Divisibility rule for prime numbers | Divisibility rule of 13, 17, 29, 53, 89 | Zero Math
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- čas přidán 12. 09. 2024
- Divisibility rule for prime numbers | Divisibility rule of 13, 17, 29, 53, 89 | divisibility test tricks
About Video :
In this video we will learn how to make the divisibility rule for any prime number. on you tube there are many videos for the divisibility rule, where you have to remember the rule which may cause issue if you do not remember properly.
We will explain how to build the rule for any number, so you really do not need to mug up the rules.
You will learn :
- What is divisibility rule
- Divisibility rule of prime number
- How to build the divisibility rule
- Divisibility rule of 13
- Divisibility rule of 17
- Divisibility rule of 29
- Divisibility rule of 53
- Divisibility rule of 89
- Divisibility rule of 23
- Divisibility rule of 79
- Divisibility rule of 11
- Divisibility rule of 9
- Divisibility rule of 7
#Divisibility #Rule #Prime
You Can visit the Zero Math Facebook page on below link :
/ thezeromath
This method is useful in many math competitive exam like
- Math Olympiad
- CAT
- GMAT
- ssc cgl
- CPO
- CHSL
- RAILWAY Exam
- IBPS Clark
- Banking exam
- SBI clark exam
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Really thank you sir.. literally I was writing all test divisibility rule bt then I found ur video ..thank you 👍
Welcome dear.
Sir it is totally agreed that we are getting to know that whether the particular prime number is divisible by some big number or not..... I genuinely appreciate your trick.... thank you so much for sharing your knowledge with us..... BUT MY QUESTION IS THAT, HOW TO FIND THAT HOW MANY TIMES THAT PARTICULAR PRIME NUMBER IS DIVISIBLE BY THAT BIG NUMBER ? (Such a question asked in my SSC exams several of times that's why I really need your reply)🙏
Its amazing.. no need to remember the formula...
Thank you
even more amazing is this cute trick... when trying to divide some number N by all these numbers ending in 9 eg 19, 29 39 49 59 69 79 89< here's the divisibility rule. Just add one (+1) to the number in the Tens column of of the divisor. e.g., dividing by 29. add one to the 2 in the tens column and you get three. Three is now the factor to multiply the truncated number in the ones column of N (which is the Number that your trying to divide by 29), so now after you multiply the truncated number by three (3), you're going to add it to the rest of N that's left over after truncating the ones column (in other words, the digit in old tens column of N is now the new ones column of N and so N is now significantly smaller than before). If the new N with the added factor of the truncated column is divisible by 29, you're done!! If the Number is still too large to figure out easily, just repeat the process of truncating, multiply and adding again until it's obvious that its divisible evenly or not.
Respected sir kindly provide video for divisible by 3 digit number
This is really unique video. Loving it.
Glad you liked it!
sir how can we do divisibility of 41...plz do a video on that
your teaching so simple way thank you so much......
Sir I watched many video but this video help me lots to clear concept
You are welcome dear
What about prime numbers above 100, that is more than 3 digits?
Thankyouu sir it is quite helpful i always find it difficult to check divisibility of prime number
Super sir👌
This is a good method, though one could shorten it to one formula, hence obtaining one formula that can generate a divisibility test for any number ending with 1,3,7,9, though I'd also like to know the origin of this method,i.e, its deriviation and proof
Thanks dear. Pleae help us to sociliaze this method with the needful audience 🙏
❤this video is very useful 🙂
Super. Really helpfull
This is my module thx
Thank a lot
I got my doubt clear
❤️ 👌🏻👍🏻thanks sir
Does it give right remainders
What do you call this formula?
Why we use subtraction for 17
Good method
13
-30
17??????
These rules are for small children.
Tell for competition exams.
How to check divisibility of 103,105 need help.
we know that 412 / 103 = 4. Now let us check the divisibility of 103.
41 2 (2*.72 = 144)
- 144
41 - 144 = 103 Hence it is divisible
One more example;
1266 9(9*72=648)
-648
618 (618 is divisible by 103 which is 103*6 = 618)
Divisibility check of 105. for 2415
241 5
- 10 (5*2)
23 1 (1*2)
- 2
2 1
-2
0
The final answer must be either multiples of 105 or Zero.
Here we get Zero.
Hence divisible by 105.
✅
Rule for 19?
+2 for the last digit
You are worst in using white board.