The lecturer could have done as you described, but what he actually provided was much clearer and simpler: v = Bc Since B = A M^-1 v = A M^-1 c Done. What you gave takes a very roundabout route. Also the lecturer would have to explain that A^-1 = (BM)^-1 = M^-1 B^-1, as your working implicitly depends on it.
really awesome!!!
Sir I would suggest you to use onenote for slides. It doesn't cause random lines while you write using a pen.
v = Bc
v = A A^-1 B c
v = A (M^-1 B^-1) B c
v = A M^-1 c
I'm not sure what why 41:00 was a mistake...
You have to preserve the order of matrix multiplication for a correct result.
( M^-1 B^-1 ≠ B^-1 M^-1 )
The lecturer could have done as you described, but what he actually provided was much clearer and simpler:
v = Bc
Since B = A M^-1
v = A M^-1 c
Done.
What you gave takes a very roundabout route. Also the lecturer would have to explain that A^-1 = (BM)^-1 = M^-1 B^-1, as your working implicitly depends on it.
@@sa8212 Nope. Eduardo did it fine.