ABCDEF | Atcoder Beginner Contest 361 Solution Discussion

Sdílet
Vložit
  • čas přidán 5. 07. 2024
  • ABCDEF | Atcoder Beginner Contest 361 Solution Discussion
    My submissions - atcoder.jp/contests/abc361/su...
    Community discord server - / discord
    LinkedIn - / yt403
    Twitter - / aryanc403
    My Atcoder Profile - atcoder.jp/users/aryanc403
    Tags -
    #icpc #ioi #codeforces #codeforcessolution #codeforcessolutions #codechef #codechefsolution #codechefsolutiontoday #atcoder #geekforgeeks #topcoder#hackerearth #hackerrank #hackerranksolution #hackerranksolutions #leetcode #leetcodesolutions #leetcodesolution #leetcodecontest
  • Věda a technologie

Komentáře • 9

  • @shahbazkhan1864
    @shahbazkhan1864 Před 17 dny

    good work

  • @rushikeshkulkarni7758
    @rushikeshkulkarni7758 Před 22 dny +2

    F is good, I used inclusion exclusion on kth root to solve it
    With bit of precomputation, it got accept with 1ms runtime

    • @mihirmallick1698
      @mihirmallick1698 Před 21 dnem

      Yeah, mine got accepted with 1ms runtime too. Though I only considered counting numbers of the form a^p, where p is a prime, so this reduced the task to checking 2,3, 5, 7, 11, ... , 59th power of numbers and applying inclusion exclusion on that

  • @anshsingh9739
    @anshsingh9739 Před 20 dny

    Won't there be (N+1) places where we can have 2 consecutive Dots.

    • @aryanc403
      @aryanc403  Před 20 dny

      Yes, we will have N+1 places.

  • @shitposting2234
    @shitposting2234 Před 21 dnem +1

    I was able to solve ABCE . Any tips for solving problems with lower constraints? I am only able to solve O(n) and O(nlogn) ish solutions and just can't think when the constraints are lower

  • @tommyshelby6277
    @tommyshelby6277 Před 22 dny

    i am so dumb for D still

  • @Ahryno781
    @Ahryno781 Před 22 dny

    is G that hard?

    • @aryanc403
      @aryanc403  Před 21 dnem

      I felt it was hard, but editorial makes it look easy.