Russian Maths | Olympiad Maths | Math Simplification for X?

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  • čas přidán 8. 07. 2024
  • A Wonderful math olympiad question. How to solve math problem.
    #maths #easymathtricks #olympiad

Komentáře • 2

  • @user-dq3uh6ee5w
    @user-dq3uh6ee5w Před 2 dny

    -1+_i, 1+_i.

  • @key_board_x
    @key_board_x Před 5 dny

    x^(4) = - 4 ← as negative number → complex number to be used
    x^(4) = 4i²
    x^(4) = (± 2i)²
    x² = ± 2i
    x = a + ib → where: a ≠ 0 and where b ≠ 0
    x² = (a + ib)²
    x² = a² + 2abi + i²b²
    x² = a² - b² + 2abi → recall: x² = ± 2i
    a² - b² + 2abi = ± 2i → by identification: a² - b² = 0 → a² = b²
    2abi = ± 2i
    ab = ± 1
    First case: a = 1 → b = ± 1
    x = 1 + i ← this is the first root
    x = 1 - i ← this is the second root
    Second case: a = - 1 → b = ± 1
    x = - 1 + i ← this is the third root
    x = - 1 - i ← this is the flourth root