Gotta find a video for that! But really, you just have to set A equal to an identity matrix and perform row operations until A looks like an identity matrix. When that is achieved, what was once identity matrix is now your A inverse:)
could you help me with this: If A and B are square matrices of the same order n and invertible, solve the matrix equations: a) XAB = A b) overline XA - B = A (AX)-1= B
can you interchange row 1 with row 3? and if you do that, should you also change the row 1 of identity matrix with row 3 in finding A^-1?
Super helpful writing the proof at the beginning, thank you!
Just can't understand the process to find the A^-1... Pls explain that part🙂
Gotta find a video for that!
But really, you just have to set A equal to an identity matrix and perform row operations until A looks like an identity matrix. When that is achieved, what was once identity matrix is now your A inverse:)
Awesome! Short and sweet video. Loved it.
got perfect on this question on the midterm thanks to you.
thanks, it helped a lot !
could you help me with this: If A and B are square matrices of the same order n and invertible, solve the matrix equations: a) XAB = A b) overline XA - B = A (AX)-1= B
in the first minute, you can make a simple replacement? like ax=b then x = b/a and that's it?
Great Job!
Extremely helpful!!!
Thanks for helping ,it helped lot of , suddenly ,I find you channel , you clear my all doubt thanks again ,we will hopefull to you
Thank you, saved my day
Exelente.!!Perfect!!..
Is there a way to solve this when A is not invertable or is there no solution?
petscop
This helps ty
JazakAllah
Thank you very much.
Glad I could help.
Helpful, thanks
I am glad. Thank you for the comment!
Thx
thanks ey.
Have absolutely no idea how you got those numbers for your inverse. Gotta use the ole calculator