Frequency Response : RLC circuit

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  • čas přidán 5. 09. 2024
  • Example RLC Problem: Find the transfer function and determine if it is a low-pass, high-pass or a band-pass filter.

Komentáře • 29

  • @qurat1920
    @qurat1920 Před 7 měsíci +6

    So amazing...it is after 12 years after my engineering I understood the concept today because of you.
    Thank you so much...

  • @tensorbundle
    @tensorbundle Před 4 lety +8

    Dude you have an amazing talent of explanation skill

  • @manojkumarpeesa7912
    @manojkumarpeesa7912 Před rokem

    I found this video rarely with this much good explanation

  • @petertwiss356
    @petertwiss356 Před rokem +1

    solid refresher

  • @CollectvlyUnconsious
    @CollectvlyUnconsious Před 5 lety +7

    Best RLC so far, I am confused as why you did these in rectangular and not polar?

    • @ENGRTUTOR
      @ENGRTUTOR  Před 5 lety +3

      Rectangular and Polar are just two different ways of looking at the same complex number. It is a matter of personal preference and what might be easier given the problem. This problem was about first finding the transfer function

  • @nymoz3587
    @nymoz3587 Před 9 měsíci

    Fantastic Video.

  • @jorickleferink7065
    @jorickleferink7065 Před 4 lety

    The last term of the transfer function magnitude calculation (wL)^2 should be -(wL)^2 (with a minus in front) because you square the j.

    • @ENGRTUTOR
      @ENGRTUTOR  Před 4 lety +1

      Actually the magnitude of a complex number of the form P+jQ is sqrt(P^2 + Q^2). j is the y-axis.

    • @jorickleferink7065
      @jorickleferink7065 Před 4 lety +1

      @@ENGRTUTOR Oh dear. You're right!

  • @juliaraquelpereira9657
    @juliaraquelpereira9657 Před 4 lety +1

    Good night teacher, can this deduction be made by a laplace transform?

    • @ENGRTUTOR
      @ENGRTUTOR  Před 4 lety +2

      Yes, you can. The 'jw' in a transfer function is the same as 's' you would get in the Laplace Domain

  • @AKPMedia360
    @AKPMedia360 Před 5 lety +1

    thanks it helped me.

  • @httm241
    @httm241 Před 4 lety +1

    Can this work for a dc voltage?

    • @ENGRTUTOR
      @ENGRTUTOR  Před 4 lety +2

      DC is just as special case of AC with frequency of 0Hz.

  • @ravioliformuoli520
    @ravioliformuoli520 Před 5 lety

    Would the process be the same if the inductor was replaced with a resistor? How much different would it be?

    • @ravioliformuoli520
      @ravioliformuoli520 Před 5 lety

      And that both the resistors are of different values?

    • @vector4100
      @vector4100 Před 5 lety

      @@ravioliformuoli520that would turn in to a modified low pass filter, you can see examples of it as low pass filter with a load resistor also

    • @ENGRTUTOR
      @ENGRTUTOR  Před 5 lety

      Yes the process is the same. It doesn't matter what the elements are --- the transfer function is Vout/Vin and as long as it is a circuit that you can put in a voltage divider type configuration shown in this example the Vout/Vin = ZOUT/Ztotal.

  • @kenneth5256
    @kenneth5256 Před 3 lety

    Would this work for a series RLC circuit?

  • @andrewmutizamhepo1124
    @andrewmutizamhepo1124 Před 3 lety

    Infinity squared is infinity and then infinity divided by infinity is undefined

    • @ENGRTUTOR
      @ENGRTUTOR  Před 3 lety +1

      Since we build realistic circuits - think of Infinity as a VERY LARGE frequency value.

    • @andrewmutizamhepo1124
      @andrewmutizamhepo1124 Před 3 lety

      Okay. What change does it bring?

    • @penelopeannetsiblakis9415
      @penelopeannetsiblakis9415 Před 9 měsíci

      @@andrewmutizamhepo1124 that square root infinity on the fourth power is squared infinity

  • @andrewmutizamhepo1124
    @andrewmutizamhepo1124 Před 3 lety

    can anyone explain to me how the j is disappearing