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That was difficult...
Another approach: (√8^√2) / (√2^√8) = -------------------> √8 = 2√2 --------> √8 2^(3/2)2^(3/2)√2 / 2^(1/2)^2√2) = 2^ [3/2 * √2 - 1/2 *2√2] =2^ [3/2(√2) - √2] =2^ [(1/2) (√2)] =2^(√2/2) = 2^(2/2√2) = 2^(1/√2)Answer: D
That was difficult...
Another approach:
(√8^√2) / (√2^√8) = -------------------> √8 = 2√2 --------> √8 2^(3/2)
2^(3/2)√2 / 2^(1/2)^2√2) =
2^ [3/2 * √2 - 1/2 *2√2] =
2^ [3/2(√2) - √2] =
2^ [(1/2) (√2)] =
2^(√2/2) = 2^(2/2√2) = 2^(1/√2)
Answer: D