Find the Smallest Divisor given a Threshold | Leetcode 1283 Solution | Searching and Sorting

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1. Given an array of integers nums and an integer threshold, we will choose a positive integer divisor, divide all the array by it, and sum the division's result. Find the smallest divisor such that the result mentioned above is less than or equal to threshold.
2. Each result of the division is rounded to the nearest integer greater than or equal to that element. (For example: 7/3 = 3 and 10/2 = 5).
3. It is guaranteed that there will be an answer.
Topic: #BinarySearch #leetcode1283 #SearchingAndSorting
Used #DataStructure: #Array
#TimeComplexity: O(n*log(M)) , n is array size and M is maximum value of array.
#SpaceComplexity: O(1)
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Linked Questions:
1. Koko Eating Bananas
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#BinarySearch #geeksforgeeks #SearchingAndSorting #leetcode1283
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[@l_drago2875]

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[@mickyman753]

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[@shang_chi4651]

Best ever explanation 😁

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[@niharika3608]

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