GCE's And G10-12 - Full Mole Concept [Stoichiometric calculations]

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1. X=20g of Ca
2.x=16moles of NH3
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[@lulu9261]

Jus a quick question isn't it 10g of ca
Because Ca+h20= Ca(OH)2 + h2
And balanced it's Ca+ 2H2O -> Ca(oh)2+H2
The equation
40g of ca->36gh20
X ->9gh20
X=10gof ca

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Great sir work Sir... I found the Same answer by dividing 3.2/4. Coz the molar mass for H in this case is 4.

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I'm not good in chemistry... but am just curious on the h
This part.... How can the number of moles of hydrogen (0.8 an element) in methane(0.2 a compound) be greater than number of the number of moles of a compound containing two different elements? So if we were to calculate the number of moles of carbon in methane and add it to the number of moles of hydrogen are we going to get 0.2 which is the number of moles of methane?

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Please finish it up with percentage yield

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Do about percentage purity

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