The sum of n , 2n, 3n terms of an A.P are S1, S2, S3 respectively. Prove that S3 = 3 (S2 - S1)

The sum of n , 2n, 3n terms of an A.P are S1, S2, S3 respectively.
Prove that S3 = 3 (S2 - S1)

[@amitmeena0310]

S3 ko open krne pr ye nhi aa rha ?

[@niharmhirani]

Very Simple Amit, S3 = 3n/2 [2a+{3n-1}d] Agar isse simplifi karenge to equal ho jayega Like this 3n/2 [2a+3dn-d] isn't it. D dono ke sath he. Yes I agree with you I should have cleared it in video only. Thanks for pointing out.

[@amitmeena0310]

@@niharmhirani thanks sir I can understand now 😊

[@VISHESH294]

Thanks sir❤❤❤

[@niharmhirani]

Welcome

[@nupurkulkarni3626]

Thank you sir 🙏 bahut acche se samaj me aa gaya .

[@VlogerKanha17]

Thankyou Sir for this excellent explanation❤️

[@PoonamKumari-od7tv]

Thanks sir for explaining it in such an easy way☺️

[@krishnakaran5743]

We can use Sn=n/2 (a+l)???

[@rajeshkumar-mj4yy]

ᴛʜᴀɴᴋꜱ ꜱɪʀ

[@amitmeena0310]

Sir S3 ke equal nhi h vo