7th maths | Pythagoras Thearom | Chapter 13 | Lecture 1 | Maharashtra Board |
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- čas přidán 8. 09. 2024
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I am Rahul Jaiswal.
In this Video You will get the Lecture videos of 7th maths Chapter 13 Pythagoras Thearom lecture 1 by rahul sir maharashtra board.
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Thank you
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Pythagoras thearom = (Hypotenuse)²= (Base)²+(Height)²
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Hypoteneuse2=Base2+Height2 right formula
In a above figure that is right angled triangled AB is height BC is base and AC is hypo...
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Pythagoras theorem formula is hyp 2 =base 2+ height2. LN =x 625 root is 25 because 25×25 = 625
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in right tringle the squre of hypotenus is equal to other side square
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7/2 what is a square root of 7/2 when u find out the square root then u get 49/2
7/2 = 7×7=49 this is a square root I hope dear u understand 🙏
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