sir 👍 thanks 😊
Brother keep Doing... It's really helping
Thanks a lot sir. This trick is very helpful, its very handy in many other array operations too.
Thank you so much sir
Thank you brother
Thank you
Thank You.
Java is fun❤️
Hi Naveen,
I was asked this question "how to Shift All Zero Element to Left Side of the Array" in my last interview. Can you please make a video of the same?
Hi Naveen...which tool/device/pad you are using to explain using pen (seems very smooth)...can you please share the details ?
Sir 1 hi dil h kitni baar jeetoge.
Hey naveen,
Can you do a program regarding setting the custom date and time and getting the date & Time.
Take a custom class and set the date and get the salary details according to the year of joining.
#interviewquestion
Naveen , what FONT do you use in eclipse ?
Please suggest any material to learn solve problems in leet code, hackerrank...
Please share the program for keeping all zeros to the left hand side of the array . This is being asked in interviews
Logic for shift left:
int count = 0;
for (int num : a) {
if(num == 0) {
newArray[count]=num;
count++;
}
}
for(int num : a) {
if(num !=0) {
newArray[count]=num;
count++;
}
}
Hii Naveen ,can you please tell the logic for shift left without out using two new arrays
int count = 0;
for (int num : a) {
if(num == 0) {
newArray[count]=num;
count++;
}
}
for(int num : a) {
if(num !=0) {
newArray[count]=num;
count++;
}
}
@@subramanianr2744 one correction
subu subramani
3 hours ago
int count = 0;
for (int num : a) {
if(num == 0) {
newArray[count]=num;
count++;
}
}
you don't need to write newAray[count]=num; bcoz newArray by default is taking 0. Hope it help u
What will be the time complexity of this programme as we are creating a new array here. Can we achieve it by single array only.
It will be O(n) only but with extra space. As I am not manipulating the existing array.
@@naveenautomationlabs thanks Naveen