Understanding Bremsstrahlung Radiation - X ray Production

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  • čas přidán 27. 06. 2023
  • ➡️ LEARN MORE: This video lesson was taken from our X-Ray Production and Safety course. Use this link to view course details and additional lessons. cloverlearning.com/courses/xr...
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    ➡️ LESSON DESCRIPTION: This lesson’s objectives are to define Bremsstrahlung radiation and to identify the three essential requirements for creating x-ray photons. This lesson also briefly explains how different components and processes in the x-ray tube control the requirements for creating x-ray photons. This lesson also describes the process of creating Bremsstrahlung radiation and explains the factors that control the energy of Bremsstrahlung radiation as well as describes how Bremsstrahlung radiation can be visualized on a graph. Lesson Objectives: *Define Bremsstrahlung radiation *Identify the three essential requirements for creating x-ray photons *Briefly explain how different components and processes in the x-ray tube control the requirements for creating x-ray photons *Describe the process of creating Bremsstrahlung radiation *Explain the factors that control the energy of Bremsstrahlung radiation *Describe how Bremsstrahlung radiation can be visualized on a graph
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Komentáře • 38

  • @MrWilly-mm5rv
    @MrWilly-mm5rv Před 8 měsíci +13

    The best explanation I found on CZcams. Thanks a lot❤.

  • @farxeennn_n
    @farxeennn_n Před 2 měsíci +2

    im an Alevels student, it is so difficult to understand phys for A2. but you made it so easy.. Thankyou!!

  • @ScarlethAngeline25
    @ScarlethAngeline25 Před 5 měsíci +1

    Thanks, it helps me alot.
    The best explanation i saw in youtube.😊

  • @SCCDentalAssisting
    @SCCDentalAssisting Před 3 měsíci +1

    Excellent explanation!

  • @mohamedamr_1
    @mohamedamr_1 Před 5 měsíci +1

    Thanks a lot . It was so helpful❤

  • @irwo
    @irwo Před 6 měsíci +14

    Thx from medical college of iraq

    • @AliFarhan-hm4ls
      @AliFarhan-hm4ls Před 5 měsíci +1

      عراقي ابو الغيرة

    • @irwo
      @irwo Před 5 měsíci

      @@AliFarhan-hm4ls 😂😂😂

    • @AliFarhan-hm4ls
      @AliFarhan-hm4ls Před 5 měsíci

      @@irwo يا كلية؟

    • @irwo
      @irwo Před 5 měsíci

      @@AliFarhan-hm4ls كوفة

    • @AliFarhan-hm4ls
      @AliFarhan-hm4ls Před 5 měsíci +1

      @@irwo موفق ان شاء الله

  • @zeph7691
    @zeph7691 Před 28 dny

    great video, very clear and the animations helped a lot! x

  • @rachana-nk8ku
    @rachana-nk8ku Před 10 měsíci +4

    Thank-you so muchhhhh❤

  • @pavanajsridhar939
    @pavanajsridhar939 Před 5 měsíci

    superb! thanx a lot! best possible explanation !

  • @mbohhonorine8470
    @mbohhonorine8470 Před 10 měsíci +4

    This was so helpful. Thanks a lot

  • @chamasuksansirikul9376
    @chamasuksansirikul9376 Před 5 měsíci

    keep up the good work!

  • @alyssamaeamolopido1612
    @alyssamaeamolopido1612 Před 7 měsíci +1

    Thank youuu ❤

  • @user-sk3ig6yq5n
    @user-sk3ig6yq5n Před 9 měsíci +2

    Thank you for this ❤

  • @user-xl7xm6vm4f
    @user-xl7xm6vm4f Před 6 měsíci

    شكرا جزيلا لك كان هذا مفيد جدا
    الكلية الطبية في سوريا ❤️❤️

  • @ch_arbaz_yt
    @ch_arbaz_yt Před 7 měsíci

    Salam very good concept

  • @ohanwenwachiamaka3078
    @ohanwenwachiamaka3078 Před 9 měsíci +1

    Thank you so much 💖

  • @JavanKibet-lv7kw
    @JavanKibet-lv7kw Před 2 měsíci

    THANK U MONSIEUR

  • @mreatboom1314
    @mreatboom1314 Před 4 měsíci +3

    Why this energy is not transfered to the nucleus by moving it ?

    • @blackalgae370
      @blackalgae370 Před měsícem

      I will preface this by saying i am not an expert, but; I think, it because atom generaly have a neutral charge. it has positvly charged protons and neutral neutrons in the nucleous and negativly charged eletrons in the electron shell. If an electron hits a neutraly charged atom and interacts with it then it will become negativly charged, and a negative charge will push away negatively charged particles. The same way a magnet will be atracted the metal and the negative end of a magnet will attract the positive side of another magnet but push the negative end away. On the atomic scale this would mean that if an electron shot into an atom and it locked into the electron shell it would knock another electron out of the shell and the too would produce an electromagnetic wave. If however it was the nucleus that recieved a transfer of energy and it recieved the impacting energy then the excited atom would release the energy by throwing out an electon or by altering the configuration of its electron shell also releasing a tiny busrt of energy in the form of heat or light. At least thats how i think it works.

  • @rahafalsultan4999
    @rahafalsultan4999 Před 7 měsíci +1

    Thank you ❤

  • @lilianemccallin1143
    @lilianemccallin1143 Před 7 měsíci +2

    how can electron have an energy of 0 keV, as its rest mass is 500keV? Does this mean the electron has disappeared completely ?

    • @miaehatamm8936
      @miaehatamm8936 Před 6 měsíci +1

      i think it is only referring to the kinetic energy that is imparted by the voltage! the electron would still have rest energy

    • @AliFarhan-hm4ls
      @AliFarhan-hm4ls Před 5 měsíci

      It is the kinetic energy

  • @emilmohan1000
    @emilmohan1000 Před 5 měsíci +1

    any other way of x ray production?

    • @cucciafr68
      @cucciafr68 Před 2 měsíci

      You can get characteristic xrays from when the incoming electron knocks out an electron from one of the shells of the atom. To stabilize itself, an electron from a higher shell moves to that vacancy. To balance the energy difference the atom can release an xray of specific energy. If you look back at the graph it shows of the bell curve it has a large spike. That would be from the characteristic xray.

  • @LinusFeynstein
    @LinusFeynstein Před 2 měsíci

    Sehr schöne Erklärung. However, please pronounce Bremsstrahlung as in „BRAMMS-STROAAA-LOONG“. The stress is on the second syllable.

    • @cucciafr68
      @cucciafr68 Před 2 měsíci

      I cringed trying to pronounce this in front of my German colleagues.