The Mathematics of Cryptography

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  • čas přidán 20. 01. 2019
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Komentáře • 224

  • @zachstar
    @zachstar  Před 5 lety +89

    Hope you guys enjoy! And here's part 2: czcams.com/video/xmwxDHX6xUc/video.html

    • @PKPS01238
      @PKPS01238 Před 5 lety +1

      MajorPrep Hey MajorPrep, thanks for creating these videos, I’m a freshman CS major and am interested in cryptography, so these videos really help!

    • @dancepants3399
      @dancepants3399 Před 5 lety

      i read a really good book called the code book all about cryptography. it also covers ciphers like rsa... you should read it

    • @Fire_techniques
      @Fire_techniques Před 2 lety +1

      Sir .. group theory in cryptography ma bi ya example LA saktay

    • @chinmayrath8494
      @chinmayrath8494 Před rokem

      We did, thanks a lot

    • @johnsantavicca5016
      @johnsantavicca5016 Před 2 měsíci

      Do you get paid in cash to secretly do peoples homework? That is a tricky subject because I wouldn't learn. It's actually more like you get paid to tutor. Extra credit

  • @dragonrykr
    @dragonrykr Před 5 lety +751

    Khoor friends

    • @precumming
      @precumming Před 4 lety +21

      iulhqgv*

    • @kevin780313
      @kevin780313 Před 4 lety +21

      khoor zruog!

    • @xofyu
      @xofyu Před 4 lety +7

      d564145aa1bae0255dc21dacfe33b258370b3c7cec44956af2d1366f5025a5ad

    • @evm6177
      @evm6177 Před 3 lety +3

      Scifi talks about transferring thoughts through something like brain waves. Crypto to me is a step in the direction of future communication as it evolves. 🍷👄💬

    • @xxdxx3776
      @xxdxx3776 Před 3 lety +1

      @@xofyu "friend" in SHA256

  • @jordancarpenter676
    @jordancarpenter676 Před 4 lety +84

    Simon Singh wrote a famous book detailing all of this in 1999 called “The Code Book”. With an impressive challenge of 10 ciphers to beat at the end that had a monetary prize. It was fascinating.

    • @jasonbates9906
      @jasonbates9906 Před 2 lety +3

      Read The Code Book as a kid. Loved it.

    • @jordancarpenter676
      @jordancarpenter676 Před rokem

      @God Slayer I don’t know what this means. Sanskrit name so what?

    • @jordancarpenter676
      @jordancarpenter676 Před rokem

      @God Slayer that’s not even punny. You’ve spoke a lot without saying anything.

  • @channelofoxford2131
    @channelofoxford2131 Před 5 lety +110

    This is one of the coolest math CZcams videos that I'v seen.

  • @MrTokyo-wc6xr
    @MrTokyo-wc6xr Před 5 lety +35

    I was half way through then I released I hadn't yet subscribed, my bad dude. Love your channel

  • @majaano
    @majaano Před 4 lety +6

    Perfect in terms of detail, depth and presentation, thank you. On a level that I can just about grasp most of it, but not all of it without stopping and perhaps writting stuff down. I wish more topics were covered on CZcams on such a level.

  • @haseebtubing
    @haseebtubing Před 4 lety +65

    Dude, you smart. More power to you.

    • @theulmitter5725
      @theulmitter5725 Před 3 lety

      That's what I think in most of these videos, I keep watching even if I don't understand anything

    • @mk_4567
      @mk_4567 Před 3 lety

      @Benjamin 😭😭 please don't say that, I can't understand. Can you help me?

    • @mk_4567
      @mk_4567 Před 3 lety

      @Benjamin after the mod part it is complicated for me

  • @sahilkthakur
    @sahilkthakur Před 5 lety +72

    Because of you I'm learning mathematics with curiosity and meaning.👍👍👍

  • @Engel-ol5rm
    @Engel-ol5rm Před 4 lety +13

    Your channel was one of the factors in me wanting to study mathematics

  • @pravatyadav3623
    @pravatyadav3623 Před 5 lety +27

    Ur content are always original and exciting....makes me want to rewatch it time and again

  • @behnamasid
    @behnamasid Před 3 lety +1

    You explaining things could not get any simpler. I'm really happy to be a subscriber to your channel

  • @computeon727
    @computeon727 Před 5 lety +142

    You ever think about changing the name of your channel? You are doing lots of new amazing videos that are more geared towards the applications of mathematics to STEM fields, as opposed to talking about college majors as you did more frequently in the past. I like this transition of content in your channel as it attracts a wider audience instead of just college students. You could grow huge if your channel focused on these types of videos. Your college major videos were great and informative in the past, don't get me wrong, but now you've established a theme of mathematical applications that make your channel really unique and interesting!

    • @zachstar
      @zachstar  Před 5 lety +40

      I have been thinking about this! I haven't really thought about changing the name because there are still majors I want to talk about but I have really enjoyed showing these applications of math to STEM fields and they seem to be received pretty well. I think I'm still just playing around with what people enjoy and what I like making so we will see what happens moving forward. Definitely a positive that these apply to a wider audience though which is something I have to think about. Thanks for the comment though and hope you continue to watch!

    • @jackmaison4209
      @jackmaison4209 Před 4 lety +8

      Look how times have changed.

    • @iampaapa
      @iampaapa Před 3 lety +4

      Now, I really want to know what his old name was 😂😂😂

    • @bigbrothersinnerparty297
      @bigbrothersinnerparty297 Před 3 lety

      Paapa Kwesi Quansah it is in his channel description

    • @bigbrothersinnerparty297
      @bigbrothersinnerparty297 Před 3 lety

      Paapa Kwesi Quansah it’s MajorPrep

  • @sharathkumar8422
    @sharathkumar8422 Před 5 lety +2

    I'm about to go to sleep and this is the perfect way to start a good night's sleep. Very good presentation. Keep it up.

  • @ilyaaslunat8382
    @ilyaaslunat8382 Před 5 lety +66

    This is a really good video. I’m doing coding and cryptography as a module in my final year maths, and your covering the main points 😁😁😁

    • @enjoyablehistory5958
      @enjoyablehistory5958 Před 2 lety +1

      Is enjoyable to study cryptography

    • @oyaoya2468
      @oyaoya2468 Před rokem +1

      I'm currently studying abstract algrebra (group theory,ring theory,...) anh yeah, it along with number theory are really useful stuff for cryptography

  • @perx5171
    @perx5171 Před 3 lety

    Best video I have come across so far. Thank you for sharing!

  • @91722854
    @91722854 Před 5 lety +27

    I would like to recommend "The code book" written by Simon Singh

    • @glokta1
      @glokta1 Před 4 lety +2

      +1. Amazing book

  • @NovaAnimations
    @NovaAnimations Před 4 lety +18

    Honestly I really don't like doing math but this was so much fun to learn

  • @chinmayrath8494
    @chinmayrath8494 Před rokem

    thank you, i finally understand what congruence is about now ! The video until the end, absolutely great !!

  • @worldedit8784
    @worldedit8784 Před 5 lety +1

    Thanks for this video. I wanted to learn more about this before desided to do it in university.

  • @loserkingclinton9244
    @loserkingclinton9244 Před 2 lety

    100 youtube tutorials later I finally understood modulo arithmetic!Dude you a genius.

  • @arunmalik790
    @arunmalik790 Před rokem

    BEST VIDEO THAT EXPLAINED THIS MATH PROPERLY

  • @dannys2817
    @dannys2817 Před 5 lety +2

    Clear explanation, thank you

  • @turtlemun
    @turtlemun Před rokem +1

    The beginning, one after the caesar cipher, is actually called the Vigenerre cipher! It's much easier to decode with an alphabet grid- you use one side as the ciphertext letters, and the other for the Key phrase. Match each letter in the ciphertext to its key counterpart and bam. Same deal for encryption.

  • @elsie1379
    @elsie1379 Před 3 lety

    This will help me with my cryptology paper for my number theory class! Thanks!

  • @leosacademy
    @leosacademy Před 3 lety

    Wow!!! very good video. I have learned many things. Thank you Zach Star

  • @aiden359
    @aiden359 Před 5 lety

    Information from your channel is so valuable

  • @vinnaroonie
    @vinnaroonie Před 5 lety +4

    Great vid! Can you make a video on combinatorics? Taking it rn in undergrad and it’s chipping way at my life🙃😂

  • @Nocbsocbsox
    @Nocbsocbsox Před 4 lety +5

    Today I learned that literally every number you can possibly think of had at least one thing in common.
    Relatively prime.

  • @sidstam
    @sidstam Před 5 lety

    Very impressive presentation and explanations.

  • @raulmogos1282
    @raulmogos1282 Před 5 lety +1

    I really enjoy your videos! Please make a video on computational science and engineering (master specialisation). :)

  • @johnadriandodge
    @johnadriandodge Před 10 měsíci

    Shalom
    Your clones caught me off guard.
    Your explanations are splendid.
    Thank you for sharing.

  • @moustafaabousalem1411
    @moustafaabousalem1411 Před 5 měsíci

    Definitely earned a sub. You really helped me.

  • @HandsomEnchilada
    @HandsomEnchilada Před 4 lety +1

    never knew this existed .But im glad i found it .

  • @simonmultiverse6349
    @simonmultiverse6349 Před 2 lety +1

    The problem of passing notes in class is NOT ONLY that of secrecy. If someone knows that you have passed a note, even if they don't know what's in the note, you are STILL in trouble. Therefore, you have to (1) conceal the _contents_ of the note; (2) conceal the very _existence_ of the note.

  • @0ijm3409fiwrekj
    @0ijm3409fiwrekj Před rokem +1

    Cryptography was my second favourite module in my Maths degree.... only behind Number Theory ;)

  • @purnendushukla8463
    @purnendushukla8463 Před 2 lety +2

    It seems like you are highly interested in cryptography as i can see an elelment of it in every of you video.
    Btw well laid and explained 😌

  • @ravirajsinhzala9535
    @ravirajsinhzala9535 Před 5 lety

    That was amazing🤗🤗

  • @ericj4094
    @ericj4094 Před 5 lety

    More common (civilians) AES-128 symmetric key encryption with RSA-2048 as key exchange mechanism (military) AES-192 or AES-256 symmetric key encryption with RSA-4096 as key exchange mechanism

  • @vlhz69420
    @vlhz69420 Před 4 lety +1

    Imitation Game is the best movie on this topic till now

  • @cubicardi8011
    @cubicardi8011 Před 5 lety +2

    8:42 fermat reference right here

  • @AjayKumar-fd9mv
    @AjayKumar-fd9mv Před 3 lety +2

    It's super easy to understand when you explain to us, Thanks , but how someone had to think about it and invent it for first time?

  • @henribebo
    @henribebo Před 2 lety

    Dude i love u

  • @SBVCP
    @SBVCP Před 5 lety +2

    I laughed because the first time i tried to make a cesa cipher i ended up doing a variation of vigenere lol (it has a few complicatiosn but not that many)

  • @samuelfey4924
    @samuelfey4924 Před 5 lety +1

    I love computer security I wish I was a super hacker but I ended working as a game developer I hope some day I get into computer security

  • @johnadriandodge
    @johnadriandodge Před 10 měsíci

    If you have not seen these movies, you might want to look into them!
    A Beautiful Mind, Good Will Hunting, The Imitation Game, Stand and Deliver and The Theory of Everything

  • @jaspaw.5473
    @jaspaw.5473 Před 5 lety +2

    Hey, could you please do a video on Computational mathematics? Am taking it I would really appreciate if I could get your point of view about the program. Thank you in advance!

  • @mohammedaasri2774
    @mohammedaasri2774 Před 4 lety

    Thanks

  • @hklausen
    @hklausen Před 4 lety

    I like your channel :-)

  • @SevenDeMagnus
    @SevenDeMagnus Před 4 lety

    So cool.

  • @SAM-ft9jd
    @SAM-ft9jd Před 5 lety +12

    Your videos are truly stunning. The production is top tier considering the content you're putting out there. If anything you truly deserve more subs. Hopefully I can gain you a few by sharing your content on reddit? Eitherway just want to say keep this up, hope you don't ever doubt yourself or your content.

    • @zachstar
      @zachstar  Před 5 lety +2

      Thanks so much! And yes please share the videos wherever you can, really appreciate it.

    • @SAM-ft9jd
      @SAM-ft9jd Před 5 lety

      @@zachstar Btw think it's possible you could do a few videos on information technology and mechatronics?

    • @zachstar
      @zachstar  Před 5 lety +1

      Mechatronics is definitely one I still need to get which I've been really slow to do. But I promise I will!

  • @sidneylc281
    @sidneylc281 Před 5 lety +3

    Are there some books you can recommend about the math in cryptography? I know the basic stuff like theory and application by using libraries but I want to understand it deeply. Do you have a series or books ordered by difficulty? I know a book can't explain all about cryptography but you that explains must know a path I can take to master the math in cryptography. And also, awesome video, nir easy nir hard.

    • @zachstar
      @zachstar  Před 5 lety +2

      'The code book' is a really good one to get started with cryptography. Then I personally haven't gone through a specific cryptography textbook before but this reddit post should help. From a mathematics side number theory is definitely a good place to start though.
      www.reddit.com/r/crypto/comments/287y7j/best_intro_book_to_cryptography/

  • @hannahtang5018
    @hannahtang5018 Před 5 lety

    LOVE your videos!!! Numberphile is too hard for a nub like me

  • @ahamadxaveel1383
    @ahamadxaveel1383 Před 5 lety

    Awesome

  • @johnohm8067
    @johnohm8067 Před 4 lety

    you have to intialize a handshake and an ever changing multi algorithm encryption

  • @souling8773
    @souling8773 Před 4 lety +1

    I don't understand euler's theorem at 11:45 . Can someone please explain or give me the name of the theorem?

  • @kittymeow3298
    @kittymeow3298 Před 4 lety

    An eighth grader learning cryptography.... Juuuuuust great

  • @purityvsprofanity2962
    @purityvsprofanity2962 Před 2 lety +1

    Still doing my IGCSEs and this isn't part of the syllabus, but why not learn it anyway??!! thanks for the video

  • @alperenorsdemir4164
    @alperenorsdemir4164 Před rokem

    I didn't know this guy is actually teaching technical stuff.

  • @tuesdaymartesvr1942
    @tuesdaymartesvr1942 Před 2 lety

    You needed to get nord von to sponsor this omg

  • @aanya7607
    @aanya7607 Před 2 lety

    I LIKE YOUR VIDEOS THEY ARE AMAZING
    LOVE FROM INDIA

  • @nitamishra9645
    @nitamishra9645 Před 2 lety

    But at 7:11 shouldnt you also divide the mod4 by 2 which would equal to 5 = 3(mod 2) which would be correct

  • @AkashDeep-bu9fu
    @AkashDeep-bu9fu Před 4 lety +1

    Can we say relatively prime numbers as coprime numbers?

  • @brandonfox9618
    @brandonfox9618 Před 3 lety

    10 congruent to 6 mod 4 isn't really the best way to put it because it contradicts part of the "Division Algorithm". Specifically, the part where it states that integer remainder "r" is greater than or equal 0 and less than integer "n" (0 < or = 6 not < 4).
    THIS IS JUST WHAT I HAD LEARNED FROM CONGRUENCE MODULO "n"!

  • @MatiGebreyehans
    @MatiGebreyehans Před 3 měsíci

    What if we use algebric equation like y=4x+4 0r y=4y+4 is it too easy for computers to crack

  • @W1LDGAMING.
    @W1LDGAMING. Před 4 lety

    Can we have some more videos on cryptography

  • @vadimneonov6172
    @vadimneonov6172 Před rokem

    I don't think at 9:47 'x' is any integer, because it doesn't work for 'x' that is divisible by 5. Please correct if i am mistaken.

  • @zajec11
    @zajec11 Před 4 lety

    Understanding 7:25 is the most important part, and without understanding that, you won't fully understand the rest

  • @SubduedRadical
    @SubduedRadical Před 3 lety

    a =- b (mod c) means "a has a remainder of b when divided by c", then?
    Seems that'd be an easier way to say it...

  • @jonelong4020
    @jonelong4020 Před 5 lety +28

    I have one idk what it is called
    IETRNCUOTOMOHSEM
    So, count all the letters which is 16.
    Square root of 16 is 4.
    Write the letters in a square form
    I E T R
    N C U O
    T O MO
    H S E M
    Read it downwards
    'In the costume room'

    • @xavierlondres6519
      @xavierlondres6519 Před 5 lety +4

      hi mate its called ceazar's box. Correct me if im wrong mate.

    • @HandsomEnchilada
      @HandsomEnchilada Před 4 lety

      so written in asian scrolls style?

    • @SunSunSunn
      @SunSunSunn Před 4 lety +1

      @@HandsomEnchilada Why did you refer to scrolls from Asia? All scrolls work that way??

    • @HandsomEnchilada
      @HandsomEnchilada Před 4 lety

      @@SunSunSunn sorry don't even understand what i typed .I guess I was watching CZcams during my CZcams rabbit hole journey and forgot . I possibly was referring to "Asian scrolls "because from what I've seen in movies, scrolls often appear to be written verticaly

    • @RifqiPriyo
      @RifqiPriyo Před 3 lety

      It looks like columnar transposition cipher.

  • @neelamsuryawanshi1137
    @neelamsuryawanshi1137 Před 5 lety

    How do you explain someone that cryptography is use of mathematics majorprep?

  • @awkweird_panda
    @awkweird_panda Před 5 lety +6

    At 10:46 You should have said "how many positive integers....". You got me guessing infinity😂😂

    • @zachstar
      @zachstar  Před 5 lety

      haha my bad! I did so many takes where I said 'numbers' instead of 'integers' and I was so focused on not messing that up.

    • @awkweird_panda
      @awkweird_panda Před 5 lety

      @@zachstar Haha. I really appreciate the Hardwork you put in.

  • @LiteraIIy_Nobody
    @LiteraIIy_Nobody Před 4 měsíci +1

    1:29
    What if the other person thinks you are trying to say, "You can't rust me" instead of "You can trust me"?

  • @kd8691
    @kd8691 Před 3 lety

    In the example at 7 minutes 10=6 (mod 4) >> 5=3(mod 4) why would you not perform the same operation on the mod? If you did would it not be correct? 5=3(mod 2)

  • @richkillertsm6664
    @richkillertsm6664 Před 5 lety

    Two big mistakes:
    1. Vigenère and not vigener
    2. You don't need many messages to decipher Vigenère when the key is short, you can decode fairly short messages with other analysis methods. The only problem comes when the key is in the same length as the message (or close to it) and the key is random, which basically turns the cipher into One-Time-Pad.

    • @zachstar
      @zachstar  Před 5 lety

      Thanks for the corrections. And I’m assuming you mean the cipher becomes more secure when it essentially turns into the one time pad? (Assuming one time use).

    • @richkillertsm6664
      @richkillertsm6664 Před 5 lety

      Yeah, it's perfectly secure when we're using a random key in the same length as the message ONCE (hence the name One-Time-Pad). When used that way it is mathematically impossible to know the plaintext without the key.

    • @zachstar
      @zachstar  Před 5 lety

      Okay yeah that makes sense. I was actually going to include a one time pad example using xor operations but didn’t have time.

    • @richkillertsm6664
      @richkillertsm6664 Před 5 lety

      You can define OTP (One-Time-Pad) under with any modulo as long as the key is random. XOR is addition under modulo 2. When working with letters in Vigenère we work under modulo 26, and can be turned into OTP as described. Besides that there's no difference, and they both result in perfect security.

  • @catherine_404
    @catherine_404 Před rokem

    If we decided to pass notes in the class so that no one could decipher them if caught, the best method is us speaking some exotic language. Chinese or Japanese would be sufficient. There are many small living languages which do not have translator in Google.

  • @alleygh0st
    @alleygh0st Před 3 lety

    can't I just find a common factor and see if the results can be divided by the modular?

  • @danielpetrov3023
    @danielpetrov3023 Před 5 lety

    I have a question. I tried it and saw that this works, but why when we subtract 1 from 3^8 the number isn't divisible by 15?

    • @zachstar
      @zachstar  Před 5 lety

      Good question and I only mentioned this briefly but at 11:54 I say that x and n have to be relatively prime which 3 and 15 are not. Try it with 4, 7, 11, 13, 14, etc instead of 3 and it'll work.

  • @starshinesun738
    @starshinesun738 Před 11 měsíci

    If use x=6 and p=3, that formula doesn't hold. Right?

  • @JarppaGuru
    @JarppaGuru Před 9 měsíci

    2:12 no need calculate just make 2 rings bigger and smaller with A-Z then turn smaller ring what key is to A first would be C under A now you look whats under Y yes there is B. no need calculate.
    same thing with long strip paper A-Z and A-ZA-Z "smaller is 2x longer" so its easy.
    was that so hard move key letter under A then look whats under letter you try encode that cipher letter. same it works backward move current key under A then look cipher letter then look whats is it decoded

  • @sab2597
    @sab2597 Před 5 lety

    Ø(7)=6x1 then how come its relative prime numbers include 1

  • @giladlad
    @giladlad Před 5 lety +4

    Great video, but I think you made a small mistake.
    at 9:40 you are reffering to Fermat's little theorem , but in order to use the equation you used you need an integer x which is not divisable by p, and not just any integer you would like.
    for example if you use: x=4 & p=2 4^(2-1) != 1 mod(2) .

    • @zachstar
      @zachstar  Před 5 lety +1

      Thanks! And yes definitely right, forgot to mention that part.

    • @99bits46
      @99bits46 Před 5 lety

      giladlad Khoor nerd

  • @abdullahalmalki2464
    @abdullahalmalki2464 Před 5 lety

    hey, at 7:55, aren't 72 and 15 both divisible by 3 so they aren't relatively prime and this still works, or did i get it wrong?

    • @Plundarr
      @Plundarr Před 5 lety

      The divisor and the modulus, or the 2 and the 15, must be relatively prime.

  • @lucioleepileptique9195
    @lucioleepileptique9195 Před 5 lety +3

    What is the message length of the universe ?

    • @clayz1
      @clayz1 Před 5 lety +2

      Frank HEUSER 42

  • @brendawilliams8062
    @brendawilliams8062 Před 2 lety

    Nice I guess it is a math that some people really like.

  • @laxmibiswas4041
    @laxmibiswas4041 Před 5 lety

    cool

  • @eve.m1026
    @eve.m1026 Před 3 lety

    Okay i got lost when he started mentioning mod x 🤣

  • @duailyp5142
    @duailyp5142 Před 5 lety

    That eulers thing is cool and confusing

  • @diegovergaracampos2325

    Hi Im doing an essay of the topic, does anyone knows any bibliography of it ?

  • @guillermoflores5511
    @guillermoflores5511 Před 2 lety

    Farm fresh to you.

  • @RickyPisano
    @RickyPisano Před 3 lety

    What about a cipher and key with letters, numbers and symbols as follows:
    TR#DUTR#DU6J23DAXX3 using key = 1#L-H1#L-HBEQ9-WNN9
    This is only a portion of it. Thanks.

  • @bardhokajvazi2726
    @bardhokajvazi2726 Před 4 lety

    Is not 10=2 mod(4) ? Or i am missing something ?

  • @anuragpandey8996
    @anuragpandey8996 Před 4 lety

    what if 10 ≡ 6 mod 4 devided by 2 equals 5 ≡ 3 mod 2?? check video at 6:18

  • @pawanghimirey2195
    @pawanghimirey2195 Před 4 lety

    is x^(p-1)=1(mod p), true for any number?
    or are there any exception?

  • @zerodegreescelsius
    @zerodegreescelsius Před 2 lety

    Wow😆

  • @uchicha666
    @uchicha666 Před 5 lety

    11:23 the formula makes no sense at all... fi(p) = p-1, so fi(15) should be 14 right? And just above it there is equation where fi(15) = 8...

  • @78anurag
    @78anurag Před 2 lety

    Shoutout to those Chads writing programs and doing lots of math just so that I can text 'Haha big chungus so funny'

  • @JarppaGuru
    @JarppaGuru Před 9 měsíci

    4:25 yes yes yes but your encoded E is splitted many other letters and also other letter change same ammount to others you cant see whats E. its only work if your cipher is subtition
    means
    ABCDEFGHIJLKMNOPQRSTUVWXYZ
    MRHOPKVNEWBGTAZSQDLUCIJFYX
    then we could analyze that P could be E if it apper most but its not allways
    but if you shift that lower part every letter VOLA that P not occur anymore most lol

  • @johnnybokie1325
    @johnnybokie1325 Před 5 lety +1

    3rd ??

  • @YoshikaKehelpannala
    @YoshikaKehelpannala Před 2 lety

    10:51, the primes under 10 should be 2,3,5,7. Nine is not a prime and 1 cannot be counted in.

  • @taleofkaran
    @taleofkaran Před 4 lety +1

    DOUBT PLEASE CLARIFY
    But 28 is congruent to 4 modulo 6 holds true when divided by 4. This should have been false since greatest common divisor of 4 and 6 is 2 not 1.. Please clarify!