The Most Beautiful Result in Classical Mechanics

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  • čas přidán 31. 12. 2021
  • Noether's theorem says that a symmetry of a Lagrangian implies a conservation law. But to fully appreciate the connection we need to go to Hamiltonian mechanics and see how symmetries act on phase space! Get the notes for free here: courses.physicswithelliot.com...
    The connection between symmetries and conservation laws is one of the deepest relationships in physics. Noether's theorem says that for every continuous symmetry of a Lagrangian, you'll find a corresponding conserved quantity. But to fully understand the connection between the two, we need to investigate their relationship in Hamiltonian mechanics. Any function on phase space generates a "flow," similar to how the Hamiltonian generates time evolution. Then the rate of change of any other function along the flow is given by its Poisson bracket with the generator. A quantity will be conserved if and only if the flow that it generates leaves the Hamiltonian invariant!
    Get all the links here: www.physicswithelliot.com/ham...
    Watch these first!:
    - The principle of least action: • Explaining the Princip...
    - Noether's theorem: • Symmetries & Conservat...
    - Poisson brackets: • Before You Start On Qu...
    Also check out:
    A 20 minute intro to Lagrangian and Hamiltonian mechanics: • Lagrangian and Hamilto...
    The relativistic action: • The Special Relativist...
    Tutoring inquiries: www.physicswithelliot.com/tut...
    If you find the content I’m creating valuable and would like to help make it possible for me to continue sharing more, please consider supporting me! You can make a recurring contribution at / physicswithelliot , or make a one time contribution at www.physicswithelliot.com/sup.... Thank you so much!
    About physics mini lessons:
    In these intermediate-level physics lessons, I'll try to give you a self-contained introduction to some fascinating physics topics. If you're just getting started on your physics journey, you might not understand every single detail in every video---that's totally fine! What I'm really hoping is that you'll be inspired to go off and keep learning more on your own.
    About me:
    I’m Dr. Elliot Schneider. I love physics, and I want to help others learn (and learn to love) physics, too. Whether you’re a beginner just starting out with your physics studies, a more advanced student, or a lifelong learner, I hope you’ll find resources here that enable you to deepen your understanding of the laws of nature. For more cool physics stuff, visit me at www.physicswithelliot.com.
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Komentáře • 105

  • @nerdsgalore5223
    @nerdsgalore5223 Před 2 lety +13

    I've been waiting patiently for this video ever since I found your video on Poisson Brackets, great quality as always!

  • @eigenchris
    @eigenchris Před 2 lety +79

    Super great video! It directly answers some of my questions from the previous video. I've never seen the "momentum is the generator of space translations" idea for classic physics explained so plainly. Do you know if there's a way to make Hamiltonian mechanics work together with special relativity? Seems in HM time and space play fundamentally different roles. I wonder if there is a way to "rescue" HM when moving to relativity.

    • @narfwhals7843
      @narfwhals7843 Před 2 lety +5

      I had a similar question, though in regards to quantum mechanics a few weeks back. I hope nobody minds if I just copy/paste ZAP Physics' answer here. It seems like it will lead us inevitably to field theories.
      "One way to see that this can fit into special relativity is that if we just define H to be the zero-component of the 4-momentum operator, then we can see that the 4-momentum generates translations of the 4-dimensional spacetime vector with x^0 = t. However, the issue is that a lot is hidden in "H," and the form of H that we have been using is absolutely not suitable for a relativistic quantum theory. This can easily be seen since the energy of a free relativistic particle is Sqrt(p^2 c^2 + m^2 c^4) unlike our classical p^2/(2m). The square root makes things tricky since it isn't well-suited for the linear properties that we want when we upgrade the momentum to a momentum operator. There are sort of two ways around this:
      First, we can try to "square" both sides, in which case we end up with the Klein-Gordon equation. The problem with this is that it results in negative-norm states, so we can't interpret Psi^* Psi as a probability density and it is very tricky to figure out what this is actually telling us (also, it doesn't account for spin-1/2 particles)
      The other option is to use a Hamiltonian which is naturally relativistically invariant, even within Newtonian mechanics. This happens to be a property of many field equations, but the issue here is that we have to replace our position and momentum operators with corresponding field operators. This is what is known as canonical quantization. "

    • @RizkyMaulanaNugraha
      @RizkyMaulanaNugraha Před 2 lety +3

      @eigenchris you both should do collab sometimes :D

    • @alphalunamare
      @alphalunamare Před 2 lety

      @@narfwhals7843 Doesn't 'Canonical' just mean 'going by the book'? ie 'follow the rules'. If it works then don't doubt it sort of thing? No actual explanation for why it works however.

    • @narfwhals7843
      @narfwhals7843 Před 2 lety +2

      @@alphalunamare Canonical in this context refers to canonical coordinates. en.wikipedia.org/wiki/Canonical_coordinates
      I'm not sure why they're called that. Possibly because the canonical transformations leave the hamiltonian equations unchanged or "as written".

    • @alphalunamare
      @alphalunamare Před 2 lety

      @@narfwhals7843 I don't know why people are allowed to post such impenetrable gibberish on Wiki just because it is correct. Surely knowledge is about understanding? As such the referenced page totally fails. I could dig into it and take it apart but, to be honest, I can't be arsed. There is nothing in Mathematics that a child can not understand, that it is disguised so is a poor reflection on those professing to understand things in the first place. Wiki is a piss poor resource.

  • @user-ws6ik1ch5c
    @user-ws6ik1ch5c Před 2 lety +9

    We hail you as an exceptional physics instructor. Thank you so much for the amazing work!

  • @edzielinski
    @edzielinski Před 2 měsíci

    Fantastic. The explanation about the flow in the phase space was a revelation to me on how to think about this. Thanks!

  • @johnchessant3012
    @johnchessant3012 Před 2 lety +3

    Great video! I've read about Noether's theorem before but this really made everything click for me

  • @bosonh7723
    @bosonh7723 Před 2 lety +4

    You are a legend mate, thank you so much for such a lovely simplified introduction to otherwise profoundly deep concepts

  • @jms547
    @jms547 Před 2 lety +7

    This video is great, and landed in my feed just in time for me to bring it to a classical mechanics reading group that's starting this year! I'd love to see your explanation of Lie algebras, symmetry groups, and representations - that's exactly where my current understanding of mechanics dries up!

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety +2

      So glad you liked it Jonathan! Thanks for sharing it with your friends!

    • @jms547
      @jms547 Před 2 lety

      Not at all, thanks for making great videos. Incidentally, I've just discovered Lax's equation, which has opened up a whole new vista on the Poisson bracket/commutator structure of mechanics. I'd love to see how they all relate to each other within the Lie algebra/group context, if you ever make that video!

  • @khandakerahmed7408
    @khandakerahmed7408 Před 2 lety +1

    Please keep up and add more and more. Please do not stop.

  • @rui-anchang139
    @rui-anchang139 Před rokem

    Very great video!!!! I have never seen such a clear explanation of the relation between symmetry and conservation law.

  • @charlesgantz5865
    @charlesgantz5865 Před 2 lety +1

    Very nice start to the New Year.

  • @General12th
    @General12th Před 2 lety +7

    I like it! One component of this is how we can take advantage of the fact that there's exactly one number N such that N = -N, and that just happens to be what these brackets ought to resolve to if there's a symmetry or a conserved quantity we can take advantage of.
    The N stands for Nifty. :)

  • @avnishhhhh
    @avnishhhhh Před 2 lety +7

    Your videos are really helpful, keep going 😍

  • @bartpastoor1028
    @bartpastoor1028 Před 2 lety +2

    It’s late here now and I will will revisit this video to get a better grasp on me studying the Lie Group /Lie Algebra within Robinson “Standard Model and Particle Physics”.
    Keep up the good work!

  • @deepakjanardhanan7394
    @deepakjanardhanan7394 Před 2 lety +3

    Great, really great. High quality content. Superb..... Expecting more and more.....

  • @hishan.farfan
    @hishan.farfan Před rokem

    new favorite channel!! 😁

  • @dennylane2010
    @dennylane2010 Před 2 lety

    My professors have the talent of making simple things look so complicated. Yours is the reversed. You just summarized the missing connection that I am looking for (for years) between symmetry and conservation laws in classical mechanics. Thank you very much! Awesome explanation!

  • @alphalunamare
    @alphalunamare Před 2 lety +1

    I understood every sentence but when I put them together my head fell off! This is fascinating stuff :-)

  • @eustacenjeru7225
    @eustacenjeru7225 Před 9 měsíci

    Nice and clear explanation

  • @mdabdulquader8995
    @mdabdulquader8995 Před 2 lety +1

    Your videos are really outstanding. Please do more

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety

      Thanks Abdul!

    • @mdabdulquader8995
      @mdabdulquader8995 Před 2 lety

      @@PhysicswithElliot If possible, Please make a complete playlist of classical mechanics & classical electrodynamics.

  • @kquat7899
    @kquat7899 Před 2 lety

    Fantastic series.

  • @canyadigit6274
    @canyadigit6274 Před 2 lety +3

    Dude…this just opened my mind!
    I’ve studied generators and translations in the context of quantum mechanics, representation theory, classical mech, and quantum field theory-it had always been something like e^(theta)X where X “generated” the group (which made sense, since it could be expanded as a Taylor series and X more or less acts like the generator of group G where G is a cyclic group. But this new intuition on generators makes more physical sense! How can we tie these 2 seemingly different notions of generators? One notion because an exponent that generates a group (G= e^(theta)X), and the other being the one you defined in this video?

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety +3

      In the flow equation dx/\lambda = {x, G} = - {G, x}, the object {G, _} is a derivative operator D_G, and the solution to this equation can be written x(\lambda) = e^(-\lambda D_G ) x.
      For example {p, _} = -d/dx is minus the x derivative of whatever goes in the second slot. Then the solution of the flow equation dx/\lambda = 1 is x(\lambda) = e^(\lambda d/dx ) x = (1 + \lambda d/dx +1/2 \lambda^2 d^2/dx^2+...)x = x + \lambda.
      In quantum mechanics, {p, f} = -df/dx becomes [p, f] = -i\hbar df/dx

  • @mplaw77
    @mplaw77 Před 2 lety +1

    Well done, I learned something today!

  • @kid0ftheOldblock
    @kid0ftheOldblock Před 2 lety +1

    Great video, made me want to reopen my group theory in physics book i was reading

  • @gowrissshanker9109
    @gowrissshanker9109 Před rokem

    Hlo Elliot, How come the position and momentum are independent variables? Consider SHM Hamiltonian when we change position , Momentum changes right?
    Both are related to each other right?
    Thank you

  • @lazzatv
    @lazzatv Před 2 lety

    Check Michael Penn video playlist on Differential Forms for a general mathematical formalism. Basically a Poisson bracket is a differential 2-form determinant of a quantity parametrized in (x,p) phase space which appears in the calculation of the integral of that quantity in phase space.

  • @aadityapratap007
    @aadityapratap007 Před rokem

    Great video

  • @nice3294
    @nice3294 Před 2 lety +2

    This is an amazing vid

  • @devamjani8041
    @devamjani8041 Před 2 lety +1

    In my opinion, Noether's theorem is the single most impactful and important result in all of physics. The entire standard model of particle physics builds upon it and also the entire mathematical physics. This theorems are what founded mathematical physics.

  • @marcovillalobos5177
    @marcovillalobos5177 Před 2 lety +1

    Wonderful video❤️

  • @ARAVINDKUMAR-ug7gt
    @ARAVINDKUMAR-ug7gt Před 2 lety

    I really love your video sir ❤️❤️❤️

  • @DeepSeeker2809
    @DeepSeeker2809 Před 2 lety +1

    You seem to be good at explaining the math of physics and its symmetries.. It would be great if you can squeeze in a series about group & representation theory of particles..!! Great video btw!

    • @alphalunamare
      @alphalunamare Před 2 lety

      Group theory is beautiful in of itself. One always worries about its usurpation by physicists. Not that I am being picky, I have just never seen a decent explanation for the ways in which they slam group structures together as if there is some underlaying miracle.

    • @alphalunamare
      @alphalunamare Před 2 lety

      Years ago' I asked Proff Weigold (Cardiff) what it was all about. He said that they were 'near' to understanding every possible group structure and I pondered why the effort. He just smiled at me ... he was a lovely Man.

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety

      Will hopefully talk more about it in the future!

  • @hundhund489
    @hundhund489 Před 2 lety +2

    Holy shit, thanks!

  • @andrasgilicz8153
    @andrasgilicz8153 Před 2 lety

    Great video :-) How you made the animation?

  • @res0nanc320
    @res0nanc320 Před 2 lety

    I love the style of these videos. Would you mind sharing what software you use to produce them?

  • @koenth2359
    @koenth2359 Před 2 lety +1

    Nice vid Eliot, very neat!

  • @DeepLyricist
    @DeepLyricist Před 2 lety +2

    Not sure how you calculate dP/dLambda using "the chosen G" since real G's are supposed to be silent like lasagna.

  • @ChristAliveForevermore

    Emmy Noether is an un-sung genius of a very high calibre.

  • @MrRyanroberson1
    @MrRyanroberson1 Před 2 lety

    Since continuous symmetries lead to conservation laws, would periodic yet discontinuous symmetries lead to periodic conservation laws? Such as a phase angle of something strangely dictating some other event

  • @samicalvo4560
    @samicalvo4560 Před 2 lety

    Hello Elliot, I've already subscribed to your web to get the notes but I haven't received any email from you.

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety

      Hi Sami, could it have gone in your spam folder? If you don't find it just send me an email (elliot@physicswithelliot.com)

  • @dlrmfemilianolako8
    @dlrmfemilianolako8 Před 2 lety +3

    Thank you so much for your videos .
    Please can you make videos about dark matter and energy ?

  • @sidkt7468
    @sidkt7468 Před 2 lety

    So can you do this with any Q, i.e. say that if dx/dt = 0 then {x,H} = 0 so {H, x} = 0 (and by solving the equations for the flow you get that space is the generator for momentum translations). Then, "position is conserved if there is an invariance under momentum translations" because that doesn't seem correct.

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety

      {x, H} won't typically vanish. For a typical Hamiltonian H=p^2/2m + U(x) you'll get {x, H} = p/m.

    • @sidkt7468
      @sidkt7468 Před 2 lety

      @@PhysicswithElliot but isn't that also the case for {p, H} as it would yield -dU/dx for a typical Hamiltonian H = p^2/2m + U(x)

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety

      @@sidkt7468 That's right---that's why I mentioned that for a single particle the momentum would only be conserved if it's free, meaning U = 0 (or constant). But when you have multiple particles in an isolated system, the total momentum will be conserved, and the symmetry corresponds to picking up the whole system and sliding everything over

    • @sidkt7468
      @sidkt7468 Před 2 lety

      @@PhysicswithElliot oh that makes sense now, I didn't quite understand the meaning of it being free at the beginning.

  • @mimzim7141
    @mimzim7141 Před 2 lety

    Does one get conservation of charge and of other quantities with the same symmetry arguments?

  • @meenalimbu2553
    @meenalimbu2553 Před rokem +2

    ELLIOT WHY THE FUCK DIDNT YOU START A PHYSICS CZcams CHANNEL BACK IN 2010 WHEN I STARTED MY PHYSICS DEGREE. 😭😭😭😭😭😭

  • @General12th
    @General12th Před 2 lety +1

    I want to see videos about Lie algebras down the line.

  • @maurocruz1824
    @maurocruz1824 Před 2 lety

    4:05

  • @nassersaleh8327
    @nassersaleh8327 Před měsícem

    I'm very disappointed that you didn't turn on the subtitle function, so we non-English speakers lost important information

  • @physicshuman9808
    @physicshuman9808 Před 2 lety

    6:43
    L is angular momentum and P is linear momentum
    L causes rotation and P causes space translation

  • @r3lativ
    @r3lativ Před 2 lety

    Interesting video, as usual. But there are some issues:
    - Not everything that commutes with H is a conserved quantity. For instance, E^2 - p^2 is not a conserved quantity. He says that if dQ/dt = 0, then Q is conserved. But not necessarily. For instance, for a free particle, v is constant, dv/dt = 0, but v is not a conserved quantity, mv is. So, how exactly do we define the idea of a "conserved quantity"?
    - He says that every symmetry has a corresponding conserved quantity. Is this true? What's the conserved quantity corresponding to the Galileo or Lorentz transformations?

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety +1

      A conserved quantity Q(x(t),p(t),t) is a function that's constant in time, dQ/dt = 0. When Q(x(t),p(t)) doesn't depend explicitly on time, its rate of change is dQ/dt = {Q, H}. More generally, this becomes dQ/dt = {Q,H} + \partial Q/\partial t when Q does have explicit time dependence.
      The conserved quantity for a Galilean boost is K = p t - m x. It explicitly depends on time, so it doesn't commute with the Hamiltonian. Instead, for a free particle, dK/dt = {K, H} + \partial K/\partial t = -m p/m +p = 0.

  • @rodrigoappendino
    @rodrigoappendino Před 2 lety

    I read in my book the demonstration, involving variatioal calculus, which is a lot more complicated. This would be easier.

  • @chadgregory9037
    @chadgregory9037 Před 2 lety

    are these "flows" basically just principle fibres from bundles

    • @chadgregory9037
      @chadgregory9037 Před 2 lety

      I know this all ties into HJB equation too and stochastic optimal control

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety

      They're the integral curves of vector fields on phase space

  • @mathadventuress
    @mathadventuress Před 2 lety +2

    I’m not at this level yet but I want to be 😫

  • @user-xt8to6yi8n
    @user-xt8to6yi8n Před 2 lety

    Thanks for the video! Is anyone aware of the proof, that there are no more conservation laws (energy, momentum, angular momentum, parity, charge, center-of-momentum velocity)? There are a lot of different symmetries in various less general systems, of course. For example, there is a discrete translational symmetry in crystals, which under the condition of the incident particles' momentum conservation leads to many beautiful results for elastic scattering. And it is also not exactly the ordinary translational symmetry, of course.

    • @PhysicswithElliot
      @PhysicswithElliot  Před 2 lety +1

      The set of symmetries depends on the system you're looking at. The Hamiltonian for a particle in a 1/r gravitational potential for example has a very non-obvious symmetry that leads to the conservation of the Runge-Lenz vector: czcams.com/video/KOek-B3Rvmg/video.html

  • @ginaluzsalcedoalarcon4779

    No subtitles 😭

  • @user-sl6gn1ss8p
    @user-sl6gn1ss8p Před 2 lety

    I like how well this seems to generalize to the idea that you could define "conservation in space", for example, in the same way as the usual "conservation [in time]", with the same relationship to symmetries - the concept that symmetries and conservation are linked is deeper than just the sense we usually see

  • @ventriloquistmagician4735

    Change the subtitles language, it's trying to translate from Dutch.

  • @drbonesshow1
    @drbonesshow1 Před 2 lety

    The Most Beautiful Result in Classical Mechanics is better when explained to a pretty girl sitting across from you. At least, for Einstein and myself the physics professor.

  • @Aragmatiki
    @Aragmatiki Před 2 lety

  • @eduardocubells957
    @eduardocubells957 Před 2 lety

    Da

  • @harshkumarjha5731
    @harshkumarjha5731 Před 2 lety +2

    First like 😀