Calculus 3: Line Integrals (18 of 44) What is a Line Integral? [(y)dx+(z)dy+(x)dz] Example 6
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In this video I will find the line integral of [(y)dx+(z)dy+(x)dz] where C is the line from (2,0,0) to (3,4,5). Ex. 6
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I do NOT know why there are 14 DISLIKES, this person's videos are one of the best explanations I've ever seen: simple, clear, and fun. I'm studying a master degree in Purdue University, and I still watch his videos.
Dear Michel, you are a truly excellent professor, and you have helped me so much.
Thank you so much.
I hope I can meet you, and I give you a hug :)
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How did you know t is between 0 and 1 😢@@MichelvanBiezen
@@curtinnn3195 its given. (right side of the screen)
I say this as one who believes math is love and life and is in an electrical engineering major,Calculus 3 is truly the devil’s lettuce.
czcams.com/video/ZFpGL4fSg3o/video.html
As a Math Student, it is
Thank you for the video Prof,
for those who are confused..
you can use
r(t) = (1-t) +t
r(t) = (1-t) +
= +
therefore,
x = 2+t, y = 4t, z = 5t
How did you take t as from 0 to 1
I was studying for my multi variable calculus exam and everywhere I looked I couldn't understand. Thanks for making such videos to make us understand such topics easily
Glad you found us.
Really well explained! Most of my textbooks only give example from point (0,0,0) to (1,1,1) and so they just state x=y=z, thus dy=dx=dz (which is not clear for me), but your video really explains those well! Thank you mr Van Biezen!
How finds the limit of t
really out here saving engineer's grades, thank you
I've been confused for a long time how to parameterize, and I am so happy and relieved the way you explained it. Thank you, sir!
Glad it helped!
Thank you Sir. Great evaluation and it has been easy for me to solve another problem easily like this.
love the way u approach the probs n the perspective u give to the students, thx
Thanks for noticing. Yes, that is what we try to do.
this is one of the only videos on this topic that was helpful, thank you professor!
Glad to hear that!
The line can be written as z = 5 x -10 and y = 4 y -8 Please do an example showing how to use these equations to find the line integral.
Very well explained sir...thank you!
Awesome work. Short, simple and clear. Keep up the good work, good sir
Glad you found our videos and you find them helpful. 🙂
Super.........explained
I usually search for a difficult topic and see your video and just smile 🌟 thanks so much
Glad you found them.
Man im grateful for this video,parametric equations gave me a night mare
They can be a challenge indeed.
Is their any other method to solve this question instead taking t...???????
Why do you not use the distance formulating the derivatives. sqrt(d/dx^2 + d/dy^2 + d/dz^2). A lot of other examples do that. I don't understand why that isn't necessary here.
I ran across a change of variable to dl to terms of dx. From this I think I can get there now. Thanks!
Excellent!
we can also find the parametric equation, by writing the equation of line in a plane,
(x-x1)/x2-x1 =(y- y1)/y2-y1=(z-z1)/z2-z1 = t
Limit of t?
What if y2-y1 is coming out to b zero
A master doing what he knows best👏
Thank you. We appreciate your comment. 🙂
Many Many Thanks sir... I was finding the same class and finally got it 🎉❤
You are welcome. 🙂
Obrigado por compartilhar conhecimento conosco professor.
You are welcome. Glad you found our videos. 🙂
3:34 Why did you use 5t * 4dt + integral (t+2) 5dt
This saved my homework grade
Thankkkkkk KKK
Uuuuuuuuuuu
Very much sir!!.......thanks a lot!...
very Good solution for these type integrals
Glad you liked it.
Than you very much ❤️❤️👍👍
You are save my life in every exam week
Glad you found our videos helpful. 🙂
u r love sir, awesome concept
So nice of you
thanks a lot
Sir if we change the parameters interms of x instead of t will the answer be same taking the limit from 2 to 3
parameterization means that you replace the cartesian coordinated (x and y) by another "parameter".
How did you take limit of t from 0to1
since x = t + 2 and x varies from 2 to 3 then t must vary from 0 to 1 correspondingly (t = x - 2)
Awsm sir
for every problem limit for "t" should be taken as 0 to 1 ???????please please ans anyone
It depends on the problem and the relationship between the variables x, y, and z and the variable t. In this case there is the linear relationship and therefore the limits from 0 to 1 work.
You have helped me a lot sir with my engineering assignment but i think you have forgotten letter "a" on the word evaluate.
Thank you
Thanks aloooot♥️♥️
Glad you found our videos. 🙂
Pls explain as soon as possible
How did you take t from 0 to 1?
I was about to ask the same
@@pj4510 its the difference between 0 to 1, so t is equals to how much the change in x quantities
Thankeww sir
What will be the answer if the value of c is not given
You need to know the path along which to integrate, otherwise you cannot integrate it. It would be like telling someone to drive to a location, but you don't tell the person where that location is.
I have a question. Is the limit for line integral always 0 to 1? If so, why?
The limit is chosen to match what the value of t can be. It is often from 0 to 1, but it can be many other values depending on the relationship with the variable x, y, z
@@MichelvanBiezen Alright, sir. Thank you so much.
thanks
i think you forgot multiply the equation with the square root of the sum of squares of dx/dt, dy/dt and dz/dt
Since we are integrating along a straight line, we don't have to do that.
Find the integral curves dx/2xz = dy/2yz = dz/z-x^2-y^2
Thank you sir
Welcome
Why is t from 0 to 1???
We could have picked a different range for t, but then the the equations would have to be different as well. It just makes it easier to come up with the parametric equations.
@@MichelvanBiezen got it thanks
Thanks dr
Welcome 😊
NEATO! 😂
Mosquito!
can i know why 0
That is standard, because that makes it easier to find the parametric equations. (Converting x, y, and z in terms of t).
Hello sir can you reply me
Did you have a question?