3097. Shortest Subarray With OR at Least K II | Sliding Window | 2 Pointers | Bit Manipulation

In this video, I'll talk about how to solve Leetcode 3095. Shortest Subarray With OR at Least K I & 3097. Shortest Subarray With OR at Least K II
Learn 2 Pointers Basics & where to apply - • 930. Binary Subarrays ...
Practice Problem - • 713. Subarray Product ...
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About Me:
I am Aryan Mittal - A Software Engineer in Goldman Sachs, Speaker, Creator & Educator. During my free time, I create programming education content on this channel & also how to use that to grow :)
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[@IK-xk7ex]

I solved it by myself yesterday!

[@priyanshkumariitd]

Thanks, great explanation

[@shivamgurjar8979]

brilliant solution

[@ekanshgupta2930]

hnoest question how do you think of such approaches while the contest itself even if I was given like 10 days to solve this I wouldn't have thought of an approach like this one

[@mbm.editzz]

mera toh 3rd yr khatam hone ko aya hai abhi bhi nhi hua

[@chase.2595]

aryan mittal legend

[@kafuu1]

you are such a genius! I wish I can be as smart as you one day!

[@devanshsengar1877]

very helpful bro

[@tzuilee588]

Well explained and nice test case walk-through man!
Just a small suggestion: you're adding too much drama in your facial expressions on camera, kind of distractive lol

[@abishekupadhyay6357]

bro many many thanks to you. apne iss week 2 pointer itni ache se explain kiya ki i got this one almost instantly during the contest. You are amazing bhai.

[@akuma_168]

got stuck in removing OR value from starting pointer. I just suck at bit manipulation.

[@Anonymous____________A721]

@abhishek pls share your profile or your solution link
I am unable to understand any code

[@k.satish3663]

sliding window marathon

[@chase.2595]

yeah even daily problems are of sw

[@prakashnandan7337]

Thanks Aryan

[@mbm.editzz]

BRO ISSE NAHI HOSAKTA KYA
#define ll long long
#include
using namespace std;
class Solution {
public:
int minimumSubarrayLength(vector& nums, int k) {
mapmp;
int n=nums.size();
ll ans=1e8;
for(int i=0;i=k)return 1;
ll x=nums[i];
ll count=1;
for(int j=i+1;j=k){
ans=min(ans,mp[{i,j}]);
}
}
}
if(ans==1e8){
return -1;
}
return ans;
}
};

[@soham6473]

nhi