Mastering Calculus: An Introduction to Integrals

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  • čas přidán 3. 04. 2023
  • Welcome to our introductory video on integrals! In this video, we'll cover the basics of integrals and how they are used in calculus. Whether you're a beginner or need a refresher, we've got you covered.
    We'll start by discussing what integrals are and why they are important in calculus. From there, we'll dive into the different types of integrals, including definite and indefinite integrals, and discuss how to solve them.
    We'll also cover some common integration techniques, such as u-substitution and integration by parts. And to help you understand the concepts better, we'll walk you through several examples of integrating different functions.
    By the end of this video, you'll have a solid foundation in integrals and be well on your way to mastering calculus. So sit back, relax, and join us for an exciting journey into the world of integrals!
    More Lessons: www.MathAndScience.com
    Twitter: / jasongibsonmath

Komentáře • 33

  • @filmic1
    @filmic1 Před 7 měsíci +2

    I got through Cal 1 and Cal 2 taught in University, but it was never taught so succinctly as this prof. Thank-you. (fond memories of my Functions, Trig and Pre-Cal prof. in Con't Ed. He taught so well just like this prof. Amazing.)

  • @kubolor1234
    @kubolor1234 Před rokem +5

    This guy GOATED. I'm learning calculus for fun now.

  • @joabfilandus1999
    @joabfilandus1999 Před rokem +3

    Breaking it more simpler here , thanks so much 💯✅✅

  • @teachnicalnepal3403
    @teachnicalnepal3403 Před rokem +4

    wow you are the real teacher and lots of love love you so much.

  • @wilkyclergeot9416
    @wilkyclergeot9416 Před rokem +5

    Thank you so much incredible teacher!!!

  • @QueenGreyClouds
    @QueenGreyClouds Před rokem +2

    How weird I just started my calculus class this will sure help

  • @sharondavis3535
    @sharondavis3535 Před 4 měsíci

    You're a great teacher. Thank you for helping me to understanding what I never thought I could.

  • @Phymacss
    @Phymacss Před rokem +2

    Interesting! Thank you!

  • @Ah-dh7oe
    @Ah-dh7oe Před rokem +3

    I have been learning calculus for 3 years,but this guy is a genius,his approach makes the topic more fun.

  • @naderhumood1199
    @naderhumood1199 Před rokem +1

    It's a value vedio. Thank you very much indeed. Sir.

  • @Elo-hv3fw
    @Elo-hv3fw Před rokem +3

    In some countries, which I will remember as " Leibnitz Countries", the term "Indefinite" is replaced with the term "undetermined".

  • @andrewjustin256
    @andrewjustin256 Před rokem

    May God bless you, and make you triumphant!

  • @AirwavesEnglish
    @AirwavesEnglish Před rokem +3

    Hello again, Jason. I have searched hither and tither in your playlists but I can't seem to find exactly which video introduces calculus for an absolute beginner. I have got up-to-speed with all the pre-lessons such as geometery, algebra etc... and I *think* I'm ready for calculus? (Not absolutely sure about this) Thanks so much in advance.

    • @buzzz241
      @buzzz241 Před 5 měsíci

      Try his channel playlists. Calculus 1 Tutor and Calculus 1 Limits Tutor. Anything marked “Calculus 1”. Then Integral or Integration in title. 😊

  • @thatomofolo452
    @thatomofolo452 Před rokem +1

    Integers my favourite 🤸🤸🤸♥️💯💫

  • @mako2918
    @mako2918 Před 4 měsíci

    Thank you

  • @drumtwo4seven
    @drumtwo4seven Před rokem

    Nice 👍

  • @jasonlove8733
    @jasonlove8733 Před rokem

    Riemann sums!!!

  • @AzamSaeed-rm3ms
    @AzamSaeed-rm3ms Před 4 měsíci

    Dale steyn teaching maths

  • @yuriorlov47
    @yuriorlov47 Před rokem +1

    Integrals were a lot better for me than derivatives.

  • @hemrajue3434
    @hemrajue3434 Před rokem

    We can find the area of a linear function y=x between limits 0 and 1 using def integrals i.e 1/2. But this is approximated by using the non-linear function i.e x^2/2 between the same limits. It's strange how it works.

    • @jan-willemreens9010
      @jan-willemreens9010 Před rokem +1

      ... Good day to you, If you draw the graph of y = x between x = 0 and x = 1, and you want to find the area under the graph between x = 0 and x = 1, you can easily see that this area is 1/2 of the area of a 1 unit by 1 unit SQUARE, in other words 1/2 of 1 unit^2. Now looking closely at the non-linear function x^2/2 (= antiderivative of x), you can see that it also in general form represents 1/2 of the area of a SQUARE: (1/2)*(length x)*(width x) = (1/2)*(x)*(x) = x^2/2 ... I hope this makes a little sense to you now! Good luck and take care, Jan-W

    • @hemrajue3434
      @hemrajue3434 Před rokem

      @@jan-willemreens9010 yes,integral of y=x is x^2/2 that resemble the geometrical formula to find the area of a triangle

    • @jan-willemreens9010
      @jan-willemreens9010 Před rokem

      @@hemrajue3434... You are completely right, but also 1/2 of the area of a SQUARE, now you understand that applying the antiderivative or integral of any function in general has to do with area under a graph between any specified boundaries, so it must be a little less strange to you how it works, I guess ...

    • @hemrajue3434
      @hemrajue3434 Před rokem

      @@jan-willemreens9010 true, applicable for any linear function like y=3x+2 that def integral gives us area of three unit triangles plus area of a rectangle under it.

    • @jan-willemreens9010
      @jan-willemreens9010 Před rokem

      @@hemrajue3434 ... Fantastic Hemraju E!, and the nice thing with integrals is that they also deal with non-linear graphs (curves) areas which are not easy to calculate with just relatively simple geometrical objects like triangles, squares, rectangles etc ...

  • @rayspencer7255
    @rayspencer7255 Před rokem +1

    When in doubt, integrate. Old engineering exam joke !