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RH
Australia
Registrace 10. 02. 2013
I translate mathematics into English.
Randell Heyman BA, BSc (Hons), PhD
Randell Heyman BA, BSc (Hons), PhD
Intro Ramsey theory
An introduction to a beautiful area of combinatorics. More videos at www.youtube.com
andellheyman
andellheyman
zhlédnutí: 21 593
Video
Primitive elements and order made easy
zhlédnutí 15KPřed 5 lety
Solutions to typical test or exam questions.
Set elements and subsets made easy
zhlédnutí 1,8KPřed 6 lety
Typical quiz and exam questions about set notation.
Presentations in the U.S.A.
zhlédnutí 663Před 6 lety
Information regarding 2018 talks for schools and universities in some states of the United States.
Mean value theorem made easy
zhlédnutí 882Před 6 lety
Three typical exam or test questions covering the principle, definition, error bounds and inequalities.
Euler's theorem made easy
zhlédnutí 81KPřed 6 lety
Solutions to 3 typical test questions. A beautiful theorem
Euler totient function made easy
zhlédnutí 74KPřed 6 lety
Solution to 4 typical exam/test questions. See other videos czcams.com/users/randellheyman
Fermat's little theorem made easy
zhlédnutí 68KPřed 6 lety
4 typical exam or test questions. For Fermat's LAST Theorem click here czcams.com/video/TEQrxlcprbY/video.html
Intro infinity
zhlédnutí 959Před 6 lety
There is more than 1 infinity. Enjoy some of the mathematics of infinity.
Inclusion-exclusion principle made easy
zhlédnutí 23KPřed 6 lety
3 typical test or exam questions. Solved using set notation and also using venn diagrams. More videos czcams.com/users/randellheyman
Intro proof 4 colour map theorem
zhlédnutí 4KPřed 6 lety
An introduction to the proof of a famous theorem and some of the beauty of how it was solved. More videos czcams.com/users/randellheyman
10 things about mathematics
zhlédnutí 3,6KPřed 6 lety
10 things in 3 min 45 sec. From Babylonian quadratics to the using complex numbers to count.
Surjective (onto) functions made easy
zhlédnutí 5KPřed 6 lety
Solution to two typical exam or test questions. More vidoes czcams.com/channels/mtelDcX6c-xSTyX6btx0Cw.htmlvideos
The limitations of mathematics
zhlédnutí 2,7KPřed 6 lety
When is too much mathematics too much? See my other videos czcams.com/users/randellheyman
Intro to the complex number i (part 2)
zhlédnutí 1,1KPřed 7 lety
Intro to the complex number i (part 2)
Next, draw the rest of the owl
God bless you
If i have x value how to get the first number before mod
this video a blessing
0:04 no, that's the null sign, the symbol to denote the empty set. Phi is something else.
You are correct. I think at the time I just used what was in Word. But that's no excuse. Thx for pointing it out.
@@RandellHeyman hehe. That's nice. I really don't care about the notation, you did a good job. Keep doing it. We need good math content creators.
what if the x has coeffecients to solve? Like i have this question that goes: 2x congruent 6 mod 14 3x congruent 9 mod 15 5x congruent 20 mod 60 Just confused a little bit, anyways the video was very helpful thank you!
In this case you can divide the first equation by 2 to get x congruent to 3 mod 7 (you might like to prove that it is ok to do this). Do the same for the other equations and then use my video.
@@RandellHeyman oh thank you!
God bless you
Thanks
You still have a problem with addition, Believe it or not.
I wanna ask for the term of gcd is one, is this term for two problems above or just for modular multiplicative invers?
human
pretty cool explanation
Thanks sir . 2024
Thanks for commenting. There is another video on big O also.
Best explanation so far.
Thanks. I'm glad it helped you.
Thankyou so much, none of my lecture notes are making sense but this does
Thanks for letting me know.
Thanks, helped a lot!
so glad i understood absolutely nothing that was said
My accent?
thanks!
You're welcome.
Why did my teacher just skip to teach this bit? Thank you for a good video.
Glad it was helpful!
Gcd 15 and45
Another great explanation - this is a fantastic resource. RH is a great educator, someone who breaks it down simply for students, rather than some academics who seem to take pleasure in showing how clever they are by describing things in a complex way!
Thanks for the positive feedback.
It's great to find a maths teacher who explains thing simply for us normal mortals! Thank you!
Glad it helped
cool
best explanation of this i've seen.
Thanks, appreciate you taking the time to let me know. Great that it's still helping people.
What about 26?
Go to 5'00" on the video and I explain.
youtube.com/@Enjoying8?si=Oi5M-6A59FbuPh45
This is great for math
The most clear and structural explanation without just using the usual steps without reason like other videos!!! Thank you !😇
Thanks. Appreciate such positive feedback.
The last one was real absurd!❤
Thanks for commenting. One of my colleagues found a variation that gives 1 divided by e squared.
@@RandellHeyman Great job!❤️ can you please make a video explaining why this "e" thing shows up everywhere as a messenger of continuity and calculus?
See my video titled The making of the video e
Thanks Mate! Great video
Glad it helped. Thanks for letting me know.
very unclear solutions. Just goes direkt to the answer.
Sorry you didn't understand it. Probably best to find another video, but if you let me know where you first get stuck I'm happy to explain further.
extremely informative content out here, would've never figured out how it worked if not your help. Thanks you
Thanks for commenting. Great to hear that my 10 year old video is still helping people.
im sorry lol but how can anyone say this is a good explanation?? he just says substitute this line with this line?? like which part do i substitute with what lol
Sorry you couldn't understand. There are of course other videos that might be better for you. Otherwise.... You are probably getting stuck around the 2 min mark. On the right hand side I show my workings to express 1 as the difference between multiples of 3000 and 197. From the last line on the left I have 6=1(5)+1. This means that 1=6-1(5). So I write that on the right. Now I want to get rid of that multiple of 5. To do that I look at the second last line on the left. This is 11=1(6)+5. This means that 5=11-1(6). So I can replace 5 in the first line on the right with 11-1(6). So then I get 1=6-1(11-1(6)). This means 1=2(6)-1(11), which is 2nd line on the right. Next I want to replace 2(6). To do this I use the 3rd last line on the left. This continues until I get to the last line on the right side.
@@RandellHeyman ahhh cool, thanks
I immediately know the answer and this is not the video for me but I'm watching it anyways.
Should the polynomial we are dividing be irreducible or primitive?
Irreducible
Great video. Thanks
Glad you liked it!
0:44 3000 = 15(197) + 45 3000 div 197 = 15 3000 mod 197 = 3000 - (197 *15) = 45 2:05 Left side of video 6 = 1(5) + 1 (solve for 1) 6 -1(5) = 1 1 = 6 - 1(5) (just switched sides, now it looks like the top right) Now get rid of the 5 from this equation So we work with the 2nd last equation on the left side 11 = 1(6) + 5 5 = 11 - 1(6) Now plug into [5 = 11 - 1(6)] into [1 = 6 - 1(5)] 1 = 6 - 1(5) 1 = 6 - 1(-1(6) +11) 1 = 6 +6 - 11 1 = 2(6) - 11 Repeat the process one more time Use the 3rd last equation on the left side and isolate 6 17 = 1(11) + 6 17 - 1(11) = 6 6 = 17 - 1(11) [re-expressed the equation] Plug [6 = 17 - 1(11) ] into the 2nd equation on the right side [1 = 2(6) - 11 ] 1 = 2(6) - 11 1 = 2(17 -1(11)) - 11 1 = 2(17) -2(11) - 11 let a = 11 1 = 2(17) -2a - a 1 = 2(17) -3a 1 = 2(17) - 3(11) Hopefully, that helps, that was too much mental arithmetic going on for me 🤣😭
Much help thanks a lot.
Glad it helped
Thanks a bunch❤
FERMAT n'a jamais utilisé tous ces calculs inconnus de son temps ! La solution est bien plus facile. Trouvez d'abord l'équation générale UNIVERSELLE cachée de FERMAT, valable quelle que soit la valeur de Zpuissance(N) et ENSUITE, vous en déduisez que Zpuissance(N) =Xpuissance(N) + Ypuissance(N) n'a pas de solution ! (conjecture de FERMAT).J'ajoute que c'est le plus beau CANULAR mathématique de tous les temps et c'est un mystère de voir autant de mathématiciens tomber dans le piège en formulant des théories inconnues de FERMAT .Il y en a même qui pensent que FERMAT n'a jamais eu la démonstration ! La démonstration est si courte et si facile que vous ne trouverez pas, cherchant une solution compliquée. Ce n'est pourtant pas difficile à comprendre ! Pour ceux que ça intéresse , afin de ne pas me répéter encore une fois, aller sur d'autres sites de FERMAT pour avoir plus d'explications de ma part..
The explanation for question one does not make sense to someone who knows nothing about this subject, the syntax and operations performed are inexplicable: Because Randell says 5 mod 3 = 2 mod 3 Without any explanation of why that is or how such a stupid looking syntax came about. Therefore not worth even trying to look at the other questions he aims to explain
Sorry the video didn't help, and thanks for letting me know. If you can't find help elsewhere email me through my website and I'll try to help further.
Just amazing! Thanks to you i saved a lot of time
I appreciate the feedback; thanks.
Great examples!
Thanks.
very useful, ty
Glad it was helpful!
That was super-easy to follow! Thank you.
Thanks for the positive feedback.
is 5^34 divided by 17 have a remainder of 1? Cause the textbook I have has a different answer.
I don't think the answer is 1.
@@RandellHeyman I figured it out. I just misunderstood the theorem. Thank you for responding.
merci bcp j taime fort
Merci
Triangle form is modular form. Proof of x^n+y^n=z^n < triangle ratio.
Hi this is an amazing video thank you! Just wanted to clarify if a_0 is meant to be divided by 2 in the original formula at the beginning? I’ve seen it like that on a lot of other formulas online, I could be wrong though!
I think what I have in the video is correct; a_0 is meant to be divided by two. Go to 4'35" where I say for a_0 you just integrate both sides with respect to x between -pi and pi and then solve for a_0.
I hate my lecturer who never makes things clear and also doesn't point out where to study, he'd better leave the academy since he's that incompetent to teach the student. Everyone suffers other than those who already got a mathematics background, everyone.
Sorry but this explanation is very difficult to understand, no idea what is even going on
Sorry to hear that. If you tell me exactly where you first had trouble I might be able to help. Otherwise try to find a better video :)
x^n+y^n=z^n is natural number combination three take in set theory are the three theory did a graph undercover