Chi square test | Goodness of Fit | Small Sample Test

[@thedrmas11]

X² =4.15
Critical region
X²t,0.05,6 (12.59)
X²c < X²t
4.15 < 12.59
Thanks ❤ for such a great lecture
H⁰ is accepted

[@cutegirl-lo2xx]

Same❤

[@thedrmas11]

@@cutegirl-lo2xx gg

[@animesaga9195]

Solution:
X2cal = 4.1633,
D.F = 6,
X2t,0.05,6 = 12.59
H0 is accepted

[@statisticsforall3433]

Yes correct

[@anshulyadav691]

Thaanku so much mam...love from agra mam..i solved and i get the answer ...u r inspiration mam...🌸❤️ Huge respect

[@dwarkeshaggarwal642]

Thanks a lot Mam
This is helping us a lot during exam time!

[@SHAHKAR_AHMAD]

Best video on internet about this topic. More power to you sister ❤️

[@sumairatariq8193]

Thnku thnku sooo much mam mjy is topic ko Dak Dak k dar LG rha tha but jasy apny mashallha mashallha 😍 smjiya ha am totally understand plz plz ase vedios appload krty rhiy plz thnks a lot again ❤️

[@sumairatariq8193]

Mjy state Sy nfrt ho Gai thi but apka lec Liya mjy smj ni arhi kasy thnks kro😍❤️

[@sangeetaroutel]

H.w ans- cal value=4.15,Tab. Value=12.59
Tab. Value>cal. Value
So Ho is accepted.thank you so much mam ❣️

[@user-st8bd6hl1e]

Table value to same hi 1 sum ki ter ha (11.07)

[@anamichauhan07]

Calculated value is 4.15
Tabular value is 12.592
Calculated value is less than tha tabular value
Therefore, condition satisified, Hypothesis accepted and the fit is gud..

[@tastyfoodrecipesvideos6050]

Great explanation 👐

[@aswinisahu9887]

Very nice explanation...thankyou mam...

[@rishyparasar5329]

Thanks a lot, didi! It was quite helpful for me to understand these concepts!

[@ThisisGhostrider]

I do not know how can I thank you . great great thanks love from jaipur

[@rizwanmirza6160]

if "e" value is not given in the question of poission distribution, how can we observe the value of "e"??

[@moxitshah6167]

Accepted 12.59

[@aadilhizbi4504]

Please continue rakhiye

[@smitkhunt3964]

H0 is accepted
X²c < x²t

[@statisticsforall3433]

Correct. Keep it up:)

[@gayatri.padmani]

All the days the accident place in same proportion.
X^2 = 4.15
X^2t = 12.592
Fit is Good

[@statisticsforall3433]

Yes correct. Keep it up:)

[@aadilhizbi4504]

Great lecture

[@farooquishafifa222]

Please upload Fisher's Z transformation chapter

[@kushalshah1514]

chi square is 12.59 and calculated value of chi square is 4.153 is this right ?

[@HashimKhan-oo2gk]

App nai expected freg kya li hai

[@Economics365]

Chi square df is ( C-1) *(R-1) , right?

[@jimms3670]

But how we know that ki ame es sum me X² ka sum Krna hai 😥

[@niralipatel8649]

X^2 cal = 5.58 < X^2 tab 12.59
Hence, We can say that on all the days the accident took place in same proportion.

[@statisticsforall3433]

Calculated value is 4.15

[@niralipatel8649]

@@statisticsforall3433 ohh sorry...I put the value of n=6 instead of 7 😅 yess...I got an ans 4.15👍🏻

[@naitikacharya]

Cal. Value = 4.17 < Tab. Value = 12.59
Ho is accepted.

[@statisticsforall3433]

Yes correct

[@fahadnizamani2487]

Your voice is too low.. it creates difficulty to understand.. kindly upload videos with raised voice it will be better

[@shashankprabhakar3486]

Phone kharab hai aapka

[@TECHZPAUL]

Ha isleya mai buds ya earphone use krta hu 😅

[@dishijain0852]

Fcal 4.167 ≤ F 0.05
Ho is accepted

[@statisticsforall3433]

Correct. Keep it up:)

[@shayar_dil_da0006]

X^2,t,0.05,5 how to find this in exams......

[@shayar_dil_da0006]

Mam.. please tell me

[@aneestariq1834]

freinds aye hayee

[@shaikhzikra7979]

Where is 2 part??

[@statisticsforall3433]

Here it is : czcams.com/video/UQ1tXbdO7RQ/video.html

[@statisticsforall3433]

Here it is :czcams.com/video/UQ1tXbdO7RQ/video.html

[@balarabhay3282]

Vnsgu na stat ni imp apo ne

[@shaikhzikra7979]

can we get imp question ??

[@statisticsforall3433]

In the exam , similar types of questions are asked which are solved in the video

[@girdhariramsuthar5728]

Mam is question ka identification kya hai.

[@kisnaop7509]

mam ko sardi h shayad