When I was obtaining a degree in electrical engineering back in the mid 1960s, pocket calculators didn't exist. My Post slide rule effectively added log2 and log3 to get log6, accurate to about three digits if you hadn't dropped it beforehand and you had good eyesight. Today, what professor or boss in their right mind would ever say, "No, we don't use calculators here, only pencil and paper or your slide rule if your dog hasn't chewed it up."
Well explained for those who need to know how to simplify log equations. Of course, when these are embedded in much larger or more complex equations we may prefer to keep the the simplified logs until the very end rather than approximate values too early. Great explanation as I said.
@@carlitoongco9682 if he is going to anyway evaluate log(3) and log(2) after so many steps, why not evaluate log(18) and log(6) and done with it faster.
@@kankri99 u dont understand...mind this, if u r a teacher with so many students who are slow learner plenty of them will fail...they need an approach a step by step solutions to problems so may for them to understand. And later on you may teach them with short cuts to improve their speed solving problems.
Once the calculation has reached the point of X log 6 = 18 the whole process can be greatly simplified for the sake of instruction efficiency. Students need to be taught simplification to reduce chance of error and time spent during exams. X log 6 = 18 = 6 * 3 X log 6 = log 6 + log 3 Note: multiplication of two numbers m and n is addition of the log form; log(m) + log(n) X = (log 6/log 6) + (log 3 / log 6) Note: {log 6 = log 2 + log 3 = 0.3010 + 0.4771 = 0.7782} but no need to calculate log 6 in terms of log 2 and log 3 X = 1 + (0.4771 / 0.7782) = 1 + 0.6131 = 1.6131
Why so many steps. After taking log on both sides , write x interms of ratio of log18 : log 6 , then from log table substitute the values for log18 & log 6, then that is x . Simplify by dividing.
It's a good teaching video. Technically though, once he put in truncated trancendental numbers, the equals sign should have been replaced with the symbol thtat means 'approximately equal."
"Precise but not Accurate!" is what a professor told me he had written on a student's exam paper in response to sixteen digits of an incorrect answer copied directly from a pocket calculator.
@@roger7341 Spurious precision is one of the fastest ways of spotting the work of an idiot. There are very few times in everyday life when any digit past the third is likely to be accurate or useful.
Sir kindly solve this with explanation...∑ ∞n=1 [log(n+1)/nsquare] Let me just say...by typing this can't be completely explained.. I know... so you can make a video on this...
The explanation is not only lengthy. It is not accurate. The values for the various logs are not finite. But of log2 and log 3 I still remember from my school 60 years ago.
These are good videos, but you should really try to condense them. Some of the basic intermediary steps can be eliminated for this video. Most of us know how to divide fractions and multiply numbers. Make the videos only about 2 to 3 minutes long.
It fits a more standard solution method to break the 18 into 6 * 3 first. Then (log 6/ log 6) + (log 3/log 6) will evaluate to 1 + (log 3/log 6). Either way the log values are found with a table or calculator.
Good GAWD, you went through a lot of unnecessary extra steps (seven minutes-worth) -- and got a less accurate answer! Just divide log 16 by log 8 (at 2:15 in the video). You're done!
Boring explanation! Once you solve It by a numerical approximation you can stop at the third step and use a calculator or log tables. A more elegant solution: X=1+log 3 were the base of the logarithm is 6
This is good timepass but useless. I learnt trigonometry, calculus, logarithm which have no practical value. 8th standard mathematics is sufficient in profession. Rather we should be taught MS office, basic program in Java. Thank you
@@MathsExplorer24 How would you do it? If the exponent is 2 we multiply 6 as 6x6; if the exponent is three then it is 6x6x6; since the exponent is greater than 1 and less than 2 how would we do it then; please show the solution.
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Olympiad Mathematics: 6ˣ = 18; x = ?
x = log₆18 = 1.255/0.778 = 1.613
The calculation was achieved on a smartphone with a standard calculator app
While I solved x = log18/log6, your method better shows the relationship of Base (6), Ans (18) and Exp (x). Good old Bacon And Eggs (BAE). Nice job.
😂😂
No need to lengthen procedure
Simply use log table for log 18 and log 6
That's what I was thinking as well because he used a calculator anyway.
Since you are using a calculator, why not simply use x=log(18)/log(6) and be done with this really super boring problem?
Here I can't used a calculator, I just remembered the Values of log2 & log3.
@@MathsExplorer24 Of, course, remembered them from when you used a calculator😂.
log table exists
@@marioprogamer12345 there is a log table book.
When I was obtaining a degree in electrical engineering back in the mid 1960s, pocket calculators didn't exist. My Post slide rule effectively added log2 and log3 to get log6, accurate to about three digits if you hadn't dropped it beforehand and you had good eyesight. Today, what professor or boss in their right mind would ever say, "No, we don't use calculators here, only pencil and paper or your slide rule if your dog hasn't chewed it up."
Well explained for those who need to know how to simplify log equations. Of course, when these are embedded in much larger or more complex equations we may prefer to keep the the simplified logs until the very end rather than approximate values too early. Great explanation as I said.
You solved and narrated it such a way that even s child can understand it.Thank you.
I am deeply grateful to you for such spectacular explanation..❤🎉
Make your solution simple…if you are taking the exam in Math and time is limited you will not pass the exam.
He is only demonstrating...so that others may understand and learn. Its not for those who already knew how to solve that particular equation.
@@carlitoongco9682 if he is going to anyway evaluate log(3) and log(2) after so many steps, why not evaluate log(18) and log(6) and done with it faster.
@@kankri99 u dont understand...mind this, if u r a teacher with so many students who are slow learner plenty of them will fail...they need an approach a step by step solutions to problems so may for them to understand. And later on you may teach them with short cuts to improve their speed solving problems.
@@kankri99 you re right
👍
Once the calculation has reached the point of X log 6 = 18 the whole process can be greatly simplified for the sake of instruction efficiency. Students need to be taught simplification to reduce chance of error and time spent during exams.
X log 6 = 18 = 6 * 3
X log 6 = log 6 + log 3 Note: multiplication of two numbers m and n is addition of the log form; log(m) + log(n)
X = (log 6/log 6) + (log 3 / log 6)
Note: {log 6 = log 2 + log 3 = 0.3010 + 0.4771 = 0.7782} but no need to calculate log 6 in terms of log 2 and log 3
X = 1 + (0.4771 / 0.7782) = 1 + 0.6131 = 1.6131
X=1.5,6pover of 1.5 meens 6*3=18,6square =36, 6pover 1=6,1.5 meens1/2,6/2=3.
Why so many steps. After taking log on both sides , write x interms of ratio of log18 : log 6 , then from log table substitute the values for log18 & log 6, then that is x . Simplify by dividing.
It's a good teaching video.
Technically though, once he put in truncated trancendental numbers, the equals sign should have been replaced with the symbol thtat means 'approximately equal."
"Precise but not Accurate!" is what a professor told me he had written on a student's exam paper in response to sixteen digits of an incorrect answer copied directly from a pocket calculator.
@@roger7341 Spurious precision is one of the fastest ways of spotting the work of an idiot. There are very few times in everyday life when any digit past the third is likely to be accurate or useful.
Log of 18 divided by log of 6 gives the value of X no need for all the waffle.
x= log of18 base6=1+log of3 base6=1+1/1+log of 2 base 3.
No need to make the solution too long unnecessarily
Sir kindly solve this with explanation...∑ ∞n=1 [log(n+1)/nsquare]
Let me just say...by typing this can't be completely explained.. I know... so you can make a video on this...
How is this a Maths Olympiad question? It is easy. I thought there was going to be some trick but there is nothing original.
Herr teacher, why no go directy :
log of 18 = 1,252527
log of 6 = 0,77815
X = 1, 61315
log 6 is better in the factoring. But not necessary to use log 2 and log 3.
The explanation is not only lengthy. It is not accurate. The values for the various logs are not finite. But of log2 and log 3 I still remember from my school 60 years ago.
Yes, here we use it's approximate values upto four decimals places......
These are good videos, but you should really try to condense them. Some of the basic intermediary steps can be eliminated for this video. Most of us know how to divide fractions and multiply numbers. Make the videos only about 2 to 3 minutes long.
Ok I will try, but most of my audionce are of basic level....... that's why I am trying to explain step by step....
@@MathsExplorer24That's fair. If that is your target audience, then I can find no fault, my friend. Nice videos and very easy to follow! 🙏
I got log6(18). In my opinion you should only approximate at the end, when you have the exact solution.
Far too lengthy. It's just log18/log6.
Those who know long a d how to see the log table can solve the problem easily.
My question is do the modern students learn how to use log table?
Just do log 18 ÷ log 6
Do 6x = 6³ now divide by 6
How can a maths Olympiad examee be allowed calculator ??
Nice Explaination❤
You are real lecturer😊
Log18 on base 6 is answer.
Unnecessary expansion of solution. Poor
Excelente explicación, paso a paso, muy entendible en el "lenguaje de los números" 👌👍👍👍
Why can't we just find the value of (log18)/(log6) by calculator?
It fits a more standard solution method to break the 18 into 6 * 3 first. Then (log 6/ log 6) + (log 3/log 6) will evaluate to 1 + (log 3/log 6). Either way the log values are found with a table or calculator.
Может быть просто ученикам пользоваться калькуляторами, которые всё считают.. Ну бред численно так выводить
If we place by simplifying what happened
a^x = b => x = logb/loga
Thanks
6^(ln18/ln6)=18----> x=ln18/ln6.
How....?
This problem is a heavy LOG Just can’t handle it
Quite an interesting video.
It's just a approximate solution.
Math olympiad? C'mon...
This is a max. 2 mins problem extended (even complicated) to nine and a half.
If you take so much time you will not be able to clear the olympiad.
You also required to divide 1 by 10,000
Point out the step, where we need this.....
Log 18 divided by log 6 will give you answer 1.6.
Why do you struggle?
Fantastic!
Wtf is log6 and log18?
Sounds like error.
X = (log 18)/(log 6) = 1.6132
Exact Ans. Approx Ans
❤
Easy things solved in very difficult way…. Not easy teaching..🙏🏽
Good GAWD, you went through a lot of unnecessary extra steps (seven minutes-worth) -- and got a less accurate answer!
Just divide log 16 by log 8 (at 2:15 in the video). You're done!
Boring explanation! Once you solve It by a numerical approximation you can stop at the third step and use a calculator or log tables.
A more elegant solution:
X=1+log 3 were the base of the logarithm is 6
This is good timepass but useless. I learnt trigonometry, calculus, logarithm which have no practical value. 8th standard mathematics is sufficient in profession. Rather we should be taught MS office, basic program in Java. Thank you
Watching from Tanzania
Usando a tab de log fica fácil…..
How to recheck your answer if it’s right.
Substitute back the Value in equation or Question.......it's simple.
@@MathsExplorer24 How would you do it? If the exponent is 2 we multiply 6 as 6x6; if the exponent is three then it is 6x6x6; since the exponent is greater than 1 and less than 2 how would we do it then; please show the solution.
Sir,
You could solve this using a much faster and easier way. In my view, you even do not know the basics of maths and logarithms.
X = log 18/log 6
log 6 18 = 1.613…
Too much bs
Divide both sides by the same factor
6x=18
6x/6=18/6
Simplify the expression
Solution
X=3
6^х\6=6^(х-- 1) 😊
Xbaraber...3❤
Nice video sir 👍
3 times 6 = 18
Three
Your math is indeed powerful but need to improve in your handwriting. You can't write 8 properly 😂
3
The averege rate $100/hr
6×3=18
× = 3
Horrible teacher
Takes too much time
good
2
tebeda new solnu qintram werrage hulla
lg18/lg6.
10000 is différent whith 10,000
How....?
They are same numbers...
🤯
Hahaha
Boring
Ye galat hai
What's wrong....???
А нельзя диктора с нормальным акцентом нанять?
Assalam O alaikum sir!
Some days before i requested you to tell that your channel is monetized you told me that not still
Please tell me now had done
The Adsense problem
I really impressed because of you and want to start my own such yt channel
Please tell me whether i give you my personal number or you❤
Yes, and now my Channel is monetized from December 1st.
@@MathsExplorer24 Mashallah
3
3
How.....?