Kinematics Of Particles Part I ( Rectilinear Motion ) - Solved University Problems

Sdílet
Vložit
  • čas přidán 22. 10. 2017
  • This EzEd Video explains
    What is Kinematics of Particle
    Rectilinear Motion

Komentáře • 29

  • @abdikhanihussien7251
    @abdikhanihussien7251 Před 3 lety

    Thank you teacher go ahead

  • @mehmetdudu7240
    @mehmetdudu7240 Před 4 lety +5

    You have a calculation error at 8:43
    At the equation 50 = v(3.613) + 0.5(-9.81) x (3.613) x (3.613)
    v comes 31.5 m/s not 23.257

  • @lalamvivek667
    @lalamvivek667 Před 6 lety +1

    Sir in uniform acceleration,change in velocity follows arithmetic or geometric progression or none.please help me

  • @owenfernandez4189
    @owenfernandez4189 Před 3 lety

    how did you solve equations 1 and 2, did you equate them to each other?

  • @mailgopal247
    @mailgopal247 Před 2 lety

    03:02 the equation for 's' is missing square on 't'.

  • @tanmoyghatak6303
    @tanmoyghatak6303 Před 6 lety

    thans for this video

  • @brandonbrown9192
    @brandonbrown9192 Před 5 lety +1

    At 8:45, I think you miscalculated v. I got 31.558 m/s.

  • @Pain-di3hy
    @Pain-di3hy Před 4 lety

    What book u are using for this, please reply because it could help every student who in need.

  • @KhalidKhalid-iv9lf
    @KhalidKhalid-iv9lf Před 6 lety

    How did you solve the equations in 5:35 ?
    Beacuse if you either solve first or secound you'll have two values to t !

    • @EzEdChannel
      @EzEdChannel  Před 6 lety +4

      Equation
      1
      S= ut+1/2 at^2
      And equation 2
      S= ut+1/2 at^2
      So for t equating bot the equation
      ut+1/2 at^2 = ut+1/2 at^2
      You will get T.
      Did that help?

    • @KhalidKhalid-iv9lf
      @KhalidKhalid-iv9lf Před 6 lety

      EzEd Channel yes thx very much sir ❤, same as I did but I did wrong calculation and I got two values of t which are postive or minus 10.54
      that very helpful in my homework ❤

    • @EzEdChannel
      @EzEdChannel  Před 6 lety +1

      You are welcome :). You can find more videos on our Channel for different topics. And do visit our website www.ezed.in for notes and unlimited tests and many more features

  • @prashantgosavi68
    @prashantgosavi68 Před 6 lety

    Nice

    • @EzEdChannel
      @EzEdChannel  Před 6 lety

      Thank You +Prashant Gosavi. Please subscribe to our EZEd Channel for more such videos

  • @boyibella6253
    @boyibella6253 Před 6 lety

    how can u get -16.67 in video time 6.32

  • @RJDJsweden
    @RJDJsweden Před 4 lety +3

    how can the acceleration increase as he jumps out of the plane? it should be constant 9.81

    • @RJDJsweden
      @RJDJsweden Před 4 lety +2

      @@jelodoroni6668 he says the acceleration is increasing as he jumps off the plane. This isn't right.

  • @ajinkya4658
    @ajinkya4658 Před 5 lety +4

    Thank you for this video but voice is lilbit low

    • @EzEdChannel
      @EzEdChannel  Před 5 lety +2

      Hi Ajinkya Jagdale, Thank You for your response. We will look at your concern and inform the backend team. In the meantime please subscribe to our EzEdChannel for more such videos.

  • @jcnotnot8120
    @jcnotnot8120 Před 3 lety +3

    Quieter, please. You're gonna blow our eardrums off.

  • @getmoney-dg5vr
    @getmoney-dg5vr Před 6 lety

    in variable accelration problem i think you have given the wrong value x=8.515m

    • @EzEdChannel
      @EzEdChannel  Před 6 lety

      Hi, Can you tell us what time in the video are you referring to?

    • @glaizamaegaray8262
      @glaizamaegaray8262 Před 3 lety

      @@EzEdChannel 6:45. I think it should be 3.70

    • @fennyclamentina
      @fennyclamentina Před 2 lety

      @@glaizamaegaray8262 no its correct.. you enter log10(v/25) it supposedly log e (v/25)

  • @mwblimited3511
    @mwblimited3511 Před 2 lety +2

    improve audibility

  • @harrisonedwards659
    @harrisonedwards659 Před rokem

    poor