What Ticket Price Maximizes Revenue? (Quadratic Word Problem Precalculus)
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- čas přidán 27. 08. 2024
- Learn what ticket price maximizes revenue in this quadratic word problem video math tutorial by Mario's Math Tutoring. We discuss how to find the revenue equation as a function of the number of $1 price decreases. We also discuss how to find the vertex of this quadratic equation.
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Been watching since about September or October and you’ve been a lifesaver on late nights when I’m bogged down with confusing work. I salute you and your work, Mr. Mario.
mario math man i love you
Mario can you please do more of these??? Need them so bad for my exam this week
really cool upload Mario's Math Tutoring. I smashed the thumbs up on your video. Keep on up the amazing work.
thank you mario becuae of you i will pass my grade 10 math exam your lesson was very much appreciated!
That's great!
I don’t normally comment on CZcams videos but somehow this quick 5 minute video made this concept click for me. This helped me to complete my story problem assignment that I spent all afternoon freaking out about. Thank you :)
Glad it helped!
Big fan from India sir🤓🤓
I love u dude covid is making me die bc of online classes but ur vids are super helpful
Thank you Mario you helped me understand the secrets of our universe
Thank you! This helped a lot
Glad it helped!
Thank you so much! Your videos make things so much easier to understand 🙏
This is very helpful for my test! Thank you
Glad it was helpful!
Super video! I applauded for ZAR 14.00 👏
nice job!
Thank you mr mario
After Covid people will go to the stadium for any price just because they finally will be able to go somwhere ;P And thank you for this video. My math classes, for now the ones from high school are retroactively useful :) I am planning to (re)teach myself a higher math. I had some h.math 20 years ago, got B and now I do not remember anything ;) I am in a process of gathering strength.
Wait shouldn't it be:
Ticket price : x
amount ticket price is lowered : 30-x
increase in attendance : 50(30-x)
attendance: 400+50(30-x)
revenue = ticket price x attendance
R(x)= x(1900-50x)
1900x-50x^2
Good content sir. I love it😍
Can you please do a algebra 2 introduction video as I’m trying to skip it
Your the best
I set the Price Function to Zero and the Quantity Function to Zero...($30-1x)=0 and (400+50x)=0. I get 22x and then use the midpoint formula by dividing by 2. This gives me an answer of x=11.
How is the 50x figured out to begin with?
Am I cooked? studying before final
no lock in
Sir, I am unable to find the solution of the problem below. I would be grateful, if you could help me.
Find √(b-c) (c-a) +√(c-a) (a-b) +√(a-b) (b-c)
find what?
This question was going to look crazy for me before i studied calculus.
The calculus method is Just multiply it.
Take a derivative. Find the critical points(by putting f(x)=0 And you will find the critical numbers. Use these numbers in the original equation and the highest number will be the answer for the X
May god bless you welcome to Ramadan
Quite the yapping
At the top point, slope=0. dR(x)/dx = 0. x = 11 ...??!!