The Michael Addition + 1,4 Additions with Soft Nucleophiles

joechem.io/videos/43 for video on jOeCHEM and attached worksheet + solution (below video on jOeCHEM aka the link)
In this video, we look at a functional group called enones--or alpha, beta unsaturated carbonyls--and how they are prime candidates to be attacked by nucleophiles in a 1,4 fashion.
We will specifically look at the Michael Addition, which is when an enolate (a soft nucleophile) attacks an enone. However, you can attack enones in a 1,4 fashion with any "soft" nucleophile, and we'll see an example of that by attacking an enone with a cuprate.
Previous version of this video: • Michael Additions + 1,...
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[@PunmasterSTP]

That was an amazing explanation, including the part about the differences between hard and soft nucleophiles!

[@peptoid1]

I love your passion to teach organic chemistry to people in amusing ways.

[@jeongminlee1551]

The best conjugate addition video i’ve ever watched!
I would love more explanation of Michael Donors and Michael acceptors for the context

[@CsGOismyreligion]

OMG I have been binge watching , love the videos

[@jOeCHEM]

CsGO, thank you for the kind words! Thanks for being a jOeCHEMist 🤓

[@PunmasterSTP]

I know the feeling!

[@kino-yuga9229]

i just discovered this channel, awesome work man!

[@kaushikumarihami1982]

very very helpful, I really like your explanation about hard and soft nucleophiles which has made the explanation even more meaningful

[@JohnDoe-hl2qm]

Amazing energy

[@zayrael]

thank you so much!! this video is really helpful 💯🔥

[@hrishikeshkhandeshe9620]

Keep up the good work bro. ❤️

[@SaahilMohta]

Such a great explanation, thank you!

[@AvaDuffy-uf8gu]

love this video! i appreciate you sm!

[@varunnaik6873]

Thanks a lot Joe ! REALLY HELPFUL

[@jOeCHEM]

Thanks for watching and the kind words, Varun!

[@jacobkimba1480]

I'm donating to your channel when i'm rich and famous, thank you!!

[@kechidadjihane1949]

That was really helpful thank you !!

[@lucaramacciottiperroni4544]

you saved me!! thanks bro!

[@kaushikumarihami1982]

very good explanation.

[@aidank.9184]

damn it joe, you’ve saved my ass again

[@anmoldeepsingh9281]

🔥 awesome

[@user-by4vg4wl6z]

I watch two videos for you and I really love it your video thank you ❤

[@jOeCHEM]

WOW, thank you for the kind words ❤
🇮🇶🇮🇶🇮🇶

[@incognitoburrito8]

youre great joe.i wish i had come across your channel earlier

[@jOeCHEM]

Aishwarya, well I'm glad you're here now!
Also, make sure to check joechem.io for all the same videos PLUS worksheets and solutions I’ve made to along with each (and I have videos going through each solution!)

[@christianmachado4795]

great video joe!

[@jOeCHEM]

Thank you so much for the kind words!

[@ammarhaider5453]

Thank You so much
May GOD always bless you.....

[@annaio659]

I’m trying to focus but you are handsome haha ,great explanation tho 💯

[@krishnashots5003]

thanks

[@Coco-cu1iy]

Thanks ! (from France)

[@jOeCHEM]

🇫🇷 🇫🇷 🇫🇷 🇫🇷 🇫🇷

[@ishaangautam5499]

Sir amazing video 👍🙇🏼‍♂️ sir is there any way to connect to you either by whatsapp or telegram?

[@tharushimunasinghe1716]

❤🙏

[@grettlowski]

In the first problem at 12minutes in, isn't there a double bond between C3 and C4 in the product? Or did something happens to it?

[@jOeCHEM]

Hi Grettlowski, so that C3 C4 double bond is gone in the product since the C4 carbon was attacked by the enolate. Refer back to 4:50, as to why that carbon is partially positive and susceptible to being attacked by nucleophiles (it's due to the resonance). Let me know if that does or doesn't make sense!