Graphing Cotangent with a Phase Shift

👉 Learn how to graph a cotangent function. To graph a cotangent function, we first determine the period (the distance/time for a complete oscillation), the phase shift (the horizontal shift from the parent function), the vertical shift (the vertical shift from the parent function) and the asymptotes (the two vertical lines which the graph does not touch). After we have obtained these features, we plot the points on the graph and graph accordingly using the graph of the parent function.
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Organized Videos:
✅ How to Graph Trigonometric Functions
• How to Graph Trigonome...
✅ How to Graph Tangent | Learn About
• How to Graph Tangent |...
✅ How to Graph Secant | Learn About
• How to Graph Secant | ...
✅ How to Graph Sine and Cosine | Learn About
• How to Graph Sine and ...
✅ How to Graph Trigonometric Functions | Learn About
• How to Graph Trigonome...
✅ How to Graph The Sine Function
• How to Graph The Sine ...
✅ How to Graph The Cosine Function
• How to Graph The Cosin...
✅ How to Graph The Tangent Function
• How to Graph The Tange...
✅ How to Graph The Cotangent Function
• How to Graph The Cotan...
✅ How to Graph Cosecant Function
• How to Graph Cosecant ...
✅ How to Graph The Secant Function
• How to Graph The Secan...
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👨‍👩‍👧‍👧 About Me: I make short, to-the-point online math tutorials. I struggled with math growing up and have been able to use those experiences to help students improve in math through practical applications and tips. Find more here: www.freemathvideos.com/about-me/
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[@kmichaelc13]

Your videos are literally the only reason i am passing my Alg/Trig class. Thank you so much for putting out so much content and doing such a fine job explaining everything!

[@bahjaabdirazack6518]

You’re the best teacher I’ve ever seen thank you for your explanation really appreciate it❤️

[@harrisonbennett7122]

I love you way you write on the board with that pen. So smooooth

[@callmejanaa9962]

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[@SZ-rz8hj]

You have a video for basically anything I have troubles with! Thank you greatly, sir.
You have earned a sub and a like :)

[@brianmclogan]

happy to hear and happy to be able to help you out!

[@emanuelvazquez6492]

Not me not showing up to class so I'm watching video lectures 7hrs before my test

[@MathAngel369]

Thank you. I am looking for different ways to explain to my students. You explain very well.

[@shezvisual]

Thank you!!! Loving these videos!!

[@a4ha0]

thank you so much for getting straight to the point

[@reidpattis3127]

New tutor here. Appreciate your work.

[@eleni3373]

bro ur a life saver thank you so much

[@elifmutafoglu]

ahaha he said "fatter, um expanded horizantly"

[@keyframecatalyst3344]

Nah, he said "fatter or expanded horizontally", wasn't a self correction

[@muhammetyusuftanas3190]

türkmüsün

[@kawtharami2635]

thank you!!!!

[@brianmclogan]

you are very welcome!

[@primetime1149]

This channel is the reason i have a grade in math

[@domaniturner8758]

Is the end part = to pi because of the period or will I always use pi

[@daniellamcintosh9946]

Since you started at -Pi/2 wouldn’t that be an intercept and not an asymptote? Zero would be the asymptote and then Pi...then every Pi from then on? The graph now doesn’t have a phase shift, just a smaller period.

[@JEntertainment06]

The reason he started at -pi/2 is because of the phase shift

[@kunaalbhatt2246]

how do you know which way the graph is supposed to go (as in negative and positive)

[@brianmclogan]

not sure if I understand your question but I am using the parent graph and applying the transformations

[@nf3288]

I have been watching your trig playlist & I think I am a little confused, because I am watching so many videos at once. That being said, when looking to solve for the start and end I noticed for your Tangent video instead of setting the inside of parentheses to equal 0 for the start and equal pi for the end you had set the start to -pi/2 and the end pi/2 . So I am wondering why we do not do this for cotangent? ( not using -pi/2 and pi/2 for the start and end) I was thinking it has to due with solving for the parent graph when there is no phase shift, but I could be wrong.

[@brianmclogan]

it has to do with the parent graphs of cotangent and tangent. If you compare them using desmos you will see that the initial period of tangent is -pi/2 to pi/2 where cotangent is 0 to pi

[@nf3288]

Wow thank you! You are seriously the best professor ever. So to certify always remember the above statement while remembering sin, cosine and there inverses start and end are 0 to 2pi

[@hira92khan]

What is x-scale?

[@KyuuleGamingHD]

I think that graph is also equal to -2tan(x) which is easy to sketch :)

[@brianmclogan]

true

[@manatees888]

Did you set the end point equal to pi because that’s the period

[@sarahpix8774]

yes one wave, but for sin or cos it's going to be 2pi. just something you need to know for formula wise

[@slummyslumEntertainment]

so when its tan the aysatote doesn't go at the start but when its cot it dose?

[@brianmclogan]

the initial period you are talking about, yes, both of those functions continue forever so there really is not a start or end but we do use that terminology for the initial period.

[@gavinsgolfs5288]

Missing my teacher’s lectures because knee surgery thanks for the help

[@brianmclogan]

You are very welcome!!

[@samluvzcookies]

Yes ❤

[@patrickparreno7741]

Sir, is it possible that a tangent touches the 0 in graph?
Another question: Am I only Filipino here who's watching this?

[@muradhamed2960]

YOU SHOULD 100% RETURN THE STACHE, it look good on you

[@zhijin0201]

So the x-scale is the distance between x-values rite

[@brianmclogan]

the x-scale as used in this video is the distance between the x-intercepts and max and min points

[@zhijin0201]

Ok, thx sir

[@zhijin0201]

Is it only will be used in cot graph or in any graph?

[@brianmclogan]

all trigonometric graphs

[@jaspermcells9527]

what is the value of the phase shift in there?

[@snafu4714]

Must have been no shave november haha

[@brianmclogan]

nope pi

[@camp1158]

damn rip Jacob. homeboy was slacking

[@brianmclogan]

Haha yeah

[@502Bentley]

2 pi / b..... B as in butterfly........ (face palm)

[@bitchesfightingonbus]

so there was no shift?

[@brianmclogan]

pi/2 left, must have missed it