Geez, I like long videos... Seriously thanks for the topic because I have been meaning to experiment with the scheme. Sooner or later I'll grab some screen shots of your experimental circuit and have a go with the concept. I am always looking for elegant ways to get more linear amplification out of fairly simple and low cost devices and this scheme looks very promising.
Nice job, you explained it pretty well, but I think if drew the ckt using the Hybrid-pi model and did the pertinent loop equations it might help some of the younger players to really get a better insight on what is really going on here. Just a thought, again excellent job and thanks for sharing.
Please also explain how the single stage amplifier using transistor at the output of chips like Um66 or Um3561 used for amplification functions & also how we can design such circuit if we need to increase the output power (calculate the watts) of those Siren type circuits in some another video
I was wondering, (although i guess it will be explained in the next video) ... but I noticed that in many circuits that use the the Sziklai pair, there is also often a resistor between Q2's base and emitter. Is that for the same reason as in the Darlington pair?
I have to get from 5V signal a Electric motor working this Electric motor needs ~12V and 1A .. i have to use BD676/5 Darlington-Transistors … can u help me please? i don't know how big is the reinforcement for the Transistors how can i find that our without to measure .. from datasheet ?
JohnAudioTech+ Do you have any plans for a 2.1 Class D Amp 50+50+100 amps we could do? and what your favorite brand of capacitors and mosfets if money wasn't a issue? Thanks.
Do you mean testing a class D board or building an amp from scratch? I don't have any favorite brands. Whatever works and is of good quality is good enough for me.
hi, can you please explain to me why there is no resistor connected between the emitter of the first transistor and ground. what will be the implication of connecting one? will have an effect on the gain achieved? thanks
If the device providing the signal to the base can't sink current well to pull stored charge out of the transistor, it will slow it down. Adding a resistor in that case can speed it up at the cost of lower input impedance.
Thanks for the quick response. myself and a few colleagues are trying to build an FM transmitter just for demonstration purposes. one of us thought by using a Darlington pair we will bust up the power to the antenna. one of the key requirements is to put that resistor on emitter the first transistor to ground and also use the same transistor with the same hfe. Do you think this is the correct line of thinking? Thanks.
HELLO THERE . THERES A TIP142 NPN TRANSISTOR IM TRYING TO USE IN MY ONE TRANSISTOR SOUND AMP . SO TELL ME WHERE IS THE EXIT IS IT AN EMITTER OR COLLECTOR ???
Exactly. Darlington configuration does that because the collectors are connected together. Instead, two separate transistors with the collectors separate should be used. Then the second can fully saturate and not waste so much power.
Dear John is there any instrument you have to measure a signal 10 mV with 1% accuracy?10 mV +/- 2% x 5000= 4900 to 5100. So practically 5100 gain and 5000 are not distinguishable .Giving the fact that gain of transistors are among many E current , CE voltage and temperature dependent so you need to add many more error factors too.The result becomes so uncertain that when you drawn yourself in theory of physics you may loose the point.
3:38 The current that is near the collector of Q2 is 505mA and the emitted current by the Q1 is 10.1, so shouldn't the emitted current by Q2 be 10.1+505=515.1?
@@TheJokerandTheJean The Beta formula is correct. The gain in the example is 5150. The emitter current is 515.1 ma because it is inclusive of the .1 ma base current going into Q1. Beta is calculated using the collector current, not the emitter current.
At last, find the perfect explaination about darlington transistor. Keep up the good work!!
Excellent video! I look forward to more on this topic in Part 2.
Excellent explanation. I wish all electronics videos were this good.
Interesting analysis of characteristics I was not aware of. Great explanation. THANX. Another reason to use Mosfets for power drivers.
Nice video sir... Enjoyed the basics a lot... Looking for your 2nd part
"Thank You", thank you very much. I thought your presentation was VERY goog. I look forward to hearing more from you
Excellent follow-up, looking forward to part two.
Love your vids man keep up the good work 🌞
Thanks for the informative follow-up
Thank you so much, a fantastic very lucid video.
Nice work John.
Geez, I like long videos... Seriously thanks for the topic because I have been meaning to experiment with the scheme. Sooner or later I'll grab some screen shots of your experimental circuit and have a go with the concept. I am always looking for elegant ways to get more linear amplification out of fairly simple and low cost devices and this scheme looks very promising.
"Tanks" for the transistor tutorial, will apply this knowledge.
Great video , keep it up.
That was really well explained. Can you do a detailed tutorial on how various components or IC work, like 555 timer, voltage regulator, flip flops etc
i love you chanel!
Nice job, you explained it pretty well, but I think if drew the ckt using the Hybrid-pi model and did the pertinent loop equations it might help some of the younger players to really get a better insight on what is really going on here. Just a thought, again excellent job and thanks for sharing.
Good video brother ❤️ love from Bharat 🇮🇳
Looking forward to part 2
nice to see I'm not the only geek with an old radio shack electronics kit
no mate :)
Please also explain how the single stage amplifier using transistor at the output of chips like Um66 or Um3561 used for amplification functions & also how we can design such circuit if we need to increase the output power (calculate the watts) of those Siren type circuits in some another video
I was wondering, (although i guess it will be explained in the next video) ... but I noticed that in many circuits that use the the Sziklai pair, there is also often a resistor between Q2's base and emitter. Is that for the same reason as in the Darlington pair?
Yes
@@JohnAudioTech excellent presentation, crystal clear English and no music.Simply great
Nice video, I could grasp most of it. How would you rate the uni-t clamp meter by the way?
I am very happy with the clamp meter.
Really nice tutorial. Is it possible to use a simple circuit like that to amplify a guitar sinal enough to headphone level?
Go to redcircuits.com to find audio amps for guitars, headphones.
I have to get from 5V signal a Electric motor working this Electric motor needs ~12V and 1A .. i have to use BD676/5 Darlington-Transistors … can u help me please? i don't know how big is the reinforcement for the Transistors how can i find that our without to measure .. from datasheet ?
JohnAudioTech+ Do you have any plans for a 2.1 Class D Amp 50+50+100 amps we could do? and what your favorite brand of capacitors and mosfets if money wasn't a issue? Thanks.
Do you mean testing a class D board or building an amp from scratch? I don't have any favorite brands. Whatever works and is of good quality is good enough for me.
Maybe test a off the shelf first then build a better one...
Is darlington configuration always NPN + NPN or NPN + PNP transistor? How about PNP + PNP?
That thumbnail is fun :D
thanks for explaination!
i have 2 in a old amp and thought they were just 2 transistors in each one but there is 4, its says its a power pack lol.
how can i buy that breadboard
Спасибо)
Great !
Wow, I had no idea you can't saturate a darlingtons main pass transistor!
Good thanks
When we fixed stereo amps theese circuits required matching xistors .the units with output i.c. s were more reliable.and easier to repair...
hi, can you please explain to me why there is no resistor connected between the emitter of the first transistor and ground. what will be the implication of connecting one? will have an effect on the gain achieved? thanks
If the device providing the signal to the base can't sink current well to pull stored charge out of the transistor, it will slow it down. Adding a resistor in that case can speed it up at the cost of lower input impedance.
Thanks for the quick response. myself and a few colleagues are trying to build an FM transmitter just for demonstration purposes. one of us thought by using a Darlington pair we will bust up the power to the antenna. one of the key requirements is to put that resistor on emitter the first transistor to ground and also use the same transistor with the same hfe. Do you think this is the correct line of thinking? Thanks.
HELLO THERE . THERES A TIP142 NPN TRANSISTOR IM TRYING TO USE IN MY ONE TRANSISTOR SOUND AMP . SO TELL ME WHERE IS THE EXIT IS IT AN EMITTER OR COLLECTOR ???
13.11 - "Am I gonna watch this??" 🤣🤣🤣🤣🤣
The bit about not being able to saturate explains the poor performance of an inverter circuit I made long ago...
Exactly. Darlington configuration does that because the collectors are connected together. Instead, two separate transistors with the collectors separate should be used. Then the second can fully saturate and not waste so much power.
13:08 - I didn't sound anything like you when I said that! I said it in a much more pleasant tone.
Dear John is there any instrument you have to measure a signal 10 mV with 1% accuracy?10 mV +/- 2% x 5000= 4900 to 5100. So practically 5100 gain and 5000 are not distinguishable .Giving the fact that gain of transistors are among many E current , CE voltage and temperature dependent so you need to add many more error factors too.The result becomes so uncertain that when you drawn yourself in theory of physics you may loose the point.
3:38 The current that is near the collector of Q2 is 505mA and the emitted current by the Q1 is 10.1, so shouldn't the emitted current by Q2 be 10.1+505=515.1?
yes
@@JohnAudioTechthankyou!
but you cross checked with the Btot formula....than is that formula wrong?
@@TheJokerandTheJean The Beta formula is correct. The gain in the example is 5150. The emitter current is 515.1 ma because it is inclusive of the .1 ma base current going into Q1. Beta is calculated using the collector current, not the emitter current.
@@JohnAudioTech okay thankyou very much sir!