Fixed end moments | fixed beams | structural analysis
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- čas přidán 2. 08. 2020
- All important cases of fixed end moments due to concentrated load, UDL, UVL, applied moments and effect of sinking of support are covered in this lecture.
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Thanks for explaining every concept in less time mam.
Mam thank you so much............u dont even know ki how much you helped me out...
All cases in less time ,well done..
Tq very much man ....It helps alot
Wahhh better u also make one super 30 batch and add me as your student ...mam🙏
Super explanation 🔥🔥
best lecture.
Thank you
Perfect 👌
First of all thank you so much .
Please , 🙏 , any PDF document to know how to find all these moments because it s so hard to learn these results by heart .
Thanks, much appreciated 🔥❤️
Welcome..
Thank you.nice presentation
Wlcm 👍
Very nice🎉dii❤
In case 10 and 11, how will we find delta by knowing the theta value
sir can i ask how to solve 3 moment fixed at one end 5 span beam
Appreciated by your effort ty
Thank you..
how 8 come in denumetor?
What if the uniformly varrying load is not half of its length?
Nice
Perfect explanation 😊
Good
In case no 9..if anticlockwise moment is acting the what will be change in formulae
Then Sign will be reversed. (negative)
From where "8" has come in first case ?
good explanation thanku mam
Welcome..
Mam How did you get those values ? Like in 5th case, uniformly varying load , you wrote WL^2/20 & WL^2/30 . Is there any formula to derive this fixed end moment ? I am not getting it exactly
All these cases are derived by analysis methods available and put in table for shortcut used in competitive exam .
Details study of its derivation can be covered into separate video.
@@selfstudygoals6371 will you make one ? I would like to watch. I had tried the derivation but my results are different than those values
can you explain how these values came?
Yes, by using method ,we can determine these values,
I will cover this in separate videos after completing the "hydraulic turbines and pumps " playlist.
Why fixed end i negative
Because it is resisting and opposite of applied one.
Mam u have not explained about when two loads are given in single span
Because it is for general and commonly used case.
Can u explain about a UDL over a distance a from left end and bat a distance b from right end?
You didnt explain how these values of fixed end moments are derived.
This video is about shortcuts,
Will explain in detail in another video.
What are the fixed end moments for a fixed beam of a length 'L', Subjected to a concentrated load 'W' at a distance 'a' from left end..??
Answer ?
It is second case . So please find it in the video.
no need to memorize, just one formula is enough
What formula
point load formula then just use integration
@@user-xj4ep5wb2j use the length to integrate? Can u give an examle pls?
Thank you
👍
Nice
Thank you..