TRICK TO FIND OUT NO.OF LONE PAIRS with 👉 NEET, JEE questions👍

[@ganeshjaggineni4097]

Nice super excellent motivated

[@silverstarkhonglahofficial4517]

Great explain sir💕💟

[@chokkakulayerrinaidu5083]

Excellent explanation sir

[@jyotiholi7952]

The way of giving tricks and teaching is wonderful Sir.... Overwhelmed by your teaching Sir.... Thankew sir🙏

[@manishayadav8426]

Thanks a lot sir

[@anuverma4698]

Very informative ⭐

[@m.vsubbareddy7686]

I have seen this trick before Feb jee, forgotten. Before July jee, confused. And in August now, for my Eamcet. I think, I will get it to my mind.thanks sir. But, this is so sweet trick. It saved me Alot times. I mean, you saved me alot and lot times. So I have given such importance and watched thrice and thrice. Glad to have online teachers like you sir. Bless me finally sir , please

[@kashyaprahul5019]

Which college you are in??

[@udayphanindrakanamarlapudi4437]

Thank you so much sir and your Explaination is soo good 👌👌

[@MrAbhishek-nn7ld]

Tq sir this Vido very helpful

[@rishijoseph3534]

Thank you so much.. All these years. I didn't understand.. Just 16mins video I could understand the concept

[@Asgard126]

Holy frickin underrrratedddd ... All the best brother... Nice vdo

[@shivanim8461]

Super explanation sir upload more vedios

[@SumpathK]

thank you sir.

[@MrAbhishek-nn7ld]

Understood sir tq

[@pragnachowdary6228]

Really ossum sir 😍😍 Understood very clearly tq sir ...keep doing more videos...

[@adeneetha9125]

Thnks alott😊

[@vijaytalladi9315]

Very useful

[@althurumasthanaiah6631]

For sf6 - 4bond pairs, 1 lone pair
For C-H3 - 3 bond pairs, 1 lone pair
For BrF5-5 bond pairs, 1 lone pair
Is it correct sir

[@gobegas9751]

Super sir

[@garimarajput7750]

Thank u soo much sir for such an amazing explanation 🤩😇

[@kumarisweta1611]

Oh my God.......best teacher ever I had seen till now 🙏🙏🙏🙏🙏🙏

[@user-lp9on4zi7n]

Thanks😊😊😊😊

[@kabitajena2622]

nice trick for jee and neet aspirants

[@meghanaganapathy408]

Tnq sir

[@Soulmatemine]

Nice explaination

[@vijaytalladi9315]

Very good

[@naveentamilvanan7000]

Supper

[@inspirationalvideo1833]

Sir your teaching skill is awesome 👌👍 that beyonds compare....thank you sir ...

[@asnchemistry]

Please subscribe
Please share

[@krishijain7300]

Sir upload more videos you yeach so well

[@dreampeak9364]

thankyou sir finally i found such amazing explanation

[@rafsumsarsad]

Thank you sir it helped me a lot

[@supriyasingh7800]

Good

[@kpandu6152]

thank you soo much sir....as ur vedios very useful....now iam preparing for eamcet....these r vry vry helpful...thanks alot....

[@dr.entropy3444]

Thank you❤❤❤🌹

[@raviravikumar6030]

Please do more videos on inorganic chemistry

[@prabhakara7340]

Thank you so much sir, this helped me a lot.

[@shivangisharma3927]

How to calculate lone pair and bond pairs easiest trick. . . czcams.com/video/1Menuw8iMFw/video.html

[@avinashhipparge9312]

than kn you

[@ganeshjaggineni4097]

I WATCHED MANY VIDEOS ON CHEMISTRY BUT TILL THE TIME, I DONT KNOW WHY FLOURINE, CHLORINE CONTRIBUTES 1 ELECTRON FOR BOND AND WHY OXYGEN CONTRIBUTES 2 ELECTRONS FOR THE BOND.. AFTER WATCHING YOUR VIDEO, I UNDERSTAND IT.

[@naveenmydur9724]

Thankyou

[@basicstudyuse2041]

XeF4 = 8+4/2 = 6
So lone pain e- = hybridation - bond pair e-
Lone pain = 6-4 = 2

[@arnavsingh2677]

u explained it in most easiest way
thank u for uploading these videos😃

[@asnchemistry]

Now,
I am uploading videos in examsatozplus channel
Please subscribe 🙏
This is the link
czcams.com/video/lsgXifA1kHU/video.html

[@keerthanakeerthana7022]

sir plz make more video like this....now only i found your channel sir....
for me i need your help sir for neet 2020 sir plz sir plz make more videos for us sir plz pzl

[@anushaneha7302]

Sir please upload more videos for tricks to solve questions in NEET .

[@asnchemistry]

Sure
Please share to your friends

[@LKS_PRODUCTION]

Tq sir doubt clear 🌻

[@shivangisharma3927]

How to calculate lone pair and bond pairs easiest trick. . . czcams.com/video/1Menuw8iMFw/video.html

[@Asgard126]

Homework
1) sf4 1lp+4bp
2) ch3- 1 lp+3bp
3) Brf5 1lp+5bp

[@Mluke5822]

Thanku

[@shivangisharma3927]

How to calculate lone pair and bond pairs easiest trick. . . czcams.com/video/1Menuw8iMFw/video.html

[@kpandu6152]

sir for oH- (hydroxyl ion)and NAOH tooo???

[@arunaaakula226]

Sf4-4 bonds,1 loanpair.NH3-3 bond pair,1loanpair,Brf3-3 bondpair,2loanpairs

[@pankajneetwarrior5228]

Come and teach in Allen sir

[@jyotiholi7952]

If valency of surrounding atom is 4 means? Then 4*monovalent atom?

[@venkatroyalcreations4451]

1answeris 4bp + 1 lp

[@selvarathinam6828]

In I3- no of lp=9

[@jadalaprashanth9404]

BRF5 =5bp-1lp

[@venkatroyalcreations4451]

2 answer is 3 bp + 1lp

[@venkatroyalcreations4451]

3 answer is 5 bp + 1 lp

[@jayapandey8940]

No2+ mei lone pair 1 aa rha mera is technique se but ye kese hoga please answer sir

[@Krishna77508]

So2 ki cheppandi

[@floraagastinagastin3613]

Sir iodine 13 pls clear pannuga sir 3 iodine thaana podanum

[@arunaaakula226]

Sir corrector kado chepandi

[@bharathiepuri9650]

Sf4=1- lp, 4-bp
Ch negative 3= 1-lp, 3bp
BrF5= 1-lp, 5-bp

[@jadalaprashanth9404]

SF4 =4 bp-2lp

[@mini5282]

No its 4bp nd 1lp check once ☺️nd all the best

[@poonamschitchats6695]

Please upload full chapter question solving videos sir

[@neermita7587]

Sir, how will we find the lp and bp of NO3- with this trick?

[@vipinyt3233]

No3- means No is least in no. So negavitive charge so 6 e , oxygen make double bond so 0 lone pair

[@jangakeerthana]

Is this trick applicable for NO3-

[@ganeshjaggineni4097]

SF4 : BP=4, LP=1 . C^-H3: BP=3, LP=1 . BRF5 , BP=5 , LP =1.

[@amarjyotitripathy491]

We can't found no3 minus 1 structure in this trick

[@gobegas9751]

Sir lone pair of HNO2 hno3

[@dreampeak9364]

HNO2 mein 0 l.p

[@Studyndexplorenew06]

SF4:- 4bp and 1 lp
CH3negative :- 3 bp and 1 lp
BrF5:- 5 bp and 1lp

[@shivangisharma3927]

How to calculate lone pair and bond pairs easiest trick. . . czcams.com/video/1Menuw8iMFw/video.html

[@swathi536]

Sir Xe03 lo oxigen 3 unnaye kadha sir
Naku ardham kaladhu sir

[@asnchemistry]

Each Oxygen forms 2 bonds
So XeO3 has one lone pair

[@rachanabshetty7822]

Sir u told 5th-8th group element have 3,2,1,0... valence electrons..but You writtn for phosphorus 5 ..🙄🧐🤔🤔🤔

[@asnchemistry]

Those are valances (3, 2,1,0)

[@tharuniyaaumachander5279]

Because phosphorous is a central atom you have to consider no. Of valence electrons which is 5 .

[@sunitanayak3562]

Sir,if iam not wrong in XeF2 there is one bond pair n 3lone pair but you wrote 2bond pair by mistake.