NECO Physics Practical 2024 (Electricity MANIPULATION)

How to manipulate readings from theoretical knowledge without performing the practical.
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#resistivityofwire

[@user-st4ns7pe6o]

Thank you very much ma. Can you pls show the manipulation when connected in parallel

[@biyamasam]

Well done ma, thanks and God bless you for your selfless service

[@JoynuelPhysics]

Amen, bless you too

[@user-rz7hc9de9w]

​@@JoynuelPhysicsi need answer physics tomorrow ❤❤❤❤❤❤ pls

[@samsonolabode66]

Yes ma'am the value of constantan wire is 5.1×10-7

[@rsquareokeke524]

What you wrote is still the same value to what she wrote.

[@nosaevbagharu1346]

Thank you ma.

[@JoynuelPhysics]

Welcome 😊

[@NazyStudio25]

Thanks alot ma... You just saved a life☺️☺️

[@JoynuelPhysics]

You are welcome 😊, thank God.

[@AminahAliAhmed]

How do we then find the current if the connection is parallel not series

[@prayerwatchforNigeria]

I think for parallel connection, the total resistance is going to be R1xR2 divided by R1+R2

[@ClementaboveOsagie]

😮, you nailed it!

[@JoynuelPhysics]

Thanks so much

[@NdidiChiokwa]

Nice method .

[@JoynuelPhysics]

Thanks so much

[@OWADUNNISEFIU-nj3wc]

Thanks for job well done, pls come up with the circuit diagram for more explanation.

[@JoynuelPhysics]

Thanks so much

[@noblemanquakers7274]

Pls dear friend, isn't V supposed to be the voltage drop across the two ohms resistor?

[@Gamerboi0407]

Well done ma

[@JoynuelPhysics]

Thanks so much

[@georgeugwoke5394]

❤ Thank you ma.
I'm gladly beneficiary of of your educative channel...
May the glory of our Heavenly Father 🙏 continue to rest upon you and upon us all in the of Jesus Christ 🙏.
I KNOW THAT THERE'S JOY IN EVERY SOUND, WHEN THERE'S LOVE AT HOME 🏡

[@JoynuelPhysics]

Amen, thanks so much. I really appreciate you ❤️

[@UcheKonkwo-is1hz]

Good work!
But you omitted the internal resistance of the cells.
E = I(R + r ).

[@ultimate2949]

And how/where would that be applied in the formula

[@rsquareokeke524]

There is no room for the use of internal resistance.

[@AkogwuMoses-cc9qd]

Wow thanks..very helpful..
It seems this manipulation addresses a series connection of the constantan wire and the 2 ohm resistor... What if the connection is different or perhaps i haven't fully understood?

[@JoynuelPhysics]

U re welcome. Don't worry, l have done the practical, expect the video soon. U will understand it better in the main video. The manipulation is an eye opener. Will soon upload the practical video. Thanks.

[@AkogwuMoses-cc9qd]

Okay.. thanks

[@Jesusmedia293]

Thank you ma God bless you ma
Pls ma is the meter rule used in place of potentiometer?

[@JoynuelPhysics]

No, this is the calculated one

[@rsquareokeke524]

(4.9 X 10^-⁷)/(1.64 X 10^-⁷) =2.99 X 10^-⁷--⁷ =2.99 X 10^-⁷+⁷ =2.99 X 10^⁰ 2.99 X 1 = 2.99 ohm metre-¹. You are doing well dear, we know it is a common mistake anyone can make. I love your empirical dexterity, keep it up👍

[@JoynuelPhysics]

Thanks so much

[@Goldcollection21]

Thanks for all you do ma. Pls how much is the constantan wire and how can i get it

[@JoynuelPhysics]

U re welcome, I'm not sure because we have it already in the lab .

[@Goldcollection21]

Okay thanks

[@UcheKonkwo-is1hz]

The resistivity is correct
= 4 . 9 x 10**_7

[@emmanuelochepaul]

Well done ma, but is there any specific voltmeter for the practical because there different types of voltmeter

[@JoynuelPhysics]

U re welcome.
0 to 3V Voltmeter is what we are expected to provide. But 0 to 5V voltmeter can serve the same purpose if that is the one you have.

[@bseedacademy5945]

Weldone ma. This is a very good job.
I think you did not take into consideration the internal resistance of the cells in your manipulation.

[@JoynuelPhysics]

Yes, l considered it to be negligible.
But I have done the video for the main practical. Here is the link
czcams.com/video/uVPexD1FMSk/video.htmlsi=rcv6xGIeiNQxawAY

[@phymathsscientistglobalcha89]

There is nothing concerning internal resistance here. Not for this Neco exam

[@phymathsscientistglobalcha89]

You tried young lady

[@edetumana3152]

Pls ma, is the resistivity of Constantan wire 49×10^-8 ohm meter or 4.9×10^-8ohm meter?

[@JoynuelPhysics]

49 × 10"-8 ohm meter

[@rsquareokeke524]

It is very very correct. You can write it as 4.9 X 10^-⁷ or 49 X 10^-⁸. She is correct 👍👍

[@Idoko_Ifeanyichukwu]

Greetings. Please, the result of 49exp-8 all divided 1.64exp-7 should be 2.99 ohm per metre and not 0.299 ohm per metre. Check it, please. Thank you. You are doing well.

[@JoynuelPhysics]

Thanks so much ❤️

[@user-vx8ok9hx1n]

Ma is the 3V a constant

[@ultimate2949]

Yes. In the yellow paper we were asked to get a power source of 3v

[@temitopealabi1770]

well done madam

[@JoynuelPhysics]

Thanks a lot

[@Omez213]

You made a mistake in the calculation of resistivity to area. It is 2.99 ohm meter.

[@JoynuelPhysics]

Thanks for the correction

[@chiomachisom1390]

So is the calculation wrong

[@olumideaina8135]

Nice one má. But from my own point of view, you didn't consider the internal resistance of the cell. Maybe I'm wrong

[@JoynuelPhysics]

Thanks so much, it's considered to be negligible here.

[@herolivesnu]

It is not negligible in the real sense of the practical. Just that they are not marking for accurate answers. Examiner marks the trends. In terms of the trends, I believe she is correct as supported by the theory.
Those that perform the practical, no manipulation of results, seems to get the opposite of the trend.
Theory states that as L increases V should also increases

[@noblemanquakers7274]

That can be negligible

[@rsquareokeke524]

There is no compulsory room for the internal resistance.

[@herolivesnu]

Based on the set up of the NECO real exam question, I am sorry to tell you that your trend is wrong. As the length increases, voltmeter reading decreases. Ensure that you try and see this year NECO SSCE physics practical marking scheme to confirm this.

[@user-st4ns7pe6o]

I think you made a slight mistake ma. In the calculation of Resistivity/area. The answer is 2.99 and not 0.299

[@JoynuelPhysics]

Thanks so much