@@Mathodman20 yh, I've solved lot of sat math questions. Although I've failed some, looking at their corrections made me grab immediately but this question was different 😮💨😢
Hi the solution is correct but there is a much easier way to do this, that took me around 1 minute. The prism's surface area can be written as 360x + x^2 = K since the height is being doubled we just adjust our formula and get 720x + x^2 = 92/47 * K This is a simple system of equation, and just graph this on desmos as 720x + x^2 = 92/47 * Y 360x + x^2 = Y and find the intersection which gets you 16.
This is incorrect. 1) The SA for an individual prism is 2x^2 + 360x (includes both top & bottom) which equals K 2) The total SA for both prisms is 2x^2 + 720x (includes 1 top & 1 bottom with the other top & bottom not counted since they are on the inside attached to each other) = (92/47)*K 3) Very difficult to do this in Desmos and find the intersection because the graphs are so steep. You need to first set the 2 equations equal to each other (or substitute in) and then you can enter that into Desmos.
K is S.A of cuboid with height 90 and 'resulting S.A' is of cuboid with height 180. (92/47) × K = resulting S.A (92/47) (360s+2s^2) = 720s + 2s^2 solve this and get answer s=8
Rigorously long question there. Does the ACT ever give these kinds of questions out because I feel like these kinds of questions may take more than 2 minutes for me
Thank you so much, I finally understand why we have to minus 2s^2😄
that was a good problem ..tried my best explaining that and trying to find a shortcut...not sure how to do this any other way
that was a good problem ..tried my best explaining that and trying to find a shortcut...not sure how to do this any other way
@@Mathodman20 yh, I've solved lot of sat math questions. Although I've failed some, looking at their corrections made me grab immediately but this question was different 😮💨😢
Omg please do upload these type of questions frequently ❤
thanks, ill get back to it. It was just my summer vacation
Hi the solution is correct but there is a much easier way to do this, that took me around 1 minute.
The prism's surface area can be written as
360x + x^2 = K
since the height is being doubled we just adjust our formula and get
720x + x^2 = 92/47 * K
This is a simple system of equation, and just graph this on desmos as
720x + x^2 = 92/47 * Y
360x + x^2 = Y
and find the intersection which gets you 16.
This is incorrect.
1) The SA for an individual prism is 2x^2 + 360x (includes both top & bottom) which equals K
2) The total SA for both prisms is 2x^2 + 720x (includes 1 top & 1 bottom with the other top & bottom not counted since they are on the inside attached to each other) = (92/47)*K
3) Very difficult to do this in Desmos and find the intersection because the graphs are so steep. You need to first set the 2 equations equal to each other (or substitute in) and then you can enter that into Desmos.
How do we know when should we use a system of equation for word problems?
Thank you so much I love you❤
Why do we multiply 90 and s in the second step? I just did 90(4).
3:19
.ehn!!!..my brian is fried!😂
yea, this was really wordy for an SAT
K is S.A of cuboid with height 90 and 'resulting S.A' is of cuboid with height 180.
(92/47) × K = resulting S.A
(92/47) (360s+2s^2) = 720s + 2s^2
solve this and get answer
s=8
that is a lot faster haha...yea I am not that great with memorizing and remembering formulas but they definitely help.
Could you elaboraate more on this?
Rigorously long question there. Does the ACT ever give these kinds of questions out because I feel like these kinds of questions may take more than 2 minutes for me
this was an SAT. There are only about 1-2 questions there that are tricky and long. The ACT doesn't really give wordy problems like this one.