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Spring Force and Spring Balance | NLM for JEE & NEET | Class 11
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- čas přidán 15. 08. 2024
- Topics covered in Lecture 24 of Spring Force and Spring Balance in chapter Newton's laws of motion for JEE & NEET in Onion Physics are listed below with timestamps:
Timestamps:
00:00 Spring force & Spring Balance
01:32 Man exerting force on a spring
02:25 Concept of Spring forces
06:11 Spring Mass combination
08:10 Springs connected in series and parallel combination
09:32 Spring cut in N identical parts
10:45 Elongation of springs connected in parallel under equilibrium
12:15 Spring in a string of pulley block system
15:02 Elongation in springs in pulley block system
16:45 Understanding Working of a Spring Balance
19:05 Spring balance inside an elevator. Reading of spring balance when elevator accelerates upwards
20:29 Reading of spring balance when lift elevator acceleration is in downward direction
There are countable fundamental concepts in the section spring force and spring balance of Newton's laws of motion from which questions are asked in JEE & NEET.
Onion Physics is a FREE You Tube series for High Quality Online Physics Classes for JEE & NEET preparation. In this series, complete physics is taught through Illustrations based on different physical situations. JEE Main and NEET are competitive exams in which about 50 percent of questions are based on applications of physical situations and the rest are based on memory and fundamental analytical concepts. In JEE Advanced all questions asked are purely on applications of concepts in simple as well as complex experiments and physical situations. Onion Physics is focused on learning through examples and different physical situations which makes it the best online jee coaching available in Physics.
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Sir please teach little slowly and from basics ,do not skip anything p,ease sir in onion physics lectures
I cannot understand in concept videos
Bhot mja aaya sir...thanks a lot 💞💞💞
HWIL 1) Ans ; 200N
let a be the acc. of mass attached to spring balance
and let T be the tension in the string
equation:
T - 4g = 4a
in the question it is given that : T = 4kg = 40N
so a = 0
equation of second mass
acc . due to pseudo force = F / M = A : M = total mass
equation for second block
4A - T = 4a = 0
4A = T = 4ON
A = 10m/s^2
A = F/M = F/(12+4+4) = F/20 = 10
F = 200N
First Answer :200 Newton,. 2nd Answer :12kg,24kg respectively
Derivation of first answer:. Acceleration=F/12+4+4(on system).
Since reading is 4 kg implies the both 4kg block will be at rest thus 4a=T=40Newton
a=10m/s^2 implies F=200Newton
Derivation of 2nd answer:
Make equation of both the blocks as such you will get:(200-T=40a)*2______eq(1)(note that we have multiplied it by 2 for future reference
2T-200=20a______eq(2). Adding both we get a=2m/s^2 and T=120 Newton
Now reading on spring 1 is T/10=120/10=12kg
Reading on spring 2 is 2T/10=240/10=24kg
Hope you got it
Wouldn’t there be a pseudo force on upper block?
@@doitrightwithella9299 yes there will be pseudo force on upper block definitely if you are in frame of moving block; that is actually balancing the tension caused due to string!
@@AdityaSingh-qf8dk understood now thanks
How can we guarantee sp2 block will go up?
@@jyotijumde7019 there are two answer to your question:
1)you can observe that the tension on sp2 is 2T while on sp1 is T thus sp2 goes up since both block have same masses ,however this observation doesn't helps always.....
2) if you want you can consider that sp2 goes down and make all equations at last you will found that the acceleration is negative ,this means acceleration is in opposite direction of what we have supposed!
--- These lecture will filter yur concepts to a next level ..and boost our confidence
No lol 😂 these are so basic they won't even get you godd enough for boards level, let alone competitive exams
@@sleepyfella Lol then u must be doing PHD for jee advance i guess XD coz iska bhar kuch nahi hai and baki alag question practice krke concept b sikhna milte
@@sleepyfella joke of the day, i can see from your statement that you dont know how to study, poor you!
@@sleepyfella RANK?
@@ShivamPandey-wf2pj Not found probably
Why all extraordinary teachers teach only physics 😭😭😭😭😭😭😭😭
Because physics is extraordinary.
@@tejasvi9413 biklul fark pdta hai
Becoz physics is an extraordinary subject
Because only extraordinary people can understand and teach physics
Kyuki tum baaki teacher ko jaante hi nahi ho
Sir you do great work for us.when I read your book earlier then I see your lecture there is no doubt remain.thanks for giving such awesome lecture and book❤️❤️❤️❤️❤️❤️
22:25 (1)200N
(2) 2i) 12kg 2ii)24kg
exactly Right 😊
Sir can you make onion physics for 12th also
I think iske baad vohi aayega
THANK YOU SO MUCH GURUJI..!! CHARANSPARSH GURUDEV JI..!!❤❤🙏🏻🙏🏻
appreciating your hard work sir......
22:20 force= 200N
In HW 1--As hanging block(4kg) is not in contact with 12kg block,will normal force due to 12kg block act on it ?nd if not,pseudo force causes acceleration with respect to 12kg block!!!
Same doubt
@@shreyanshsrivastava2799 dude same yaha sablog 200 bol rhe
bhai aapka enginerring chal rha hoga
best physics teacher itw
Thanksss sirrrr
1st answer will be 160 N do the fbd of 12 kg block tension will act leftward and f rightward as acc is 10 m/s square we can write F-T = 120 therefore f is 160 n
Sir now dpp are not provide by you
Only relative motion complete Please dpp continue kar dijiye
motion in 2D bhi aagayi bro do it
@@divyanshuverma552 ok bro
Nahi mai nlm ke liye bol raha tha
Thanks a lot sir 🙏🙏🙇♂️🙇♂️🙇♂️
is the answer of 1st HW question is 120 N
HWIL 1) 100N
HWIL 2) 12kg. And 24kg
Is it correct ?
Is it right ?
First q’s answer should be 200N ig
How?
@@Ajitkumar-wj7ev see @aditya singh’s comment
Ok
The only of the uncles who is so much educated 🎓 ❤🙏
Wtf?
Sir ko uncle nahi bolte bro
Guruji bolte hai
13:33 Sir apne string tension ko spring force ke barabar kaise keh diya?
22: 33 ,answer is 16 newton
Thankyou sir
sir kya ye lecture me puri content i really can't believe ki itni jaldi aap kaise chapter khata kr dete ho jaha log 9-10 ghante ki video bante he.sir plzz ye bata dijiye
Bhai aapko sirf in lectures pepended nahi rehna chahiye...sir ne kaha hai book ko refer karte rehne ke liye...and jo time dusro ke lectures me aapclass illustrations solving and understanding pe lagate ho, uss time ko aap book ke illustrations pe lagao...in lectures ka complete benefit lene ke liye don ek saath karte rehna hai...
Sirr,,upp keu video ko unlisted karke dalto
Taki dedicated students apne aap ko scheduled rkhe 🙂
Sir apka book. Amazon pe hai kya??
Khud dekh lo na jaake
Which is better concept vedios Or onion physics
Concept videos
Sir, please aap cutting of string and spring bta dijiye
Dhayan se lec dekh
Shes looks good in luffy zoro sanji chopper robin and vivi and dont forget the best koby
Tf
I am refer to lactur for teacher
HWIL- 200N HWIL-1-12KG 2-24KG
Hey can you tell me , hum pure ko ek system maanke net external force equals ma kyu nhi Kar sakte ( usse a 10 aara hai kyunki Maine surf mg consider kiya dono ka kyunki tension toh internal forces hai)
Sir advanced 2021 walo ke lie kuch start kre plaese.amazing amazing and amazing
Watch advanced illustration 👍
@@kunaljbk is that sufficient for adv...
@@asabhashiitian1321 yes that is sufficient . concept videos bhi dekh lo
@@YdvSyAero ok thanks
Thank u sir ❤️
Jo ye board saaf kr rha h iska naam kya h . Jispe pg likha hhua h
Bahi wo computer 🖥️🖥️ hai
@@ShubhamKumar-fo4 ha wo to pta h par sir jo naam leke bula rhe kya naam bol rhe h
@@winggsss. pogi
@@winggsss.kuch nhi 😂
You watched this 5 months ago? Abhi konse class mein ho tum?
Ans is 200 N
40N
15:20 why the system can't move?
Because spring is fixed
@@manassaini5239 thank you for your kind comment. My entrance exam is over 😌
@@swastiksarkar3360 I hope you have succeeded
@@manassaini5239 yes ☺ thank you
12:41 how come two blocks move with the same acceleration?
Bcz they boht are connected with each other
@@mashritatripathi4245 they are connected by a spring ... not string
@@jayendrasharma9133 when the string gets stretched to it's full potential it'll start acting similar to a string
Because string is considered here a rigid body as it is unextensible then the distance covered by block 1 and block 2 will be same.
Same doubt but abb clear ho gya thanku
10:44 how 1/Keq is equal to N/Ki pls explain?
Equal parts LCM ki aa jayega and 1+1+1+.....N
=N/ki
Sp2 block will go up how can we guarantee?
u can take any direction of acceleration if on solving u got negative ans it does means that direction of acceleration is opposite to what u have taken.....but the value will be same only direction changes because of negative sign
Movable Pulley
HWIL1=200N
HWIL2=Sp1=12kg
Sp2=24kg
Getting same ans
Bro ha 1 me system ka mass is 16 kg !..so 16×10 will be 160 N
@@aspirant_IIT-KGP 20 kg hoga system ka mass 12kg ka bada block aur do 4kg ke chote blocks
Kuch samajh nhi aya.....
Tumhari bas ki baat nhi hai
H.WIL1=200
12 kg and 24 kg
H.WIL2=12kg and 24kg
HWIL1=200N
HWIL2=(SP1=12KG),(SP2=24KG)
website isnt working ashish sir
clear cache and cookies and then try it will work.
ans 1 is 200N .ans 2 is 12kg,24kg
Jai Shri Ram
pdh le bhai ye sb likhne se ghar nhi chlega
200N,12Kg,24Kg
Bro i am not able to get 12kg and 24kg can you tell me process
@@Siddharth2407 you have to find tension in rope only nothing more and can also watch onion physics moving wedge block vedio
@@Siddharth2407 can you plz help in finding answer 2 of last lecture
@@nitin2749weighing machine wlaa????
@@Siddharth2407 hm
This professional never tells his secrets making us fool
He teaching theory only 😂😂😂
Not practical visualising
This is biggest mistake in our education 😢😢😢
Answer 1. 200N
Answer 2. 12kg and 24 kg
No bro
acceleration aaya hoga (-2g/5)...is negative sign ko ignore Mt Karo😅😅...Final answer would be 12kg and 24kg
Aman yadav right bro I do not take - sign now I got right answer.
How did you get the hwil-1 ,I am not getting the first one ,pls give some hint
@@vatsal512 hmm sure
Look
Question is demanding for value of F for which spring reads 4kg
Okk
Now
Applied force (F) = some of all masses times net acceleration of system
Here Say, F= 20kg times acceleration
Now
Look for upper block
As system moves with "a"
Upper block also moves with "a" as a part of system
And the driving force is tension
So
T= 4×a
Or
T=4(F/20) { a=F/M}
Or
F=5T
Now spring reads 4kg implies
T/g is 4kg...
F= 5T
=5(4×g)
= 200
Hope it helps👍🏻
@@cse-10-amanyadav77 thanks