Remainder Theorem - Polynomials | Class 9 Maths
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- čas přidán 5. 09. 2024
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✅ In this video,
✔️ Class: 9th
✔️ Subject: Maths
✔️ Chapter: Polynomials
✔️ Topic: Remainder Theorem
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Remainder theorem 9:00 to 13:31
Proof 13:50
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Sir I have a doubt
Previous class you told
Degree of remainder will always be less than of divisor
But when we divide 9 by 2
Degree of divisor i.e. 2 is 0
Degree of remainder i.e. 1 is 0.
But 0 is not less than 0
Thank you for pointing this out! You are absolutely correct. The degree of the remainder will always be less than the degree of the divisor when we divide polynomials. In this case, we divided 9 by 2, so the degree of the divisor (2) is 0 and the degree of the remainder (1) is also 0. However, since the remainder is not equal to 0, we can say that the degree of the remainder is still less than the degree of the divisor.
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12:45 x - α = 0 kyo liya ??? sir
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sir what if verification of remainder in remainder theorem isnt correct??....is it means that it is wrong remainder???
It will always be correct. Either you have done mistake in calculation .
now you are in 10th class
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Sir why will we solve (x-a)=0.
x-0= a
x-a=0 i hope u'll understand...
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Sir remainder theorem is easier for me,now😇
Jitna log cilata ha kii polynomial hard hota ha but this is very easy chapter ☺️☺️☺️padhna wala student hona chiya 🤣🤣
Using the remainder theorem, find the remainder, when p(x) is divided by g(x), where p(x) = x3- 6x²+2x-4, g(x) = 1-(3/2) x. How to solve this sir
What is x3 ?? . It is x cube or 3x
@@vindheshwarisharma4516 x cube
Uhh I think it's 2/3
Btw where did u get that question from?
"""ARTI"""
Already written in the question.............
Solve it by remainder theorem.........
@@bruhman1668 but my answer is -90/27...............
Plz check it again............. or may be my answer is wrong ..............😢😭
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Thnkuu sir😊💫
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Well explained
Very nicely explained sir 👍I have no doubt in remainder theoram now
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