Stress on an Inclined Plane.MP4

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  • čas přidán 30. 01. 2011
  • Here's how to calculate stress on an inclined plane due to an axial load. I show how to find the expressions for normal stress and shear stress. Then I show how shear stress is a maximum at 45 degrees.

Komentáře • 116

  • @IamJustJosh_
    @IamJustJosh_ Před 8 lety +30

    I spent hours and hours trying to understand this, but this video has cleared it up for me in 10 minutes! Thanks!

  • @verygood6625
    @verygood6625 Před 5 lety

    The way you drew the figure in the first sight explained every thing, great job. lucid and clear. Thanks

  • @drusle6
    @drusle6 Před 11 lety +8

    Brilliant explanations, and done without editing!
    Best available mechanics clips on youtube, I don't know how lecturer's in Sydney have a job after watching you. You make them look like mumbling fools.
    You're on the ground level of the next generation of education and I truly hope you prosper and grow in this field.
    Keep up the good work mate!

  • @RKO36
    @RKO36 Před 9 lety +12

    You're always very good at explaining things, Prof! Thanks.

  • @Rajdsmart
    @Rajdsmart Před 7 lety

    I tried many Vdos out there, but yours is the best and was able to understand the concept very clear !! Thank you very much

  • @updownleftrightish
    @updownleftrightish Před 2 lety

    You are such a good teacher, I watched you as a student, I now watch you as a teacher and you hit home runs every time. Your videos are invaluable for many to fill that gap by giving the correct and detailed background of the theory.

  • @gromajor
    @gromajor Před 6 lety +1

    simple and clear explanation, I made some progress. thanks to you. :) have a great day.

  • @matthewoverton2206
    @matthewoverton2206 Před 5 lety

    Very good, clear, concise, easy to follow video. Thank you very much, its made it clear for me!

  • @zavierwu14
    @zavierwu14 Před rokem

    Beautiful explanation. Straightforward and great use of examples

  • @animiztothepoint3156
    @animiztothepoint3156 Před 5 lety

    i have read many articles on that topics but this was the best lecture which gave me more understanding than those articles

  • @stephensmith8743
    @stephensmith8743 Před 11 lety

    If only youtube was around when I was in engineering college. These videos would surely have been very helpful!

  • @pradeepkarna
    @pradeepkarna Před 9 lety +2

    GR8 ONCE AGAIN,,,,GUESS WHAT ..MY SEMESTER EXAM IS TOMORROW AND I AM LEARNING FROM UR VIDEOS...

  • @autogordel
    @autogordel Před 12 lety

    better explanation than any person or book gave me, thanks! I finally get it now.

  • @sanjeevkushwaha7614
    @sanjeevkushwaha7614 Před 7 lety

    THANK YOU SIR You reduced a one hour lecture into 10 minutes.

  • @arianabedi
    @arianabedi Před 11 lety

    I think there are only a few videos in your channel that I haven't seen. Right now I am WAY ahead of my mechanics of solids class :D thank you so much!

  • @hayaankhan3022
    @hayaankhan3022 Před 8 lety

    sir u have been amazing al the time i wish our professors were qualified as u are :)

  • @shamdamdoobley4266
    @shamdamdoobley4266 Před 7 lety

    dude I love you so much, my teacher for materials as sweet as she is, she is not good at explaining and I need your help

  • @CADable
    @CADable Před rokem

    Very nice explanation Professor. This lecture is excellent for undergraduate students.

  • @sugarlaura22
    @sugarlaura22 Před 5 lety

    Thank you! Great Video. Explained perfectly.

  • @olivermiddleton1100
    @olivermiddleton1100 Před 9 lety +3

    you are a saviour my man.

  • @ankitmahato7050
    @ankitmahato7050 Před 3 lety +2

    Thanks a lot sir. Love from India ❤️🙏

    • @purdueMET
      @purdueMET  Před 3 lety +1

      You're most welcome. It's great to hear from a viewer so far from where I live :-)

  • @purdueMET
    @purdueMET  Před 11 lety +2

    You are most welcome. I'm glad the videos are helpful. I like to collect CZcams hits. If you like these videos, please help me spread the word :-)
    - RMF

  • @singha2927
    @singha2927 Před 3 lety +1

    The good teacher is a teacher with excellent art skill

    • @purdueMET
      @purdueMET  Před 3 lety

      I hope this means that my drawing was OK. I think all Engineers should take art classes :-)

  • @isagumus1
    @isagumus1 Před 8 lety +3

    So well explanation thanks !

  • @DaniloSilva-wf2zp
    @DaniloSilva-wf2zp Před 7 lety

    Thanks for such excelent explanation!

  • @akshaysaraf6865
    @akshaysaraf6865 Před 8 lety +1

    u taught it soo well!!
    thank u sir!

  • @arjunrai4937
    @arjunrai4937 Před rokem

    Great teaching skills much better than here in India in 2022. Thank you professor.

  • @Johnvincentvivek
    @Johnvincentvivek Před 7 lety

    Sir thank you for making such videos i am a die hard fan of yours.

  • @suzelion6729
    @suzelion6729 Před rokem

    this video explanations is clear, big up
    im like super dumb in strength of material but this video actually helps

    • @purdueMET
      @purdueMET  Před rokem +1

      Thanks, I'm glad it helped :-)

  • @ranvijaysingh8671
    @ranvijaysingh8671 Před 6 lety

    Awesome video,thanks a lot Prof 😁😁😁😁

  • @jaffarkhan4487
    @jaffarkhan4487 Před 5 lety

    very helpfull video.... waititng for more videos

  • @adarshkorde7848
    @adarshkorde7848 Před 3 lety

    Nice explanation,Thanks.

  • @20hawkar10
    @20hawkar10 Před 12 lety

    For once we have a mechanics of solids teacher that does not make the assumption that everything will come to us naturally and goes through everything in a slow but steady manner ensuring the viewer is taking in a good amount of information. Looking forward to future videos

  • @Joules120
    @Joules120 Před 3 lety +1

    BEAUTIFUL!

  • @anuragdaksh4659
    @anuragdaksh4659 Před 3 lety

    Thank you so much sir ....
    This topic is cleared😊😊

  • @psycho4570
    @psycho4570 Před 3 lety

    SO helpful 🙏🏼 thanks

  • @BraveGamer2016
    @BraveGamer2016 Před 9 lety

    Thank u so much
    I have an exam tomorrow
    And u helped me

  • @prasanth-ky2pn
    @prasanth-ky2pn Před 7 lety +1

    thnq sir.... east or west u r the best....

  • @Hh12358
    @Hh12358 Před 4 lety

    Thank you professor.

  • @aliarind
    @aliarind Před 6 lety +1

    420th like! Great video, clarified the confusion for me. Especially love the correlation to the breaking of columns on an angle

  • @ImranHossain-pt3ye
    @ImranHossain-pt3ye Před 5 lety

    you are great sir....

  • @anoop150587
    @anoop150587 Před 11 lety

    nice learning videos .. particularly fr me bcoz i need to recall everthing learnt earlier

  • @amosmwangi1741
    @amosmwangi1741 Před rokem

    Thanks for this lesson

  • @sebastianospina131
    @sebastianospina131 Před 7 lety

    Really helpful, thank you!!!

  • @CandidlySubtle
    @CandidlySubtle Před 10 lety +1

    Thanks! I'm studying for the FE exam and I have no experience in Mech. Eng. The study guide does not explain concepts at all!
    Though, in the book, they solved the problem using the Transformation of Stress Equations. I don't understand which angle to plug in for those equations. If you ever do a video on that, please let me know. Thanks!

  • @romarssieverything9667

    that was great!!

  • @ibrahimraza394
    @ibrahimraza394 Před 2 lety

    thank you very much you make it vert convenient for student like me

  • @kenule4032
    @kenule4032 Před 11 lety

    thank you so much for this video. Was wondering if you have a video showing an explanation of stresses on an inclined plane in a two-dimensional stress system.

  • @abdirahmanfiishey5774
    @abdirahmanfiishey5774 Před 4 lety

    Thank you sir it is an amazing.

  • @Ajay795
    @Ajay795 Před 13 lety

    thanks, helped me with my work

  • @zVincoo
    @zVincoo Před 7 lety

    you are a god sir, thank you so much

  • @warrensze321
    @warrensze321 Před 10 lety

    Thank you very much!!!

  • @hariprakash1992
    @hariprakash1992 Před 6 lety +1

    hello sir.. that was great.. could u make a video on understanding moments nd forces in a piping system

  • @sagarkonnur2861
    @sagarkonnur2861 Před 6 lety

    Superbbbb.. ..

  • @sajithmusic
    @sajithmusic Před 10 lety +1

    thank you so much...

  • @knowledgezone8748
    @knowledgezone8748 Před 8 lety +1

    its too amazing thnax

  • @shenci9767
    @shenci9767 Před 4 lety

    thank you!

  • @margaritacarmona-carriedo7503

    EXCELENT VIDEO BTW!!!!! THANK YOU!!!!

  • @christinaMaher3
    @christinaMaher3 Před 3 lety

    what about if i have a bending force perpendicular to the block i have and a torque acting on the block(torisinal force stress )
    so how do i calculate these stresses on an inclined plane????????

  • @king0vdarkness
    @king0vdarkness Před 11 lety

    Dear Prof. RM French, Thank you for your videos they are very helpful! Please if possible could you do a cantilever beam connected to another wall, with pin joints at a section in the beam, or a similar problem and explain what happens to a beam if you(after solving it) add another moment. Thank you in advance. Best wishes!

  • @cwl6814
    @cwl6814 Před 9 lety

    thank you so much!!!

  • @arielamzalak8562
    @arielamzalak8562 Před 4 lety

    Awesome!!!

  • @purdueMET
    @purdueMET  Před 11 lety

    Thanks very much. It's great to hear that these videos have been a help to you.
    RMF

    • @ORion807
      @ORion807 Před 5 lety

      Sir can you please explain me how the cross sectional area become bh devided by cosin theta

    • @sadiasaeed9608
      @sadiasaeed9608 Před 4 lety

      sir can you please give me your whats app number. I need a help of person like you, in my thesis work. please its request. waiting for your positive response.

  • @samflockhart6615
    @samflockhart6615 Před 8 lety

    Thank you !

  • @user-hu3sq9pl1b
    @user-hu3sq9pl1b Před 3 lety +2

    Big like from Jordan

  • @asarebediako1330
    @asarebediako1330 Před 8 lety +1

    Thank you sir

  • @tamizhtamizh412
    @tamizhtamizh412 Před 4 lety

    Tq so much ❤

  • @91099Babar
    @91099Babar Před 12 lety

    Nice and thank you .

  • @kakbar10
    @kakbar10 Před 13 lety

    thanks again !

  • @Some-one99
    @Some-one99 Před 5 lety

    Hello sir plz try to deliver in clear tone . Anyway it's so good and easily visualize able

  • @souravsingh3025
    @souravsingh3025 Před 3 lety

    Thanks.

  • @XanderMande
    @XanderMande Před 6 lety

    Is it only applicable for forces who have the same magnitudes in both directions?

  • @abcarin0O0
    @abcarin0O0 Před 13 lety

    good video

  • @ORion807
    @ORion807 Před 5 lety

    Sir can you please explain why the cross sectional area become bh devided by cosin theta.....

  • @husnainhyder6713
    @husnainhyder6713 Před 7 lety

    nice 3d drawings

  • @dorairajvijayan8155
    @dorairajvijayan8155 Před 3 lety

    Sir, how does a Normal Force produce a shearing effect on an inclined plane?

  • @satyenderkumar9332
    @satyenderkumar9332 Před 9 lety

    Thanks a lot sir.

  • @rudhajassim9469
    @rudhajassim9469 Před 5 lety

    thanks a lot

  • @GenaEnSamIAm
    @GenaEnSamIAm Před 10 lety +1

    Ten out of ten!!!! Thank you!!

  • @kaleabembezaalem1637
    @kaleabembezaalem1637 Před 7 lety

    thanks

  • @loi7827
    @loi7827 Před 6 lety +1

    How did u find out the shear stress cross sectional area? 4:00

    • @juliocesarambriztapia7641
      @juliocesarambriztapia7641 Před 6 lety

      The cross sectional area is the same as the normal stress area. It is the component of the force what makes the difference

  • @arianabedi
    @arianabedi Před 11 lety

    Your very welcome :D

  • @aniketverma4736
    @aniketverma4736 Před 3 lety

    great

  • @fatimaezzahrahilal6699
    @fatimaezzahrahilal6699 Před 7 lety +1

    Sir why did u use both shear and normal stress here thank u

    • @juliocesarambriztapia7641
      @juliocesarambriztapia7641 Před 6 lety

      When you have an inclined plane, your axial force always have two components, therefore, unless it is 0 degrees both type of stresses are present in the element

  • @Rohitme99
    @Rohitme99 Před 11 lety

    thx sir

  • @Rohitme99
    @Rohitme99 Před 11 lety

    thxxxxx sir

  • @VintageLimage
    @VintageLimage Před 4 měsíci

    I still don't understand why A= bh/cos(theta).

  • @weasleypotter7105
    @weasleypotter7105 Před 11 lety

    Fn = Fcos0
    Fs = Fsin0
    Im usin trig but its not working can you explain it ?

  • @rmmalimet
    @rmmalimet Před 13 lety

    He's dreamy.

  • @sanjaykumaryadav9723
    @sanjaykumaryadav9723 Před 9 lety

    "please" also calculate stresses on an oblique section in a) two mutually perpendicular directions, b) subjected to simple shear stress c)subjected to direct stress in one plane and accompanied by a simple shear stress d)subjected to direct stress in two mutually perpendicular directions accompanied by a simple shear stress.

  • @emeldahowell3705
    @emeldahowell3705 Před rokem

    why is A=bh/cos theta

    • @emeldahowell3705
      @emeldahowell3705 Před rokem

      i get it now ...But how is A=AthetaCOStheta from geometry

  • @rupeshkumarpandey8727
    @rupeshkumarpandey8727 Před 2 lety

    Why bh/cosθ = A/cosθ ?

    • @purdueMET
      @purdueMET  Před 2 lety +2

      Because A=b*h. A_theta=A/cos(theta). Thanks for watching my videos. I hope they are helpful. I wish you the best in your studies :-)

  • @daysharing6061
    @daysharing6061 Před rokem

    best

  • @GenaEnSamIAm
    @GenaEnSamIAm Před 10 lety +1

    Like Like Like!!!

  • @Bendaua1
    @Bendaua1 Před 8 lety

    Man! You need better lightning.

    • @purdueMET
      @purdueMET  Před 8 lety

      I sure did. What you can't see in the video is the light stands I had in my little office. I never really got it right, though. This video is pretty old. Check out the newest ones with the cool LED lights - way better. Thanks for watching :-)

  • @hossamsaid3230
    @hossamsaid3230 Před rokem

    First of all better use X- Axis and Y -Axis not N & S , for simplicity. Secondly if we consider such case , then it shall be Cos Degree on S and Sin Degree on N . Thanks

  • @rajulanjewar8516
    @rajulanjewar8516 Před 3 lety

    Level he nahi hai

  • @MehediHasan-ku3po
    @MehediHasan-ku3po Před 5 lety

    thank you sir

  • @patricko911
    @patricko911 Před 7 lety

    thanks

  • @ahmedkorim7658
    @ahmedkorim7658 Před 7 lety

    thank you sir