Special Topics - GPS (7 of 100) The C/A Code (Coarse Acquisition Code)
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- čas přidán 8. 02. 2016
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In this video I will explain the C/A (Coarse Acquisition) Code and parameters of L1, frequency, and transmission rate.
Next video in this series can be seen at:
• Special Topics - GPS (...
Long live PRN !
(I never would’ve even imagined let alone hypothesized that a deterministic signal could be used to emulate noise while simultaneously creating orthogonal codes). Wow.
It is a remarkable design indeed.
Thank you for this very clear description!
Sir, Shouldn't the transmission rate be 1.023 Mbps instead of 1023 Mbps ?
Yes, there should be decimal point there. 1023 bits at a msec rate.
Awesome presentation and nice tie :)
Excellent presentation style. Can you describe in more detail how the time sent is encoded into each 1ms transmission?
Amazing.
I think the invention of the C/A code was amazing! 🙂
Please do some videos on computer programming
Ok so whats the point of looking like noise if its not an encrypted channel or a military channel? 2. So two streams of data that are exact copies are sent but with a set delay to differentiate which sattelite it was sent? Is this what I heard? I feel like there is a better way to signify what sattelite is what without the redundancy, its wasting bandwidth.....Also since radio waves are EM waves like light and I believe refraction, is basicallly a term that implies that light travels at different speeds in different mediums, so isnt there ambiguity already because of the different mediums that radio waves have to travel through to get to the receiver? I wonder how they compensated for that... Please clarify.
The point of PRN is to allow all satellites to operate on the same frequency, otherwise they would interfere. The PRNs allow all the satellite signal to coexist on the same frequency through the techniques of CDMA (code division multiple access), through the orthogonality of Gold codes.
@@irrationalpie3143 Congratulations! Your two sentences make better sense than the whole 5-minute video.
1023 MBit/s = 1023*10^6 Bit/s = 1023*10^3 Bit/ms = 1000 Messages/ms
What am I missing?
Answer: A decimal point. It should be 1.023 MBit/s
I was also lost in here but take a look at Mr Biezen reply to Sir, Shouldn't the transmission rate be 1.023 Mbps instead of 1023 Mbps ? comment on the top.
I think he made some mistakes with the metrics.