Electrical Engineering Made Intuitive
Electrical Engineering Made Intuitive
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Active Filters
Why do we need active filters and how to analyze circuits that include active components (i.e. Op-Amps).
zhlédnutí: 2 767

Video

Second-Order Passive Low-Pass and High-Pass Filters
zhlédnutí 5KPřed rokem
A simple technique to achieve better-performing Low-Pass and High-Pass filter is described through increasing the filter order with little complexity.
Second Order Band-Pass and Band-Reject Filters
zhlédnutí 1,4KPřed rokem
RLC Band-Pass and Band-Pass filters are introduced and their characteristics are analyzed.
First Order Low-Pass and High-Pass Filters
zhlédnutí 1,9KPřed rokem
First order filters are discussed and metrics to characterize them are introduced.
Passive Filters
zhlédnutí 1,1KPřed rokem
The concept of frequency selective circuits (filters) is introduced.
Circuit Transfer Function: Definition and Calculation
zhlédnutí 550Před rokem
We we discuss the definition of transfer function in Laplace domain and demonstrate methods to calculate it.
The mighty "Buffer": The amplifier with unity gain!
zhlédnutí 1,3KPřed 2 lety
Why do we need an amplifier that doesn't actually amplify (gain=1)?
Impedance in Laplace Domain
zhlédnutí 1,4KPřed 2 lety
This lecture introduces the most general definition of impedance in the Laplace domain.
Basics of circuit analysis in Laplace domain
zhlédnutí 1,1KPřed 2 lety
The equations for R, L, and C are introduced in Laplace domain and the process of Laplace domain circuit analysis is described in detail.
Preview of circuit analysis using Laplace transform
zhlédnutí 983Před 2 lety
The process of using Laplace transform in circuit analysis is previewed in order to prepare for the associated math.
Introduction to Laplace Transform (Why and How?)
zhlédnutí 944Před 2 lety
We will discuss why we use Laplace transform in circuit analysis and how?
Analog Adder and Difference Amplifier
zhlédnutí 543Před 2 lety
We will analyze active adder and difference amplifiers based on Op. Amps
Inverting and Non-inverting Amplifiers
zhlédnutí 570Před 2 lety
We will analyze two useful amplifier configurations and develop the gain equation for both.
Introduction to Operational Amplifiers (Op. Amps)
zhlédnutí 827Před 2 lety
The equations that describe the functionality of operational amplifiers is discussed for the first time and analyzing circuits that include op. amp. is practiced.
Parallel RLC Circuit (Over Damped)
zhlédnutí 1,1KPřed 2 lety
In this video we will analyze an over-damped parallel RLC circuit.
Parallel RLC Circuit
zhlédnutí 2KPřed 2 lety
Parallel RLC Circuit
BJT Amplifier AC Analysis
zhlédnutí 1,1KPřed 3 lety
BJT Amplifier AC Analysis
Circuits with Two-Port Subsystems
zhlédnutí 720Před 3 lety
Circuits with Two-Port Subsystems
DC Analysis in BJT Amplifiers
zhlédnutí 1,3KPřed 3 lety
DC Analysis in BJT Amplifiers
Active Filter
zhlédnutí 494Před 3 lety
Active Filter
Common Gate Amplifier
zhlédnutí 307Před 3 lety
Common Gate Amplifier
Common Drain Amplifier
zhlédnutí 371Před 3 lety
Common Drain Amplifier
Alternative Band Pass Filter
zhlédnutí 2,3KPřed 3 lety
Alternative Band Pass Filter
Common Source Amplifier
zhlédnutí 337Před 3 lety
Common Source Amplifier
Biasing simple MOS circuits
zhlédnutí 244Před 3 lety
Biasing simple MOS circuits
Transfer Function in a Circuit
zhlédnutí 1,2KPřed 3 lety
Transfer Function in a Circuit
Equations Describing Operation of BJT transistor-1
zhlédnutí 451Před 3 lety
Equations Describing Operation of BJT transistor-1
Diode Connected MOS
zhlédnutí 1,4KPřed 3 lety
Diode Connected MOS
Equations describing typical MOS transistors
zhlédnutí 215Před 3 lety
Equations describing typical MOS transistors
Multi-Diode Circuit Practice 2
zhlédnutí 606Před 3 lety
Multi-Diode Circuit Practice 2

Komentáře

  • @phillipneal8194
    @phillipneal8194 Před 5 dny

    Great presentation. Thank you. But what op-amp will I need for hf ?

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před 4 dny

      Do you mean High Frequency?

    • @phillipneal8194
      @phillipneal8194 Před 4 dny

      Yes. I keep reading about how to build filters with coils/inductors for ham radio. But I want to use op amps so I can get some amplification. . But I don't know which ones to buy. I know that slew rate is important. What parameters in the datasheets should I be looking at ?

  • @user-eh8qu3tf3d
    @user-eh8qu3tf3d Před 5 dny

    Great video!

  • @comfortasibiawaafo3916

    Thank you sir

  • @agusgowes
    @agusgowes Před měsícem

    Do you have this blok?

  • @aainajavaid148
    @aainajavaid148 Před 2 měsíci

    is it a second order circuit

  • @andreasandreou2651
    @andreasandreou2651 Před 2 měsíci

    no sound\

  • @nhathapham7115
    @nhathapham7115 Před 2 měsíci

    can't hear anything

  • @gabejagnoun2107
    @gabejagnoun2107 Před 3 měsíci

    .

  • @gabejagnoun2107
    @gabejagnoun2107 Před 3 měsíci

    love it.

  • @saidbaci4344
    @saidbaci4344 Před 4 měsíci

    One of the purposes of use of an opAmp is now made it clear, well done. Thank you very much.

  • @chumlee6634
    @chumlee6634 Před 4 měsíci

    Are you writing everything backwards from your point of view? That’s impressive!

  • @danielnoriega6655
    @danielnoriega6655 Před 4 měsíci

    I know you're applying inverse Laplace, but I still got lost where the Ks came from... more over, if I had to know the values at a specific time, how will I solve those Ks?

  • @willadem8643
    @willadem8643 Před 5 měsíci

    man, you are criminally underrated:( Absolutely incredible explanation. Wishing you a lot of success

  • @marinaarsuaga1181
    @marinaarsuaga1181 Před 5 měsíci

    Hi! When you do the module of H(jw), wouldn't it be (1-LCw^2)^2 - R^2C^2w^2? Since we are doing j^2 = -1. Let me know if I am wrong.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před 5 měsíci

      No because I am not doing "j^2" for calculating the magnitude of a complex number. I just need to take the imaginary component which is RCW in this case, square it and add it to the square of the real part (this is the definition of magnitude that I have explained in the different video). Hope this helped.

  • @Electrical-Engineering-Course

    Thanks

  • @kinzarashid2277
    @kinzarashid2277 Před 9 měsíci

    Shouldn't the last term in the equation be V_1/20 instead of V_1/45 (at 17:20)? Since the last term is equal to I_phi?

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před 9 měsíci

      I_phi = V_1/20 and V_1= V_o/2.25 put the two together and you get I_phi=V_o/45

    • @kinzarashid2277
      @kinzarashid2277 Před 9 měsíci

      @electricalengineeringmadei1041 oh yes, thank you sir. You wrote V_1/45 in the equation but the V_1 is a typo, correct?

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před 9 měsíci

      @@kinzarashid2277 yes it gets corrected later in the video.

    • @kinzarashid2277
      @kinzarashid2277 Před 9 měsíci

      @@electricalengineeringmadei1041 oh I see now. Thank you for posting these, I greatly appreciate your work.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před 9 měsíci

      @@kinzarashid2277 Where and what do you study (if you don't mind me asking)?

  • @z_.v
    @z_.v Před 9 měsíci

    thank you so much. Sir. i will listen and use this video for my studies. thank you Sir.

  • @EPICfranky
    @EPICfranky Před 10 měsíci

    🐐

  • @asherbarnsdale5203
    @asherbarnsdale5203 Před 10 měsíci

    Awesome video! Your channel is underrated.

  • @therookie273
    @therookie273 Před 11 měsíci

    Do you have a video which explains almost all types of diodes?

  • @alarsholala
    @alarsholala Před rokem

    باعث افتخارید استاد

  • @mechmania8450
    @mechmania8450 Před rokem

    Takes me back to HNC days. But I need to design a symetrical filter (will work both ways ) However the output and input impedances could be different which would have to be taken into account. This could probably mean the resistances would be different. Many thanks for the explanation.

  • @enginm.
    @enginm. Před rokem

    thank you so much sir. where did you take that example ?

  • @sagewagner3803
    @sagewagner3803 Před rokem

    I know that the solution of a differential equation depends on its form. Does this differential equation (L di(t)/dt + Ri(t)/tau = Acos(wt)) have the same solution as the general one (dy(t)/dt + y(t)/tau = Acos(wt)) if there is a constant multiplied by the differential term (L*di(t)/dt)? Or does this constant indicate that the differential equation is not of the same form as the general one? Must we divide by L and take tau to be L/R so the equation becomes di(t)/dt + (R/L)i(t) = (A/L)cos(wt) so that the differential equation matches the general form? Or does this not work because now the amplitude becomes A/L instead of A, the given amplitude?

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      Sage, in order to use the general solution your equation should match the general equation and therefore, you have to device by L first. Does that make sense?

    • @sagewagner3803
      @sagewagner3803 Před rokem

      @@electricalengineeringmadei1041 yes! Thank you. So tau becomes L/R. Does that mean the amplitude is now A/L? Or does the amplitude remain A?

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      @@sagewagner3803 Your tau is L/R and the equivalent amplitude for the general equation becomes A/L. Now that you brought this up I think I should have used a different parameter for the amplitude of the input signal for it not to be confused with the amplitude in the general differential equation! Oh well... 🙂

    • @sagewagner3803
      @sagewagner3803 Před rokem

      @@electricalengineeringmadei1041 So A is the amplitude for the source while A/L is the amplitude for the signal at v1?

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      @@sagewagner3803 "A" is the amplitude of the input signal to the circuit and A/L is the amplitude of the input for the generalized equivalent differential equation. It is not the amplitude for any particular voltage in the circuit. You just use it as part of the procedure to do the math. DO you happen to be at UCF? I would be more than happy to meet and clear any doubts you may have if you are.

  • @oguzbey4214
    @oguzbey4214 Před rokem

    Hi sir, thanks for your helping us to get better marks. I have a question about the equations in time between 22:30-23:00. We said that i2=i3 and also i3=i4. From the first equation we get V2=-V3 but from the second one, we get 5V3=3V2. Is there something that i might have missed? Best regards.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      I don't understand why you are saying from i2=i3 you conclude V2=-V3! Where is that coming from?

    • @oguzbey4214
      @oguzbey4214 Před rokem

      we said that i2=i3, at the same time 3is=i2. Am I wrong? From this point V2=i2 so we can say that V2=V2-V3/2 and this equation shows V2=-V3. thanks for responding.

    • @oguzbey4214
      @oguzbey4214 Před rokem

      I think i have a conceptual misunderstood. That 3is shows a potential term. I got it now, sorry 😅

  • @DarrenDIY
    @DarrenDIY Před rokem

    The way you explain is very intutive, thanks, Would love to see a video on second order filters using rc cct

  • @trapItaliana
    @trapItaliana Před rokem

    👍

  • @homerodaniel_007
    @homerodaniel_007 Před rokem

    I like this

  • @Coreyahno
    @Coreyahno Před rokem

    This video series has been very helpful in my Linear Circuits course I'm currently taking. You are even using the exact same textbook as my Professor! Thank you for uploading these.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      Corey, I am happy I have been of help. Please spread the work amongst your friends as I am planning to do more videos on other electrical engineering topics in the future.

  • @ashishjha9961
    @ashishjha9961 Před rokem

    🙏namaste from India, this series of lecture from your channel are gems. Thanks for making such excellent videos.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      Thank you Ashish! I am happy you have found this material useful. Please let your friends know if you get a chance.

  • @dilarakarabulak5673

    hello professor , at 17:34 I couldn't quite understand that V1=Vi . I would be happy if you answer.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      The two input terminals of an ideal op-amp follow each other (when there is a negative feedback which is the case here). Watch the video on ideal op-amps and I explain that in detail.

  • @maiky5815
    @maiky5815 Před rokem

    great video thank you

  • @JoyRidaPR
    @JoyRidaPR Před rokem

    Thank you!

  • @dilarakarabulak5673

    Thank you !!!!

  • @dilarakarabulak5673

    hello professor, I have a question on labeling circuits how do we choose the direction of the currents and how do we decide the positive- negative parts of the voltages and currents This problem has been messing with my head and I couldnt find an explanation that I can grasp well. Thank you for nice lectures .

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      Dilara, I suggest that you watch the lectures in which I explain the universal circuit analysis method. But to quickly answer your question, the direction of current is completely arbitrary.

    • @dilarakarabulak5673
      @dilarakarabulak5673 Před rokem

      I watched every lecture of yours before this one . Thank you for responding:)

  • @user-wu2mo7ou1n
    @user-wu2mo7ou1n Před rokem

    You can continue with you a very necessary theme

  • @pathToHaven
    @pathToHaven Před rokem

    Can't hear anything dude

  • @21thTek
    @21thTek Před rokem

    excelent !!! wish you the best with your channel ⭐⭐⭐⭐⭐

  • @Broughtvulture
    @Broughtvulture Před rokem

    Thanks for working out the formula to finding the impedence formula in S-Domain. This really clarified any questions and doubts I had. 👍

  • @leonhardeuler8457
    @leonhardeuler8457 Před rokem

    mamnoon :)

  • @jaraddemarco7664
    @jaraddemarco7664 Před rokem

    Just a side note: Classes in school are always exclusively a subject. Just math or just physics. What students need is something that is like a Math/physics class, because after we study just math for a semester, then the next semester just physics, we can't remember all of the math that goes along with the physics so we never see the important connections, of using our math skills to solve real problems. If it was mixed we would learn both of them, because we used all of our skills. I assume you are a professor, so if you agree with me maybe you can pass it down the line. I'm not sure if it is your intention, but watching these videos is what I've needed in an algebra class my whole time in college. Algebra class never took it this far or made it this real and applicable. With these videos I feel like I'm getting two things done at once. I see you simplify things, and sometimes you skip a lot of algebraic steps, but it's what I needed to make those skills solid. When I get stuck on your steps I stop the video and figure it out. Plus I'm learning circuits. Sorry for the long message, but I hope one day schools start to mix classes. I don't know if that's your intention but it's perfectly what I needed. Thanks.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      I totally agree with you Jarad! I would teach electrical engineers a class entitled "Math for Electrical Engineers" or something like that if it was up to me!

  • @electricalengineeringmadei1041

    correction: iL(0)=24mA+A1+A2=0

  • @jaraddemarco7664
    @jaraddemarco7664 Před rokem

    For I(2) I was a little confused. You got conductance for I(2) over conductance for I(3) and I (4)? But the conductance for I(2) is the resistance of I(3) and I(4)? Then total conductance was the added resistance? Does that mean when resisters are parallel that the conductance of the first one is the resistance of the other? If not, I don’t know why you used all resistance values as conductance. Thanks

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      The formula I used is called current divider for parallel resistors. I discuss that in an earlier video and you can watch that one to understand where it is coming from. Generally speaking I don't suggest using such formulas if you are not comfortable.

    • @jaraddemarco7664
      @jaraddemarco7664 Před rokem

      @@electricalengineeringmadei1041 figured it out.

  • @jaraddemarco7664
    @jaraddemarco7664 Před rokem

    Hello, there is one thing I am confused about in this video. You are using kilo ohms, but would it make a difference if you used ohms? Is it the same because it's always a ratio multiplied by Vs?

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      You are correct Jared, since we are dealing with ratios of resistors, it doesn't matter if you use kilo Ohm or Ohm. Even if you deal with actual values, you can still keep using kilo ohms and Volts, and all the currents end up being in mA as opposed to Amps.

    • @jaraddemarco7664
      @jaraddemarco7664 Před rokem

      @@electricalengineeringmadei1041 thank you

    • @jaraddemarco7664
      @jaraddemarco7664 Před rokem

      @@electricalengineeringmadei1041 was wondering if you knew of any good linear algebra videos off the top of your head? Setting these up into a system of linear equations, is the thing that’s most foreign to me, at the moment.

  • @xerveschex5761
    @xerveschex5761 Před rokem

    I assume by the end of all the lectures we will understand how you draw in the air.

  • @jaraddemarco7664
    @jaraddemarco7664 Před rokem

    That was a great explanation of where light comes from. I watch all your videos but thought that was remarkable.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      I am happy that the videos are helping you. Can I ask where you are?

    • @jaraddemarco7664
      @jaraddemarco7664 Před rokem

      @@electricalengineeringmadei1041 Sure, I'm in Rhode Island. I'm taking Linear Circuit Theory in the fall, and with these videos I'll be able to hit the ground running when classes start. Is there a book that has these problems or a book that you recommend?

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před rokem

      @@jaraddemarco7664 The book is Electric Circuits, by J.W. Nilsson and S.A. Riedel, 11th edition, Generally I don't use the techniques that are taught in most books and prefer to use what I call universal method (Lectures 3-1 and 3-2). I continue to use the same technique for all circuits at all times.

    • @jaraddemarco7664
      @jaraddemarco7664 Před rokem

      @@electricalengineeringmadei1041 That's good to hear because the approach is easy to follow. I'd just like the book so I don't have to draw out every circuit.

    • @jaraddemarco7664
      @jaraddemarco7664 Před rokem

      @@electricalengineeringmadei1041 I just have one more question, about how you said your method is unconventional and not in the book. Is your method still the general idea of the class? I guess my main question, is will your videos help me when I start the class?

  • @braedenlarson9122
    @braedenlarson9122 Před 2 lety

    v1(t) = (9000000te^-10000t)u(t)

  • @aaronz2781
    @aaronz2781 Před 2 lety

    քʀօʍօֆʍ

  • @ugurambarc3735
    @ugurambarc3735 Před 2 lety

    I was waiting this video for a long time :) thank you sir

  • @ugurambarc3735
    @ugurambarc3735 Před 2 lety

    have u a video about ideal and linear transformers ? thanks for clear explanation also :)

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041 Před 2 lety

      Ugur, I don't have that yet but I will make a note of your request and prepare one in the future. Can I ask where you are studying?

    • @ugurambarc3735
      @ugurambarc3735 Před 2 lety

      @@electricalengineeringmadei1041 In Turkey sir. Thank you so much

    • @user-wu2mo7ou1n
      @user-wu2mo7ou1n Před rokem

      @@electricalengineeringmadei1041 You can continue with you a very necessary theme