Calculus Help: Linear Differential Equations - Integrating Factor - y'- y=2te^(2t) ,y(0)=1
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Here is the technique to solve this question and how to find them in step-by-step
#Technques
#Integrals
#Integrations
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At 4:31, you should write y = 2t e^(2t) - 2e^(2t) + Ce^t not 2t e^(2t) - e^(2t) + Ce^t. I made minor mistake in here. So C = 3
You made an error C=3 not 2
Ok, I got it.