04.3-1 Statically indeterminate shaft - EXAMPLE

Example Problem:
Find the maximum shear stress in the statically indeterminate solid shaft using the force method.

[@Erowens98]

You explain how this works very well. Thank you.
I've seen a few other sources so far, but they just go through the steps without actually explaining why they are the way they are.

[@thomasbrunner8516]

Mechanics ASMR

[@user-ph7yn6we9u]

😅😅😅😅😅😅😅

[@haneenmomani2543]

This was absolutely helpful, thank you so much.

[@tolga9311]

this video is quite helpful, thanks.

[@saurabhpatil5101]

thanks a lot, cleared my doubt

[@mdminhajalamdip4372]

nice

[@king0vdarkness]

Thanks for the video. I had a quick question. I have a problem where there is a bar ABCD of circular cross section having a diameter of 50 mm. It's fixed at A and D ends and carries two concentrated torques at B (1000Nm) and C (1500Nm). a to b is 2m and bc is 1m and cd is 1m.
The solution I have goes through in a similar way, from equilibrium Ta +Td = Tb + Tc. And from compatibility (Theta-B)AB = (Theta-B)BC + (Theta-B)CD. As GJ is a constant for this equation I would have the compatability equation become Ta(Lab) = Tb(Lbc) +Tc(Lcb). However, the solution I have instead states Ta(2) = (Td-1500)(1) - Td(1). Please may I ask how they get this? Any help would be greatly appreciated.

[@MisterBinx]

The drawing makes it look a bit like the 325N*m is applie at A. Other than that it's a great video.

[@safwanasghar3203]

What will happen if half of the shaft is hollow

[@shubh074]

Then J change..

[@lotrofan100]

No difference to the torsion force, because 'J' (polar moment of inertia, related to crosssection) is canceled.