𝗝𝗘𝗘 𝗠𝗮𝗶𝗻 𝗟𝗘𝗩𝗘𝗟 Question in 𝗝𝗘𝗘 𝗔𝗱𝘃. 𝟮𝟬𝟮𝟰
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- čas přidán 9. 09. 2024
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I still believe in you that you will re-upload those videos .so I check your channel 10 to 15 times in a day
Which videos ?
@@kushagrajindal1052jo private krdi
@@kushagrajindal1052 bro sir has removed his old playlists of chapters like functions,etc
Thanks for 30 Subscriber CZcams family 🎉
Sir we can also find values of of a and b by equating real 😊 and imaginary part of complez no.😮 In polynomial 2 by substituing value of i√3🤔 then it becomes easy 😎❤
सर मेने गणित से बीएससी किया और उसके बाद 2019 में फिजिक्स के साथ एमएससी भी पूरा किया हूं। यद्यपि मुझे कोई मैथ्स का एग्जाम नहीं देना है पर मैथ्स के साथ मेरा लव अफेयर बहुत पुराना है तो आपके विडियो मुझे खींच लेते हैं। मैं जब दिमागी तौर पर थक जाता हूं तो आपके विडियो मुझे रिफ्रेश कर देते हैं। ❤
Thank you sir you re uploaded few of the lectures like continuity lec-01.... please if possible re-upload all the others also
Thank you soo much sir....for being with us and supporting our journey.....
Lot's of love and regards.....
Sir, please 😟 make a video on the question :
Q. The equation (x ^ 2 + x + 1) ^ 2 + 1 = (x ^ 2 + x + 1)(x ^ 2 - x - 5) for x \in (- 2, 3) will have number of solutions,
(1) 1. (2) 2. (3) 3. (4)Zero.
Sir I am waiting for your video. 🙂🙂🙂🙂🙂
Answer - (4) Zero
Sol:- simplify given equation. It will become x³+4x²+4x+3, let it be f(x). Then find f(-3), f(-2), f(-1), f(0) to have an idea about it's graph. Then find f'(x) and find critical points. Plot the graph of f(x)
@@speed01234 thanks 😊
Sir I we put (i.sqrt(3)) in second equation as it satifies it so we will get -9a+i.sqrt(3)(2b-12)=0
so real part =0 and imaginary part=0 so a=0 and b=6
In the Same way bruh...I did also
Idk but adv standard is also decreasing that why marks are going high
If u have got high marks then only you can say that
which grade are you in ?
@@chaitanyakumar-gupta-viib2320 Yeahh , as felt that i'm good at maths but couldn't solve these shit ques there .. That's huge difference solving it at home ( free mind ) and in JEE adv exam hall......
sir second wali polynomial mai i root 3 ko put karke imaginary and real part equate karke a and b aasani se aa rahe hai
Sir I got IIT Bombay, engineering physics branch 😊😊
86 marks in maths
Apne phod Diya bhaiya congratulations
Bhaiya how you solve cengage I am in 11 can you give me some tips
@@user-rn9nn3bg7e bhai maine cengage solve nhi kiya tha. Mere coaching module me jo questions the main unhe aur teachers ke classwork me karae hue questions hi karta tha bus.
@@tuiitphodega7618 apki rank kya thi
@@tuiitphodega7618 math me itna Acha score ka secret
गुरुदेव ITF की प्लेलिस्ट नहीं मिल रही है कहां गई आपने प्राइवेट🎉 तो नहीं कर दी है या फिर डीलीट तो नहीं हो गई यूट्यूब से। Please sir provide ITF playlist.
Very very simple question
which grade are you in ?
Class 10
@@godkeshavyt7229 mein to 8th mein hun
@@AryaArya-io8sb Abe chup
Sir I have just observed that 2nd equation given in question just differentiation of 1st equation given
So there might be sone diff approach present
You are ✅️
x⁴+ 0x³+ 6x²+ 0x - 16 =0
If the four roots of this equation are p,q,r,s
Why can't we solve this using theory of equations ?
Sum of roots--
p+q+r+s = -b/a = 0
Sum of product of roots taken 2 at a time = c/a = 6
(p+q+r+s)² = p²+q²+r²+s² +2(prod. of roots 2 at a time)
0= p²+q²+r²+s² +2(6)
p²+q²+r²+s² = -12
Please someone help me with this I am not able to figure the mistake out
EDIT--
ok i got it, its because the roots p,q,r,s are complex here mod for complex numbers is not same as that of real numbers...
Thats why p²+q²+r²+s² is different from what is asked in the question. Beacuse mod in complex nos would be a positive real no. and its square would be positive.. and p² can be -ve as it is complex
GOT IT! 😅
Bro which grade are you in ?
How did u expand (a+b+c+d)^2=a^2 + b^2 + c^2 + d^2 +2(product of roots) there are many mathematics laws broken here
@@sarthaksinha8986
(a+b+c)²= a²+ b² +c² +2(ab+bc+ca)
This identity is valid for 4 terms, 5,6...
The "format" remaining same i.e sum of squares of individual numbers + 2times product of them taken two at a time
I think sir should bring some extra ordinary maths of jee along such maths
Sir where can we get your lectures? please tell🙏
Sir please upload your old videos 😢
Like sir blessings ❤❤
Sir aapki ITF ki playlist ni mil rhi, we do really need it
How could x² = -8 ??
I have factorised in a different way,, talking x² common and sending 16 on another side,,,,in this way I got x = 4,-4,√10,-√10
And hence got the answer 52..
#doubt
🟣 Doubt Cleared :
Sorry,,Sir is right.
In this question,it is not mentioned that x is real,so that condition (x²= -8) is valid. And we will get imaginary root.
Mai kitna silly mistake krta huu 😮💨
Sorry, Sir is right.
In this question,it is not mentioned that x is real,so that condition (x²= -8) is valid. And we will get imaginary root.
Mai kitna silly mistake krta huu 😮💨
A word that's both adjective and a noun such word is called
Sir, please kind 🙏🙏 humble request here.
Please don't remove any your past videos in this channel like ITF, SETS, FUNCTIONS
Sir, thousands of students still use and thankful to you till now, those videos are creation of only the pure feel of mathematics, an emotion.
Sir, just a suggestion you can start new courses but let old ones be remain here, you can give more premium content with money courses but sur don't remove videos.
🙏
Sir please ISI exam ka question karaya kariye usne bahut Achcha level ka question rahata hai
I did the mistake of writing |2√2 i|² as -8 not +8
your fault L
Sir Big Fan ❤
Sir equation satisfy karke fir comparing both sides karke bhi answer aa raha bina SOR aur POR toh matlab 9th wala baccha bhi kar sakta hai❤
sir dusri equation me sum of rot lagake to b 0 aa rha hai
Sir please 🥺 come back in PW
Bhai 100k like kardo
Simple
Done by 10th grader
❤❤❤
Sir ap graduation level ki maths kyo nahi padate bhot jarurat hai ap jese teacher ki
Successfully solve sir
SIR PLZ PLZ DO A BOOK REVIEW ON SL LONEY COORDINATE GEOMETRY JUST LIKE YOU DID FOR TRIGONOMETRY BOOK.. PLZ SIR ..WHICH EXERCISES TO DO AND WHICH WE SHOULDN'T
bhai 11th mei hai kya ?
agar hai toh mere hi saab se tu usse mat ker jee ke liye kyuki jo usmei hai sab kuch cengage (coordinate geometry) mei diya hua hai .
Sir aapke function Trigo ITf ke lec hide ho gaye he kese dekhe plz help ❤❤
Sir don't private your old videos we need those videos
Sir please re upload the hidden playlists please sir 🥺🥺🥺🥺🥺🥺🥺🥺🥺
Sir how 2root2 iota square is 8 it should be -8
Sir plz solve MIT Integration bee problems
Has anyone buyed sir PYQ batch please tell how is it going
20 he iska answer Maine kud solve Kiya tha
Done by 10 th grader but took some time
Why leave PW
My study has been stopped
Muthi mar fir❤
Bhai meri bhe mar dena muthi
Wrong product of roits also zero as 0,i√3,-i√3..hence product is zero na
Talking only about only imaginary part
Sir pls 11th ke vdo upload karo sir pls
again i request you to please sir reupload those videos
Successfully solved the question as a 10th grade student 🫠
I am in 10th and I also calculated the roots but did you also know how to take mod of imaginary no’s.
@@jatingomber9141bina mod liye hojayega... Newton sum equation ya simply sum of roots taken 2 at a time 3 at a time use krlo
Bro I'm disheartening you but solving any level or question at home ( free mind ) and solving in paper as of JEE adv is extremely seperated with each other , as a good at maths but can't solve these shit ques there - So making you more confident about on your own that you may do something but just study ......
😂 exam centre me hawa nikal jati hai
@@VaibhavSharma-gg5ge yes i can feel it but jee is never my target neither iit
the given equation 4X^3 + 3a^2 + 2bx = 0 has exactly more than three solution
x={i√3, -i√3, 0, √3, -√3} seems like this equation is lies between imaginary and real world
3 imaginary root also 3 real root
Kudratic😂
First comment ☺
I am 123 one to like😅😅
Sir pls upload old videos 😢