7.1.1 Example 2
Vložit
- čas přidán 28. 08. 2024
- 7.1.1 of Griffith's Introduction to Electrodynamics 2nd Ed
Calculating the relationship between the current and potential between concentric cylinders with a conductor between them.
Next: • 7.1.1 Ohm's Law (Part 2)
Previous: • 7.1.1 Example 1
Chapter 7 Playlist: • Introduction to Electr...
Introduction to Electrodynamics Playlist: • Introduction to Electr...
Your videos are all super helpful, my professor actually gave us a link to your channel at the beginning of the semester so these have all been super helpful. Thank you for making these
That is simply ridiculous. I am humbled and amazed. I hope things go well in the course. Physics can only be self-taught, through many hours of problem solving and deep thinking. Professors, textbooks, and videos like this can only help spur thinking and ideas.
Crystal clear. Students will be happy to see this.
+Baasansuren Batsukh Thanks.
I would like to say that your videos have not only saved my grade for this course, but my understanding of electrodynamics as a whole. I truly could not thank you enough!!
how do you know theres a linear line charge density?
I would make a screen edit thing-E showing or saying that you solved for lambda in the potential equation and subed it in to the current equation. You mentioned it quickly in the video and I heard it but it took a few minutes to realize what was going on. Also what information is being lost when you get rid of lambda?
agreed very confusing
agreed
Why did we divide by area, isn't gauss law just q/epsilon_not
Why is it lamba.L and not roh*pi*a^2*L in the numerator? Because its clearly a cylinder with volume charge density.
Thanks bro
Superb👌
Asslam o alaikum sir...iss mai Lamda ksy liya hai?
Lambda is linear charge density
😍