ट्रेन (380m) 110 km/h की गति से 36 सेकंड में प्लेटफार्म को पार करती है। प्लेटफार्म की लंबाई? 🚅🤔❓
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380+x=110×5/18×36
380+x=1100
X=1100-380
X=720m
5 18 36 kya hai kaise aaya
36 sec diya gaya hai
aur km/hr 1000/3600=5/18
@@tanishjain614636 sec diya gaya hai
aur km/hr 1000/3600=5/18
परफेक्ट
@@tanishjain6146 to change hrs into second he use 5/18
Distance = speed × time
Distance = 380m + distance of platform (x)
380 m+ x = 110 km/hr× [. 36÷(60×60)hr]
380m + x = 1100 m
X = 720m ans
0.72000016 km. Without any formula
Kese kiya bro😮
To find the distance of the platform, we can use the formula:
Distance = Speed × Time
First, let's convert the speed from km/h to m/s:
110 km/h = 110,000 m / 3600 s = 30.56 m/s
The train covers the platform in 36 seconds, so:
Distance = 30.56 m/s × 36 s = 1099.36 m
However, this includes the length of the train itself (380 m). To find the length of the platform, subtract the train's length:
Platform length = 1099.36 m - 380 m = 719.36 m
So, the distance of the platform is approximately 719 meters.
D=s×t=110×(5/18)×36=1100m
Platform distance=1100
Tarin distance=380m
1100-380=720m
720
1100
Nice😊
Same same bhai , hmm bhi aise hi banaye hai
720🎉
Answer is 720 MTR
And nice mathod sir ,,,questions while travelling 😊😅
Correct bro❤
Shi h bhai
Question galat
Q kaha se start kya tha
1100 मीटर
1100m
ट्रेन की लंबाई = 380 मीटर
ट्रेन की गति = 110 किमी/घंटा = 110*(5/18) मी/सेकंड = 110/3.6 मी/सेकंड
समय = 36 सेकंड
प्लेटफ़ॉर्म की लंबाई = x मीटर
ट्रेन और प्लेटफ़ॉर्म की कुल लंबाई = 380 + x
कुल दूरी = गति * समय
380 + x = (110/3.6)*36
380 + x = 1100
x = 1100 - 380
x = 720 मीटर
प्लेटफ़ॉर्म की लंबाई 720 मीटर है।
Meanwhile me solving JEE ADVANCED questions 🗿
😂great bro and answer is 720m
toh wahi karo bro yaha kaise aa gaye😂
Bhai tuu kis field me kis ko ghusser raha he udhar alag tayari chalta he idhar alag.
Guaranteed tu kuch nahi karne wala karne wale ase hala nahi macahte 🤡🤡
Sach kaha bhai maine bhi jee ki preparation ki hai lekin sir ne jaise hi question pucha maine chup chap solve kiya, kisi bhi chiz ka ghamand nhi karna chahiye@@mayankgupta9321
380+x/110×5/18=36
380+x=36×110×5/18
380+x=1100
x=720mtr
Detailed formula?
Kya khichdi pka di tune
Ye lo solution
D=s×t=110×(5/18)×36=1100m
Platform distance=1100
Tarin distance=380m
1100-380=720m
@@catcute3698wo khichdi nhi pka rha hai legend hai 👍
Aap bhi tahari pka di ye lijiye salution 380+x=110*5/18*36=720m@@catcute3698
720mtr
720m.
Convert speed 110km/hr in m/s
S=110×1000/60×60=30.56 m/s
distance coverd in 36 sec
D=s×t=36×30.56=1100.16
Now minus the train length
1100.16-380=720.16m
Thanks
No need to minus trains length
Galat hai
D- 380m
S-110×5/18
T- 36sec
Suppose Platform length -X
Total(Train length+ platform)/speed=time
(380+x)/110×5/18=36
= 720metr
x=length
110kmh=110×1000=110000 mph
then,convert hour to sec
110000÷3600=30.5mps
30.5×36(given time)=1098
380x=1098
x=718🥱
easypisy
guys i know this qs is solve in short
i gust describe for you.
110km = 110000m
1h= 3600sec
As speed is 110km/hr, so the train goes 110000m in 3600sec, thus the train will go 1100m in 36sec.
As the train length is 380m, so the platform size is ( 1100-380)= 720m.
As simple as that.🙏
Typing mistake 110000 meters not 110000 km in line 4😊
@@sukeshkr1928 yes..😊 right
720
720
Muje to aata nhi coment me dekhne aa gya❤😅
110 km goes in 3600 seconds, then how much distance will be covered in 36 seconds?
30.55 m will be covered in one second, then 36 x 30.56 = 1.1 km will be covered in 36 seconds.
110/60=1.833
1.833/60=0.030
0.030*36=1.1
Means is distance is 1.1 km(1100 m)
Right
Speed =110×5/18=30.55
Speed = distance/ time
Speed × time=distance
30.55×36=distance
1099.80=distance
Total distance between train in 110km/h =1099.80
Train lenth =380m
Then
Platform distance = total distance between train in 110km/h - train lenth
1099.80-380
619.80m
Then platform distance = 619.80miter
Your answer = maximum marks of neet exam😊
Creative are you preparing
@@tanishjain6146 no bro
Hy vanshi
Bro it is not maximum marks , it is a normal marks , nowadays 😂😂😂
@@Apex_Predator13 🙂🥲mere liye to maximum h normal to sirf kuch logo ke liye h
110×5/18=30.55
Distance= speed×time
=30.55×36
=1100
=1100-380
=720m
72o
Bhai 5 kya hai plz explain
@@sandeshshewale3052
This is the conversion factor which is used to convert km/h to m/s. On simplifying 1000/3600 further, we get 5/18, which can also be used to convert this speed.
Bestly explaind ❤
😅
Let length of the platform be X
And train length = 380 ( given)
|v| = 110kmh-¹ = 30.55 m/s
So simply using distance covered formula
Distance = speed × time
X+380 = 30.55 × 36
X = 1100-380
X= 720metre
And we got lenght of plateform which is 720m 💫💫😗
Ok
So time take is 36sec
Velocity in m/s=110km*(1000/3.6)=30.56m/s
S=Ut=36*30.56=1100m
Station length+Train length=1100
Station length=1100-train length
=1100-380
=720m
Ismei Pen paper ki kya jaroorat hai..
3600s mei 110km
36 s mei 1.1km = 1100m
1100 mei se train ki lambai 380 minus kardo
answer is 720m😏
Nahi app galat ho, apka ans train station ka chua pass nahi kia
@@pofocreation811 chua kya hota hai bhai?
T+P=110×5/18×36=1100
P=1100-380=720M Answer
Right answer
Let the length of station be ‘x’ metre
So, distance travelled= (380+x) metre
Speed= 110 Km/hr = 110 × (5/18) m/s
Time taken= 36 seconds
Using the formula,
Distance = Speed × Time
380 + x = 110 × (5/18) × 36 = 1100
x = 1100 - 380 = 720 metre
Pen aur paper uthane wala mood hota to phone uthakrr CZcams thodi scroll kara hota main sir 😂😂
Maine socha comment hi padh leta hoo answer mil jaayega 😂.
Same to same 😂😂
Bhai Mera coment bhi pad Lena...
Thank you Bhai hmara selection ho jaega agar aap aaise hi comments pdte rhe ❤
720
You are very chalak bro😂
380+D/110*5/18=36
D=110*5/18*36-380
D=1100-380
D=720m
1hour=110kmt travel
3600secend=110000meter
1sec=110000/3600
=30.55555556 meters
36sec= 30.55555556×36
=110meter
Train lenth 380
36sec cross the station= train + station lenth
Then 110-380=720m
Station lenth720m
To find the length of the railway station platform, we need to follow these steps:
1. **Convert the train's speed from km/h to m/s**:
- 110 km/h = 30.56 m/s [1].
2. **Calculate the total distance traveled by the train in 36 seconds**:
- Distance = Speed × Time
- Distance = 30.56 m/s × 36 s = 1100.2 meters [2].
3. **Subtract the length of the train from the total distance to find the platform length**:
- Platform length = Total distance - Train length
- Platform length = 1100.2 m - 380 m = 720.2 meters [3].
Therefore, the length of the railway station platform is **720.2 meters**.
Platform ki length 720 m💯
Sahi pakda hooo.....
I also have the same ans.
110*5/18 *36 =1100 m
1100-380= 720
Distance=speed*time
💯✅
380+a/110×5/18=36
380+a=36×110×5/18
380+a=1100
a=720mm
Nakal to dhang se karna seekh😂
Correct answer should 1100 kyuki station ki लंबाई puchhi hai
V=110*5/18=30.5 m/s
Station L=30.5*36=1100 m
Total D covered= 1100+380=1480
Because jab train station ke last end pe pahuchegi to uska aage ka hissa station ke last end pe hoga aur puri tarah se station ko cross karegi to total distance 1480 hoga
Se60×60mit=3600se
Spd110÷3600 se=0.0305555556parseked side
0.0305555556×36se=1100-380=720
720 plet foki lamabai
720 meter without pen or copy❤
Without pen or paper just watching comment 😂
Good 👍
Distance= speed*time
Speed =110
Time =36 second
Time 36/3600
Time = 1/100 hour
D=s*t
110*1/100
=1.1km
1100 metre
Train length 380 metre
Platform 1100-380
= 720
(380+P)18/110*5=36
P=1100-380
P=720mtr
Best❤❤
380+x/110X5/18. =36
380+x =36X110X5/18
380+x= 1100
1100-380 =720mm. Ans
mm nahi meter hoga
Bro 720mtr.
Mm? 😂
Mm 😂 ye to mili meter hota h
720mm❌
720m✔️
3600secand= 110000 mtr
36secand = 1100 mtr
1100mtr. -380 train length
Platform length= 720 mtr
Time = length of train + length of platform ÷ relative velocity
36 = 380+ l ÷ 36×5/18 = 720 😅😅
720m right answer
720 metre very simple question
Yes bro iske liye to koi pen notebook ka jarurat hi nehi hai 😂
340 m
distance covered in 36 sec = 1100m
1100 = 2(380) + platform length
(380+station)÷110×5/18 = 36sec
380+station=36×550/18
380+station=1100
Station=1100-380
Station=720
720मिटर
T=p+t/v
P+t=T.v. (110km/h = 110x5/18 m/s)
P+380=36x110x5/18
P=1100-380
P=720m
380+$=110*(5/18)*36
$=1100-380
Lengthof platform $=720m
110 km/h = 110,000 m / 3600 s = 30.56 m/s (approximately)
Now, we can plug in the values:
Length = 30.56 m/s × 36 s = 1099.36 m
However, this includes the length of the train. To find the length of the station, we need to subtract the length of the train:
Length of station = 1099.36 m - 380 m = 719.36 m
So, the length of the station is approximately 719 meters.
720 meter
110×5/18×36=1100meter
1100-380=720meter
X +2*380 =(110*5/18) *36
X=340m
Let's denote the length of the platform as \( L \) meters. The length of the train is \( 380 \) meters, and its speed is \( 110 \) kilometers per hour, which is \( \frac{110 \times 1000}{60 \times 60} = 30.56 \) meters per second.
The train crosses the platform in \( 36 \) seconds. Therefore, the distance covered by the train in \( 36 \) seconds is \( 36 \times 30.56 = 1100.16 \) meters.
This distance is the sum of the length of the train and the length of the platform, i.e.,
\[ 380 + L = 1100.16 \]
Now, solving for the length of the platform \( L \):
\[ L = 1100.16 - 380 = 720.16 \]
Therefore, the length of the platform is \( 720.16 \) meters.
Chal=110×5/18
=275/9 m/s
Duri=275/9×36
=1100
Platform ki lambai=1100+380
=1480 ans
Sir kya answer right hai❤❤❤❤❤❤
Kon itna jhanjhat karta hai mai jabal pur mai hii rhata huu platform par jaa kar naap leta huu😂😂😂😂 720m answer
110km/h = 30.5m/s
D = x + 380
T = 36
X+380= 30.5*36
X=1098-380
= 718meters
Easy explanation:
If the train is moving at a speed of 110km/h, therefore distance which the train covers in each second is 30.55 mtrs. Now the train crosses the platform in 36 seconds, 30.55x36=1099.8 mtr (approx 1100 mtr). Now we subtract the length of the train from the distance travelled in 36 seconds for the length of platform, 1100-380= 720 mtrs. So the length of the platform is 720 mtrs.
Jabalpur station ki length 720m hai👍
Speed =distance/time
110*5/18=platform + train length/36
D= Speed × Time
380= 110 km/h×36m
380= 110×(5/18)m×36m
380= 1100
= 720
110km/h
1min mein cross 1.83 km
60 sec mein 1833 mtr
1 sec 30.55mtr
36 sec x 30.55 mtr =1,099.8 mtr
110×1000= 110000÷ 3600
1 sec = 30.55m
36 sec = 30 .55× 36
= 1099.8
Train length = 1099.8- 380 = 719.8 = 720 meter
Itna simple toh hai dimag me hi karlo na bhai log
Train length 380 metres hai toh train speed ko bhi metres me karlo means 110000 divide it by aur time ko bhi 3600 divide toh aayega 30.55 agar 1 sec me 30.5 metres cross karta hai toh 36*30.55 toh 1100 aayega now minus the train length 1100-380
720 answer
Distance in 36sec=110000/100=1100mtrs
Plateform distance 1100-380=720mtrs
3600 second →110km
36second→1100m
•°•1100-380=720m
Good motivation for students.
110X(5/18)X36 is equalto (380+L) then by solved it L is equal to 720mitre
Distance = speed * time
X+380=110*1000/3600*36
X+380=1100
X=1100-380
X=720 mtr
60 minat =110 km to 6 minat /360 second = 11 km /11000m to 36 second = 1100m
Ans = 1100m
चाल = दूरी / समय
110 kmph = 380+d/ 36
110x1000x36/3600 =380+d
1100=380+d
d = 1100-380
d= 720 मीटर
Apka ans train station ka chua, pass nahi kia
1100 deducted length of train 380= 720meter ✌🏻👍🏻
Itna soch na kiya hai joldhi se google kar leta hu😅
Let's break it down step by step:
1. Speed of the train = 110 km/h = 110,000 meters per hour (convert km to meters)
2. Time taken to cross the station = 36 seconds = 0.01 hours (convert seconds to hours)
3. Distance covered by the train in this time = Speed × Time = 110,000 meters/hour × 0.01 hours = 1,100 meters
4. Since the train is 380 meters long, the distance covered includes the length of the train itself. To find the length of the station, subtract the train length from the total distance covered:
Length of station = Distance covered - Length of train = 1,100 meters - 380 meters = 720 meters
Therefore, the length of Jabalpur railway station is 720 meters.
720m.....itna easy kis exam me aata hai😅
Aapke station se jabalpur station Tak total 1100 miter duri hai yani point x se y ke bich ki duri 1100 m pr sath hi train ki length 380 m hai to ho sakta hai yaha do answer ho kyuki agr train ka pichhla hissa point x pr hai to 1100-380 = 720 lekin agr train ka agla sira point x pr hua to point y ko par karne ke liye uske dwara duri 1100+380 = 1480 m Tay ki gyi
110×5/18×36=H+360
110×5×2=H+380
1100=H+380
H=1100-380
H=720m
110*5/18=
275/9*36=1100mt.
Plateform=1100-380
720mt.
😊😊😊😊
Distance= speed× time
380 + plateform= 110×5/18 ×36sec
380 + plateform=30.55×36
380+plateform=1100
Plateform=1100-380
Plateform= 720mtr
Matlab ki Jabalpur me vandebharat train nhi rukti
Aur 720mtr lambi hai
In 60 mins train travelling 110 kms
In 0.6 mins travel 1.1 km i.e. 1100 meter
Therefore length of platform = 1100 - 380 = 720 meter
Easy way is
110k/h = 275/9 m/s
275/9 × 36 = 1100
1100-380=720meter khatam
110*5/18*36=1100-380=720
Normal people trying
Legend google
Answer 750m😂
Jabalpur Jn. 410.87 m
Madan Mahal Jn. (Jabalpur) 750m
Par me toh chemistry ka student hu 😂
E=MC²
PT=XYZ
JBLP×WNB+TRN=STN
620+100
=720
😂
110km/hour=110000/3600=30.55meter/second
X is lenghth of platform.
The train crossed the platform plus its own length in 36 seconds.
Speed=distance/time
30.55=x+380/36
X=36×30.55 -- 380=719.8
380 + X = 110× 5/18 ×36
380+ X = 110 × 10
380+ X = 1100
X = 1100- 380
X = 720 M
0.38km + X km = 110 * 36/3600
0.38km + X km = 110 * 1/100
0.38km + X km = 1.1
X km = 1.1 - 0.38
X Km = 0.72km
X = 720m
Easy sir 😂😂 make it hard next time😊
जबलपुर स्टेशन की लंबाई =720m
110km/h = 110,000m/h (3600 second)
110,000m/3600 = 30.56m/second
30.56×36= 1100.16
1100.16-380=720.16 metre(answer)
Good bro🎉🎉🎉🎉🎉🎉🎉🎉😊
From jharkhand
380+P = 110x5/18 x 36
=> P=1100-380= 720 metres
720.016 metres is the length of the platform
380+X = 110× 5/18 = 30.5555.... × 36 =1100
X = 1100-380 =720m ans
v= 110 km/h
t= 36 s
v=d/t
d=v•t
d= 110(1000)/3600•36
d=1100 m
110×5/18×36= 1100 - 380= 720m(Ans)
T+p=110×5/18×36=1100
P=1100-380=720 ans
Maine bina pen copy uthar answer nikal eska 720 first time 😊
110 divide by 100 = 1.1 into 36 second =39.6 meter
X = (110000×(36÷3600)) - 380
X = 720 m
550/18=380+x/36
550=380+x/2
1100-380=x
×=720
770 Meter Platform distance hai😊
380+x=110×5/18×36
380+x=1100
x=1100-380
X=720m