Linearity and nonlinear theories. Schrödinger's equation

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  • čas přidán 4. 07. 2017
  • MIT 8.04 Quantum Physics I, Spring 2016
    View the complete course: ocw.mit.edu/8-04S16
    Instructor: Barton Zwiebach
    License: Creative Commons BY-NC-SA
    More information at ocw.mit.edu/terms
    More courses at ocw.mit.edu

Komentáře • 195

  • @StaffordGreen
    @StaffordGreen Před 7 lety +157

    I appreciate these lectures being online.

  • @mrsulaman9901
    @mrsulaman9901 Před 5 měsíci +7

    I would like to compliment the camera man for his fine work. Also whoever is responsible for recording the sound did a great job. It's so important to be able to hear and see these lectures clearly. My thanks also to MIT for making this content available.

  • @stephenanastasi748
    @stephenanastasi748 Před 3 lety +21

    I love this form of explanation. It is so complete. And I love that the facts and reasoning are explained in a human-centric simple form, where so many others throw a bunch of fact at the screen. Thank you! I will use this information in the most powerful way. I have tried to wrap my head around the supposedly simple idea of linearity for a long time. Somehow this shifted me over my preconceptions.

  • @mjackstewart
    @mjackstewart Před 3 lety +21

    There are some people who are perfect communicators of complex subjects.
    My calculus teacher, Martha Kasting, was one such person. She would smile the entire time as she described Green’s Theorem, or she would say, “Isn’t that a pretty equation?”
    Dr. Zwiebach is another.

  • @SanDiego_J
    @SanDiego_J Před 6 lety +35

    Thank you MIT OCW and all MIT staff!

  • @cidorodrigues6087
    @cidorodrigues6087 Před 4 lety +9

    I'm Sido Rodrigues Brazil I really like Quantum Physics Classes. Very important to know quantum physics. Teach everything the universe knows and you gain self-knowledge about everything. Great series of really useful lectures on quantum mechanics. I am also very grateful to MIT OpenCourseWare and Barton Zwiebach... etc...

  • @chrisl3987
    @chrisl3987 Před 4 lety +53

    As someone who works in (classical) fluid mechanics, I can confirm that it's very very nonlinear.

    • @chuuuu1131
      @chuuuu1131 Před 4 lety

      Can you give an example?

    • @frun
      @frun Před 4 lety

      Does it look like electromagnetism? I think he meant classical mechanics.

    • @LifeForAiur
      @LifeForAiur Před 4 lety +3

      @@chuuuu1131 Not him, but in fluid mechanics, to quantify the deformation of a fluid particle in a continuous medium you need something called a stress tensor, which is a 3 by 3 matrix describing the direction of the stress imposed and on which "face" of the fluid particle it is acting on. Check out the Navier Stokes Equation expanded out.

    • @MrMathjordan
      @MrMathjordan Před 4 lety

      Agreed.

    • @user-fb4zo8wd5n
      @user-fb4zo8wd5n Před 3 lety +1

      True. Many applied mathematicians research in the field of fluid mechanics.

  • @axis_8
    @axis_8 Před 6 měsíci +1

    I feel illuminated. A clear and concise lecture by a lecturer who comes across having an authentic passion for learning and understanding. Thank you 🙏

  • @homerodaniel_007
    @homerodaniel_007 Před rokem +4

    This is actually an excellent class. It worth's its length in Gold. Thank you very much

  • @mohammednour1534
    @mohammednour1534 Před 7 lety +1

    MUCH THANKS MIT

  • @anywallsocket
    @anywallsocket Před 2 lety +11

    First time I’ve ever heard the process of QM explained outright, every professor I’ve ever had on the subject just jumps right in and it’s hard to grip without foundational information.

  • @TheFenny
    @TheFenny Před 4 lety +25

    Nearly 200,000 views on the first video, and the second video only has a quarter of that? Shame so many people gave up already

    • @HighestRank
      @HighestRank Před 4 lety +2

      Brandon Smith maybe it was just a review which they needed, I myself got this only as a recommendation even though I’m not a subscriber to OCW, and wouldn’t have expected anyone who didn’t realize there is a second part because they weren’t told in the video to go looking for it or to recognize it if it had bit them in the nose.

    • @MegaFunkysoul
      @MegaFunkysoul Před 3 lety

      They were looking for pseudoscience

    • @abrarfaiyaz6503
      @abrarfaiyaz6503 Před 3 lety

      Maybe they moved on to the ocw site.

  • @prabudeva2547
    @prabudeva2547 Před 4 měsíci

    I'm from India.... great thank you mit gives the online courses...little tweak are arises...but most of the phenomenal are not predicted..which means my life time scenario is the one of the examples...some atoms are vibrated...but no losses. After some times the illusion are visible... 🤔

  • @nikhilgoyal7814
    @nikhilgoyal7814 Před 4 lety +4

    This professor is amazing.. Though my stream is not linked with this subject but then also i have seen the whole video :)

  • @fujiexia2515
    @fujiexia2515 Před 3 lety +2

    Very excellent open course on QM, thanks MIT professor!

  • @yordygarciamalca3487
    @yordygarciamalca3487 Před 4 lety +1

    Thank you so much!

  • @ramonasosna
    @ramonasosna Před 7 měsíci

    Great teaching ❤

  • @MikeDbean420
    @MikeDbean420 Před 4 lety +10

    Thank you. Great teacher. Easy to follow.

    • @Anb-ng2ou
      @Anb-ng2ou Před 4 lety

      How is called this teacher pelase?

    • @ZapytajRedditPolska
      @ZapytajRedditPolska Před rokem

      @@Anb-ng2ou what are you doing here if you have problems with reading description?

    • @nichokind5233
      @nichokind5233 Před 2 měsíci

      @@Anb-ng2ou Dr. Barton Zwiebach

  • @khaledal-homam6482
    @khaledal-homam6482 Před 4 lety +1

    You are great.

  • @karthigamanivannan7922
    @karthigamanivannan7922 Před 3 lety +2

    thank you MIT AND ALL FACULTIES FOR PROVIDING INTERESTING LECTURES ON QUANTUM MECHANICS...

  • @antoniolewis1016
    @antoniolewis1016 Před 7 lety +5

    @MITOCW Is this the same room where they did the old 2013 QM course, but renovated??

    • @mitocw
      @mitocw  Před 7 lety +10

      Good eyes! Yes, this is the same room where they did the 2013 version of the course. :)

  • @deepakkumarravi9217
    @deepakkumarravi9217 Před 4 lety

    Thnx to mit n your staff to spread your valuable contribution in enhancing the concept in worldwide.. Respect n love to you all guys.....

  • @java_Marcelo-xx5nw
    @java_Marcelo-xx5nw Před měsícem

    Thank you for share!

  • @beenishmuazzam
    @beenishmuazzam Před 4 lety +1

    Thanks

  • @retepredlef5212
    @retepredlef5212 Před měsícem

    Phantastic lecture!

    • @lepidoptera9337
      @lepidoptera9337 Před 4 dny

      Not really. I am beginning to wonder how this guy made professor at MIT. ;-)

  • @abdulbaqui9499
    @abdulbaqui9499 Před 3 lety

    Good lecture

  • @emersonfranzuaaldanagavarr231

    thank you

  • @geoffrygifari3377
    @geoffrygifari3377 Před 2 lety +1

    If schrodinger's equation is linear in any case by default, is it not possible to observe nonlinear behavior in quantum system?

  • @arushaacharyya6376
    @arushaacharyya6376 Před 3 lety +2

    Where and how does the non-linearity get introduced in classical mechanics when quantum mechanics is all linear?

  • @Mystic0Dreamer
    @Mystic0Dreamer Před 3 lety

    @ 9:30 he talks about Schrodinger not knowing what the wave function is. How did Schrodinger come up with this equation in the first place. Professor Zwiebach doesn't offer an explanation of how Schrodinger came up with this equation. But Schrodinger must have had reasons.

  • @i.m.Q.2
    @i.m.Q.2 Před rokem

    Thanks for confirming something I've been wonderimg about for some time now! You've got no idea what you just helped me out with. 👍😁

  • @tarunpurohit6522
    @tarunpurohit6522 Před 2 lety

    What a great intro

  • @gustavodeoliveira702
    @gustavodeoliveira702 Před 2 lety

    In what extent can someone assert that classical mechanics or quantum mechanics is linear or not? Is in regarding to the description of fundamental interactions and not merely idealized models?
    Because a classical harmonic oscillator is a linear system inside classical mechanics and systems that respect Ginzburg-Landau equation are non linear examples in quantum mechanics. Why those aren't consider counter-examples to the thesis defended in the video?

  • @AlexBlade27
    @AlexBlade27 Před rokem +1

    I have a question, isn't Hamiltonian operator also a non linear operator, because it also contains Potential term which may be quadratic or cubic depending on the condition. Thus, isn't then Quantum mechanics also, non linear in nature. Please, explain if I am wrong.

    • @sylvenara
      @sylvenara Před rokem +3

      While the potential energy term in the Hamiltonian operator of quantum mechanics can be nonlinear, the dynamics of quantum mechanics are fundamentally described by a linear equation, the Schrödinger equation. Therefore, quantum mechanics is considered a linear theory.

    • @AlexBlade27
      @AlexBlade27 Před rokem +1

      @@sylvenara ok understood. Thanks for the help😊

  • @debanujchatterjee2768
    @debanujchatterjee2768 Před 4 lety

    The Hamiltonian operator may contain a potential term. So how is the Hamiltonian always linear?

  • @FreezerBurn.
    @FreezerBurn. Před 4 lety +9

    I think I am going to treat myself to hotdogs in my mac and cheese tonight.

    • @spencersabet8601
      @spencersabet8601 Před 3 lety +1

      I respect that. Have fun

    • @ProgressiveTeen
      @ProgressiveTeen Před 2 lety

      How evil. Torturing animals for your tongue's evil delight.

    • @FreezerBurn.
      @FreezerBurn. Před 2 lety

      @@ProgressiveTeen ... kind Sir, sadly you are mistaken. Mac and Cheese is not an animal.

  • @ahmedafifkhan
    @ahmedafifkhan Před 4 lety

    Can anyone elaborate a bit from @2:20 to @2:33. What did he mean? Where did that graph came from?

    • @NoName-vq6cg
      @NoName-vq6cg Před 4 lety

      Graph of potential energy over time. (Potential energy meaning the work that force has to do. Force × distance) The derivative is the force acting on it at a specific time. Like if a ball is rolling down a hill, hes basically just saying that because there's mass, gravity would be pulling it down, and it loses potential energy as it gets closer to its destination and force is used. So the force is the negative of the derivative of potential energy.(someone correct me if I'm wrong)

  • @sagarwadhwani1610
    @sagarwadhwani1610 Před 4 lety

    Can't we use linear qm to solve 3 body problem

  • @123string4
    @123string4 Před 2 lety +2

    Why is the Schrodinger equation linear when the Hamiltonian depends on V(x), and earlier he said that V(x) can be arbitrary? The quantum harmonic oscillator is a perfect example of a nonlinear potential and as far as I know you need special techniques like Hermite polynomials to solve it.

    • @commonlistener87
      @commonlistener87 Před 7 dny

      Linearity depends on the dynamical variable you’re solving for.
      In the example the lecturer presents for Newton’s equations, you are solving a second-order differential equation for the “variable” x (which is a function of time). The equation is nonlinear *with respect to x* whenever V’(x) is nonlinear with respect to x.
      In the case of Schrödinger’s equation, by contrast, you are solving a partial differential equation for psi (the wavefunction), not for x. You’re right that the Hamiltonian has a potential term V that depends on x (often nonlinearly), but V doesn’t depend on psi, and it’s psi that you’re solving for.

  • @geoffrygifari3377
    @geoffrygifari3377 Před 2 lety +1

    hmmm i guess quantum mechanics is linear because the potential operator is applied ("multiplied") to the wavefunction, instead of the potential being an arbitrary function *of* the wavefunction, as in classical mechanics

  • @eternapesadilla2355
    @eternapesadilla2355 Před 4 lety

    Arent you the dean of the university of architecture in copenhagen?

  • @pranjalsharma3370
    @pranjalsharma3370 Před 3 lety

    Amazing👍
    Can anyone say whether these are graduation or postgraduation classes? Or anything else?

  • @SarojKumar-lt8qy
    @SarojKumar-lt8qy Před 6 lety +2

    Sir can a wavefuntion determine the dynamics of a macrobody?????or it is just applicable in cases of microbodies

    • @farooq8897
      @farooq8897 Před 6 lety +2

      It can.. But Classical Mechanics is a good approximation and easy to use..

  • @kaushaljain5999
    @kaushaljain5999 Před 4 lety

    4:39 Is time is dynamical variable? what is definition of dynamical variable?

    • @friendlyone2706
      @friendlyone2706 Před 3 lety

      @@damariscalleros4631 but time changes, sometimes

  • @kaushaljain5999
    @kaushaljain5999 Před 4 lety +1

    5:13 how is Hamiltonian operator linear? Since it also contains potential energy term which need not to be linear.

    • @zacharythatcher7328
      @zacharythatcher7328 Před 4 lety +7

      Kaushal Jain the potential in the Hamiltonian can be thought of as a set of values that span relevant space (a normal line or surface over space) that the wave function will be multiplied by at every single one of those points individually. So the wave equation (the input) will be transformed in essentially a multiplication style operation. Multiplication is linear, and so is the “potential operator”. If the potential was somehow squaring or logging the wave equation, that would be nonlinear, but that is impossible. The potential isn’t that weird. It just multiplies the wave equation by its own predetermined values, which you could do before or after multiplying by a constant and get the same result.

    • @aryasingh8173
      @aryasingh8173 Před 3 lety

      @@zacharythatcher7328 wow

  • @kaushaljain5999
    @kaushaljain5999 Před 4 lety

    9:22. Why is one wave function unable to explain both spin up and down state of e-?

  • @nsudhir_here
    @nsudhir_here Před 4 lety +1

    Can someone explain what is potential V of x? I'm noob in quantum physics. Does it mean a kind of potential which is providing force?

    • @bencegabor9228
      @bencegabor9228 Před 3 lety +2

      Potential V(x) is a classical quantity, whose negative derivative is force. For example: en.wikipedia.org/wiki/Gravitational_potential or en.wikipedia.org/wiki/Electric_potential#Electric_potential_due_to_a_point_charge

    • @nsudhir_here
      @nsudhir_here Před 3 lety +2

      @@bencegabor9228 thank you sir

  • @FredBakker
    @FredBakker Před 4 lety +2

    Mister Zwiebag, you absolutely rock! Explaining complex stuff simple is a trait of true genius!

  • @farahsalam1887
    @farahsalam1887 Před 4 lety +3

    thanks sir for this amazing lectures
    but can any one give me the notes of the course please?

    • @mitocw
      @mitocw  Před 4 lety +13

      The lecture notes are available on MIT OpenCourseWare at: ttp://ocw.mit.edu/8-04S16. Best wishes on your studies!

    • @abubakarejaz5539
      @abubakarejaz5539 Před 3 lety

      Hey U a physics student too?

  • @user-fc3wx7bp4i
    @user-fc3wx7bp4i Před 5 lety

    Good

  • @pmcate2
    @pmcate2 Před 3 lety

    Aren't maxwell's equations only linear for some materials?

  • @gamalf123
    @gamalf123 Před 6 lety +4

    Why can we assume the Hamiltonian is a linear operator? Isn't it another measure of potential, and theoretically could be made some non-linear result?

    • @LusidDreaming
      @LusidDreaming Před 4 lety +2

      I don't know enough about the Hamiltonian to directly answer this, but in general an operator is linear if it satisfies the following two conditions (O is an operator):
      1.) O(f + g) = O(f) + O(g)
      2.) O(c*f) = c*O(f)

    • @frun
      @frun Před 4 lety

      @@LusidDreaming yes. I think that's the definition.

    • @fredrikj8491
      @fredrikj8491 Před 4 lety +5

      The difference is previously your solution was in terms of x(t) and the potential depends explicitly on x. Now your solution is in terms of the wave function, of which the potential is not a function. The Hamiltonian is a linear operator on the space where the wave function lives. The potential is not a function of your wave function.

    • @ericsmith1801
      @ericsmith1801 Před 4 lety +1

      @@LusidDreaming So there cannot be time compression to satisfy linearity... experiments seem to suggest that in addition to spatial nonlocality there is temporal nonlocality involved in entanglement. I doubt that changing the inertial frame of reference will get rid of such nonlinearity.

  • @infinity-and-regards
    @infinity-and-regards Před 4 lety +2

    9:35 How did Schrodinger come up with his equation before there was any physical interpretation for the wave function? What did he try to derive? What was his starting point?

    • @durgeshgaikwad741
      @durgeshgaikwad741 Před 4 lety +3

      When de Broglie proposed the idea of matter waves, Schrödinger tried to find an equation which could describe these matter waves and hence came up with the famous Schrödinger equation

    • @lambda2693
      @lambda2693 Před 2 lety

      it is quite easy. you just have to prove that what the classical operators become in qm. like p=-ihbar d/dx or E=ihbar del/del t

    • @infinity-and-regards
      @infinity-and-regards Před 2 lety

      @Lambda that doesn't sound easy at all, could you elaborate?

    • @lambda2693
      @lambda2693 Před 2 lety

      @@infinity-and-regards look finding the operators is tough but the derivation of the equation is very easy if you know the operators. okay look i will derive it for you but i will assume the operators if you want the proof for why the operators are equal to what i am assuming you will have to look it up as the proof is very long.
      E=KINETIC ENERGY + POTENTIAL ENERGY
      KE= P^2/2M. PE=V(X,)
      LET US QUANTIZE THIS
      EΨ=P^2/2M Ψ +VΨ
      NOW EΨ=Ih/2π dΨ/dt. and p=-ih/2πd/dx
      Ih/2π dΨ/dt=(-ih/2πd/dx)^2/2m Ψ+VΨ
      Ih(ΒΑR)dΨ/dt=-h(BAR)^2/2m d^Ψ/dx^2+VΨ
      AND YOU HAVE DERIVED THE SE. YOU CAN DERIVE ITIN OTHER FORMS BUT THE PROCESS IS SAME. THE REAL CHALLENGE COMES IN PROVING THE ASSUMPTIONS AND YOU TO USE BRA'S AND KET'S FOR THAT. ALTHOUGH THE PROOFS ARE GIVEN IN SOME TEXTBOOKS BUT ARE VERY COMPLEX. EVEN GRIFFITHS DOES NOT GIVE THE PROOF

  • @rezokobaidze8501
    @rezokobaidze8501 Před 3 lety +1

    hamiltonian has potential energy inside and why it is linear?

    • @AbhishekSachans
      @AbhishekSachans Před 2 lety +1

      Because potential energy is not a function of the 'wave function'- the independent variable in schrodinger's wave equation (or its derivatives); unlike in Newton's equation of motion in which P.E. WAS a function the independent variable(s) e.g. x in general.

  • @kostasargiris748
    @kostasargiris748 Před rokem

    Very good teacher!! I have a question : 3:34 Why x squared is not a linear function?

    • @mateusmarinho72
      @mateusmarinho72 Před rokem +2

      f(x) = x²
      f(a + b) = a² + 2ab + b²
      f (a) + f (b) = a² + b²
      So f(a+b) is not equal to f(a) + f(b), therefore it's not additive. So it's not linear.

    • @kostasargiris748
      @kostasargiris748 Před rokem +1

      @@mateusmarinho72 yes, okey, thank you very much!

    • @urpisarmiento5385
      @urpisarmiento5385 Před 2 měsíci

      ​@@mateusmarinho72muchas gracias, entendí la explicación.

  • @nayemabdullah7627
    @nayemabdullah7627 Před 3 lety

    I am from Bangladesh
    Love Quantum mechanic

  • @cedriccappelle2036
    @cedriccappelle2036 Před 4 lety +1

    For some reason I keep watching this guy even though I don't understand ßhit of this

  • @ejoe7938
    @ejoe7938 Před 6 lety

    Where is the teacher from?

    • @carloveable1
      @carloveable1 Před 4 lety +3

      He studied at my University in Peru (well known in Peru as UNI) at the same Faculty than me and he finished (Electrical Engineer career) I believe in 1977, then he came to America to follow Master and PhD. degrees.

  • @hadlevick
    @hadlevick Před 5 lety

    Can you catch the sensation of simultaneity, can you do 1+1...

  • @hadlevick
    @hadlevick Před 5 lety

    Hamilton?

  • @ZEROCARTOO
    @ZEROCARTOO Před 2 lety

    I didnt know i had spedup the videos (to 1.5x) until I read the comments. Oh man, he speaks too slow to the point that his class could be boring. Thankfully it is an online course where you can set the speed, and also for some people that are not familiar with the language and might want to slow it down ;) Greetings from Peru

  • @hadlevick
    @hadlevick Před 5 lety

    (Reproduction/Feed/Reasoning) decanted selfover hexagon...

  • @ryogakaydc7017
    @ryogakaydc7017 Před 4 lety +1

    Ojala algun dia regrese Barton a la Fiee para para una clase de estado solido 🙌

  • @surendrakverma555
    @surendrakverma555 Před 2 lety

    Excellent lecture Sir. Thanks 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

  • @riturajanand7133
    @riturajanand7133 Před 4 lety

    sir how force is equal to the derivative of potential...Sir as I know the force is equal to -du/dx (rate of change of potential ENERGY W.R.T X) not potential.....

    • @mysteriouspandey3450
      @mysteriouspandey3450 Před 4 lety

      Pehle basics clear karo Bhai baadme quantum ki lectures samjhoge

    • @riturajanand7133
      @riturajanand7133 Před 4 lety

      @@mysteriouspandey3450 Thanks sir for your advice, please answer to bta dete doubt ka

  • @kaushaljain5999
    @kaushaljain5999 Před 4 lety

    Explain 0:56 to 1:05 by example

  • @forheuristiclifeksh7836
    @forheuristiclifeksh7836 Před 5 měsíci

    Dynamic quantum variable, wave function

  • @kaushaljain5999
    @kaushaljain5999 Před 4 lety

    explain 0:53 to 1:07 by example

  • @abhijeetbhattacharjee6185

    3:31 What is V(x) ?

  • @brandomiranda6703
    @brandomiranda6703 Před 3 lety

    Why is 2nd law for newton not linear wrt Potential? Partial derivatives are linear and so are the normal derivatives...

    • @AbhishekSachans
      @AbhishekSachans Před 2 lety

      Because, say for one dimension, x is an independent variable of which potential energy is generally a function so that gives you a non-linear differential equation. That's it!

  • @hassanbaqer9280
    @hassanbaqer9280 Před 6 lety +1

    👍👍👍👍👍👍👌👌👌👌

  • @SarojKumar-lt8qy
    @SarojKumar-lt8qy Před 6 lety

    Sir . I wanted to ask .............we know that a theory has numerous equations in it working all together to state one point .Now if we say that a theory is linear then does it state all the equations of that theory to be linear or there is a possibility for only a few to be linear ???????

    • @friendlyone2706
      @friendlyone2706 Před 3 lety

      The moment a non linear factor is introduced, everything affected by that nonlinear factor becomes nonlinear.

  • @CharlesSmith-vk8co
    @CharlesSmith-vk8co Před 4 lety +1

    You can aquire all thie knowledge for free.You may even sit down in the lecture und visit all classes and pass the exam.But if you want that piece of paper which says that you did all of that you have to pay thousands of dollars.

  • @suteguma0
    @suteguma0 Před 4 lety +1

    Can anyone help me understand what the T-like symbol really means in the derivative equation?

  • @mattmurdock2259
    @mattmurdock2259 Před 4 lety +3

    free knowledge hooray

    • @Adam-cn5ib
      @Adam-cn5ib Před 4 lety

      why pay when you can not pay? right?

  • @leonidasloquendero
    @leonidasloquendero Před 2 lety +1

    Orgullo peruano

  • @forheuristiclifeksh7836
    @forheuristiclifeksh7836 Před 5 měsíci

    3:49

  • @chandrusekar9575
    @chandrusekar9575 Před 4 lety

    Hi

  • @hadlevick
    @hadlevick Před 5 lety

    The size of simultaneity...

  • @RonPaulOrDie
    @RonPaulOrDie Před 5 lety

    Whatever it is it's non-linear, and it is the easier explanation. Maybe he says this later Im 30 seconds in.

  • @p0lv0jack_
    @p0lv0jack_ Před 2 lety

    👁️

  • @LRahmanGrandUnifiedModelLRahma

    L. Rahman Grand Unified Model

  • @dougiev9287
    @dougiev9287 Před 4 lety

    Newton's is non-linear because potential could be non-linear function; ok! But Maxwell's is linear...couldn't potentials A and V be non-linear?

    • @HighestRank
      @HighestRank Před 4 lety

      dougie v yes, Aa is easy to see, but Vv will always be made using straight lines.

  • @wassupari2294
    @wassupari2294 Před měsícem +4

    benedict cumberbatch in disguise

  • @timetostudy6443
    @timetostudy6443 Před 3 lety

    Yes professor, I found the tutorial irrelevant since I’m no where near being a physician.

  • @timmy18135
    @timmy18135 Před 4 lety +1

    It is linear iff a linear relationship exists

  • @MS_PrithwirajMaity
    @MS_PrithwirajMaity Před 2 lety

    CLASSICAL MECHANICS IS NONLINEAR AND QUANTUM MECHANICS IS LINEAR THEN HOW CLASSICAL MECHANICS IS APPROXIMATON OF QUANTUM MECHANICS.

  • @posthocprior
    @posthocprior Před rokem

    Somewhat vague definition of the difference between linear and non linear.

  • @achintyajai2934
    @achintyajai2934 Před 2 lety

    alright he reminds me of dr. peyam

  • @sharptongue2972
    @sharptongue2972 Před 4 lety

    Han Solo is now a physicist? Damn...

  • @mohammadaminmasoomi3597

    I'm from Iran.I love quantum physics and the other parts of physics and absolutely I go to the MIT university.

  • @czitels1856
    @czitels1856 Před 2 lety

    Interesting thing. First video has 2x more views than second :D

  • @diegofernando4277
    @diegofernando4277 Před 5 lety +3

    I don't get it, he says that classical mechanics ain't linear because of the potential energy, but the Hamiltonian it's the sum of the kinetic and potential energy, so, how can the classical mechanics be non linear, but the wave function that also depends of V(x, t) be linear?

    • @ogoshi
      @ogoshi Před 5 lety

      Yeah, I'm also a little confused by this argument

    • @andrewstallard6927
      @andrewstallard6927 Před 5 lety +2

      Notice in the classical equation, m x'''(t)=-V(x'(t)), the potential is a function of the derivative of the position. While the derivative itself is linear, we don't know what the unknown potential function "V" is so we can not say with certainty that V(x'(k*t))=k*V(x'(t)). By contrast, in the Schrodinger equation the potential V is multiplied by the wavefunction psi, so V*k*psi=k*V*psi

    • @UnknownBeast41
      @UnknownBeast41 Před 5 lety

      The potential function is arbitrary, in most scenarios we approximate it to be harmonic (proportional to x^2) but it can be generally non linear. Alternatively H-hat is the Hamiltonian operator which is basically a constant time the 2nd derivative with respect to position i.e its linear. Its not the Hamiltonian itself, its an operator named after the Hamiltonian.

    • @mike4ty4
      @mike4ty4 Před 4 lety

      The quantum Hamiltonian operator acts on the state variable differently than the potential/kinetic energy (classical Hamiltonian) does in Newtonian mechanics. In particular, "x" in the potential energy function is just a parameter, not the present particle state being plugged into the function like it is in the Newtonian case with Newton's second law or Hamilton's equations, because in quantum mechanics position, momentum, etc. are not actually numbers, but "fuzzy" quantities described by probability distributions (which corresponds to reduced information, as per Shannon), and they are all wrapped up in the linear state vector, |psi>. That state vector is not a real number, but (effectively) an infinite number of them, and hence could not be inserted into the potential energy function anyways, which is expecting only one real number as input.
      Instead, the potential energy function _becomes_ an operator on the state vector by first considering it in the form of the positional wave function psi_x(x), which is a "basis expansion" (effectively the same thing as vector components of ordinary vectors, but with infinitely many components) and then you multiply this wave function by the potential energy function to get another wave function (i.e. form psi'_x(x) = U(x) psi_x(x)), which then represents, by going backwards through that expansion, the resulting new state vector. Since multiplication is distributive, hence linear, you get a linear action of this operator.

  • @uTubeNoITube
    @uTubeNoITube Před 2 lety

    You don't need any of this. Just go to Vegas on weekends and play black jack.

  • @ryanyi8900
    @ryanyi8900 Před 5 lety +1

    I have some doubt about the view that professor mentioned in the lecture about the relation between the many body equation solving difficulty and the linearity of equation.And I think the linearity of shrodinger equation provide us a possible way to solve the superposition problem, which is a one body problem! So, I do not agree the view that the nonlinearity of Newton mechanic equation make three body problem hard to solve.I have not tried to solve many body problem by shrodinger equation or newton mechanic equation, so my point might be wrong.I hope somebody could help me to figure this out.Thank you:)!

  • @smartscience5305
    @smartscience5305 Před 3 lety +2

    Wow , great lesson Sir. I am 12 years old and I am learning quantum gravity,string theory , Electromagnetism, thermodynamics and other lessons . but your lesson was great also the another lesson of relativity

    • @lamaquinadelainformacion826
      @lamaquinadelainformacion826 Před rokem +1

      At your age I was learning basic astronomy, you know where I ended up, studying geological engineering, I'm in my first cycle, I like physics although it's a bit difficult to understand, but what I don't understand much is chemistry, I'm from Peru.

  • @abcdef2069
    @abcdef2069 Před 4 měsíci

    QM(quantum mechanics) is linear? where is the laws of physics that says it is, we dont truly know if QM is linear, but the probability representation of psi or ANYTHING is ALWAYS linear, because we MADE it linear so that it could be solvable, this is the ONLY way we could even TRY to solve for the slightest bit. "it is linear" and "we MADE it linear" are two different things.
    the initial value problems of non-linear classical mech is the SAME as the boundary problems of linear probability representation in quantum mechanics.

    • @lepidoptera9337
      @lepidoptera9337 Před 4 dny

      It is linear because the quantum mechanical ensemble consists of statistically independent experiments. That's an assumption. Since we do not have an actual ensemble in real life but only the repetition of the same experiment, the statistical independence of the data set that it produces has to be tested. It will usually work out fine for e.g. the photon flux from a thermal light source, but it will show very strong temporal correlations for a laser source. So you are not completely false in saying that "we made it linear", but the naive assumption that every quantum mechanical system obeys that linearity is incorrect.

  • @ahmedessam1426
    @ahmedessam1426 Před 6 lety +7

    this continuous montages and cuts through the video made my upset because i want to know everything he says like the real lecture :(

  • @schrodingerscat3912
    @schrodingerscat3912 Před 4 lety

    (steepled hands)

  • @justinji431
    @justinji431 Před 4 lety

    2:14 FUNNY