PROJECTION OF PLANES_Recreated_Lecture 4 - Hexagon with surface inclined to HP and diagonal to VP
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- čas přidán 28. 08. 2024
- Download the Manas Patnaik app now: cwcll.on-app.i... Problem Description: A regular hexagon of 25 mm side has a corner on the HP . Its surface inclined at 45o to the HP and top view of the diagonal through the corner which is in the HP makes an angle of 60o with the VP. Draw the projections.
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Watching this on the morning of My 1st Sem Paper
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Lot of hard work put into it and I hope everyone acknowledges it. Thanks a lot for the tutorials. Helped me a lot.
But it is already given that surface is inclined at 45 degree to HP
I feel blessed....that I've come across this video....this is literally awesome😻😻I've been looking for this kind of visual explanation..thank you so much..sir👍☺
This video is very helpful for the engineering students
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Sir, your explanation is marvelous, which helped me a lot in sorting out any problem very easily.keep going sir.
we heartily appreciate your efforts sir ....God bless you :)
absolutely great sir. You are my motivation in this subject. Keep inspiring us by making this subject easy with ur teaching techniques.
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You rock sir keep doing more of them. From tamilnadu
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Prathap Anandhan neenga endha ooru
Hello sir, you have said in the previous videos if edge is to be inclined in the third part, you have to make it perpendicular in the first step, but in this video, the diagonal is parallel to HP.
I said that about edge and side and not about diagonal
I'm fromm Andhra Pradesh ...ur English communication is good ..to understand and very nice explanation..tnq a lot...
Thanks vinay.
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the diagonal has to be inclined with the VP in the third step then why it is parallel to the x axis?
Yes bro you are right
Yes
Yes
3rd step is wrong
Diagonal ko inclined Karna h bus@@srisaiteja9375
Sir, in the 3rd projection where you have take points 2 n 3 can on that line we take 1 and 2?
Thanks for such a good explanation. Great help !!.
Sir here diagonal line ad is inclined 60 to vp and on hp so we inclined ad as 60 is right or not please give me reply
hexagonal lamina of 30 mm sides rests on HP on one of its sides. the side which is on HP is perpendicular to VP and the surface of the lamina is inclined to HP at 45°.the lamina is then rotated through 90° such that the side on HP is parallel to the VP, While the surface is still inclined to HP at 45°. Draw the front view and the top view of the lamina in its final position
Im also want answer for this daigram
I m draw tha diagram😎
You are the God for me
whenever sir says reccomend this channel a weak student like me always think that i'll never do this
It's the best videos available for graphic students
U r the best sir.. These videos really help us a lot
Smartly, u explained all things perfectly
Sir, I have a doubt about diagonal .. as the diagonal is making an angle.. so in first step we need keep it perpendicular to xy...
yup! i have also the same doubt if u have find the ans please comment below
at first it is so complicated now its soo simple....
thank you very much
Thanks for your comments Paranay.....
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Sir heres the question
"A circular plane of 60mm diameter is resting on H.P on a point of circumference.The plane is inclined to H.P such that plan of it is an ellipse of 40 mm minor axis.The minor axis makes an angle of 45° to V.P. Draw projection of plane and find its inclination with H.P."
How to find inclination with H.P ?????
Sir plz respond as quickly as possible...
Thank you sir...
Nice effort Sir.ur too good. god bless you
Hi Faizal.....
I am sure this channel is helping you learn...
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Manas Patnaik ya Sir it helped me very much ...keep going Sir
Sir please make lectures on machine drawing based on assembling lathe,plumber block,machine vice,pedestal bearing ,and rivete ,cotter
Why is ad parallel to xy line and not perpendicular?
In this video you initially kept the diagonal parallel to xy line which was later to be inclined ,but in your earlier videos you stated that the line which is to be inclined finally should be kept perpendicular to xy line . I mean there are some exceptions
Yes i said about the edge/side, but did i ever say that about diagonal...I believe not....
Very helpful comment
Sir pls do sums from nd batt text exercises it would be more effective and easy for us
Simply awesome
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Effective teaching sir it is very useful to us
Sir I have a doubt y can't we take 1and 2 in 3rd case
Sir,here we have to incline the daigonal 60° to VP not a side..Can u please explain.
Side bc is parallel to diagonal ad ao if bc is at 60 with vp then ad will also be
Gr8 sirr... Keep helping students... N thanks alot
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Sir I'm studying in Bajaj institute of technology. Tomorrow there is my exam of engineering graphics.. After watching your videos, I'm quite sure that I'll score good marks in tomorrow's exam...
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Sir today's my exam was amazing.
Thank you for clearing our concept
I have a doubt. The diagonal perpendicular to xy is fb/ec. So shouldn't they be inclined at 60 degrees rather than ac
Here we have to select taht diagonal whose one corner is in HP. And u can clearly see that....
I would advise u sumedh to watch the video once again.....I am sure u gonna crack it............
Super sir .I will definitely suggest to see these videos to our classmates.
Thanks sir really best ❤and luckily this is from provided pyq's of my university
Great 👍
Super sir I am the student of CUSAT totally helpfull for me
My faculty teaching this Ed in mother tongue but I cannot understand it..sir,you just explaing in hindhi and English ...but it is very easy for me
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How to draw when there given a regular hexagon of 25mm dimension has a central hole of 30 mm diameter
regular hexagon of 40 mm side has a corner in the H.P. Its surface
is inclined at 45° to the H.P. and the top view of the diagonal
[
Sir your solution best I am able make sum well...
Sir first image position lo edge xy line ki perpendicular ga ledu kada
Pls cheppandi sir
Thank you sir this video help full for me
Brilliant Explanation
Thank u and all the best
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well said.
Thank you very much Manas patnaik sir
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Thank you sir jii
this is simply super sir. thanks sir.and keep moving
Q1: A regular hexagon of 40 mm side has a corner in the H.P. Its surface is inclined at 45" to the H.P. and the top view of the diagonal through the corner which is in the H.P. makes an angle of 60° with the V.P. Draw its projections.
Thanks sir for clearing my doubts
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good explanation ,sir..Thank you so much
Watching for mid Exam before 2 hours,
Exam time 5:00PM
Simply superb
Can in the third step can we just take the diagonal passing from the corner on the line which is making 60 to vp sir....??
Very useful....... Sooper.....understood the concept......
Thank u sir
Sir in this solution you took point 2 & 3 on the 60 degree line......but can we make this by taking 1 & 2 on that line?........this came 1st in my mind instead of 2 &3
Hello sir can you solve this question for me
An hexagonal of pyramid of 60mm sides has a corner on the horizontal plane of axis 100mm. the axis is inclined at 60 degree to the horizontal plane and top view of the diagonal through the corner which is in horizontal plane makes an angle of 60 degree to the vertical plane. draw the projection using auxiliary plane method
Sir how to draw a rectangle in this problems? What are the measurements ?
Thanks a lot sir ,it was very helpful
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Can you tell me is this problem similar to this one. A regular hexagonal plate 40mm side is resting on one of its edges on H.P. The plan makes an angle of 30°to HP and the longest diagonal makes an angle of 45° with V.P. Draw it's projection.
Made it very easy
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Beautiful lesson. Please which app are you using.
sir wont it be b'f' instead of f'b' ? we are looking from the front...so f would appear behind b ,right?
Thank you so much sir I have confusion of these problem
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easy to understand
Thanks sir this is very helpful
Sir in third step they given that diagonal through the corner then we have to incline the diagonal through 60 deg......
thanks sir for solving the problem
thank u sir ur the savior
Nice
Sir aren't you considering beta construction? Here we have reduced length and not the true length in second stage so corresponding how can you take phai angle with reduced length?
Last part is wrong TL of the diagonal is at an angle of 60 with VP not the trucated diagonal
How they can be drawn if we draw the second condition at an angle 60 degrees to vp in that case how they can represent 2,3 line
For eg you are the best
Sir i want to ask that why we have not found the apparent angle i.e. is beta
Sir my doubt is , in the last step you are assuming and drawing the rectangle . How can it be done on the sheet of paper ?
amazing explanation but adds are more which are interrupting
Ur guidelines are really helpful Sir thank you 👍👍
You are welcome Shraddha.....
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Sir iam a big fan of ur explanation really ur doing a great job ... Keep on gng sir🤍
Hello sir... I have a question... Why did you changed the position of hexagon...
Sir its given that surface is inclined at 45 degrees to hp but why did u say that no such information is givne
ad side makes an angle in the 3rd step but where is the ad side is 90 degrees in the 1st step 👆
Sir why u r taking bc points on 60degree line why can't we take ad points
My did same but I have rotated Top view and found angle on left side of 59deg Is it correct?
Thanks for video
please make the frequency of ads low,
they r very irritating
all the 3 hexagon size should be equal or its not necessary or if its equal will it be wrong or it must be equal? i dont see they r equal in the vid bt still i have doubt hope the reply will come soon ty
Sir u said 3 rd case mentioned line should be perpendicular to xy line but u have taken another way can u explain
sir have a doubt
u had said that we have to draw a side perpendicular to the reference line in the initial step but u dont seem to do so here.
please reply i need help
I suggest you to also have question on screen during drawing i.e I mean the second part of the video
Sir..... It's inclination of Diagonal.... Not a Side.......
Since u drew the true shape at a distance from axis line shouldn’t the third figure also be inclined at 60 degrees from that spot rather than the axis line?
Thats not necessary....